Explanation
C.P. of $$1$$ knife $$=\dfrac{10}{11}$$ S.P of $$1$$ knife $$= \dfrac{11}{10}$$Profit $$=$$ S.P $$-$$ C.PProfit =$$ \dfrac{11}{10} - \dfrac{10}{11} = \dfrac{121 - 100}{110} = \dfrac{21}{110}$$
Profit $$\%$$ $$ = \dfrac{\text {profit}}{\text {C.P.}} \times 100 $$
Profit $$\%$$ $$ = \dfrac{\dfrac{21}{110}}{\dfrac{10}{11}} \times 100$$
$$ \Rightarrow \dfrac{21}{110} \times \dfrac{11}{10} \times 100 = 21$$ $$\%$$
Given that, sita's salary was reduced by 1010 percent,
we have to find order to reach her salary back to the original amount it must be raised.
Let, Sita’s salary $$=100$$
Reduced 1010, then remaining salary $$=100-10$$ of $$100$$
$$=100-\dfrac{100-10}{100}$$
$$=Rs. 90$$
Order to reach her salary back to the original amount it must be raised by $$10$$
$$=\dfrac{10\times 100}{90}$$
$$=\dfrac{100}{9}$$
$$=11\dfrac {1}{9}\%$$
Given that, series is profitable $$25$$%,$$12$$%,$$3$$%, or $$18$$%, $$1.7$$%,$$5$$%.
Now,series $$25$$%,$$12$$%,$$3$$% is profitable in compare to series $$18$$%, $$1.7$$%,$$5$$%.
Because $$25$$ percent is greater than $$18$$ percent
And 12 percent is greater than 1.7 percent
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