MCQ Questions for Class 8 Maths Comparing Quantities Quiz 6

A, B and C enter into a partnership They invest Rs 40000, Rs 80000 and Rs 120000 respectively At the end of the first year B withdraws Rs 40000 while at the end of the second year C withdraws Rs 80000 In what ratio will the profit be shared at the end of 3 years?

0%
2 : 3 : 5
0%
3 : 4 : 7
0%
4 : 5 : 9
0%
None of these

Explanation

$A:B:C=(40000\times 36):(80000\times 12+40000\times 24):(120000\times 24+40000\times 12)$

$\Rightarrow 1440000:1920000:3360000$

$\Rightarrow 144:192:336$

$\Rightarrow 12:16:28$

$\Rightarrow 3:4:7$

A, B and C start a business each investing Rs 20000 After 5 months A withdraw Rs 5000, B withdraw Rs 4000 and C invests Rs 6000 more At the end of the year a total profit of Rs 69900 was recorded Find the share of each

0%
$Rs.\ 20500,Rs.27200,Rs.\ 22200$
0%
$Rs.\ 20500,Rs.25200,Rs.\ 24200$
0%
$Rs.\ 20500,Rs.21200,Rs.\ 28200$
0%
$Rs.\ 20500,Rs.23200,Rs.\ 26200$

Explanation

Ratio of the capitals of A, B and C =

$20000 \times 5 + 15000 \times 7 : 20000 \times 5 + 16000 \times 7 20000 \times 5 + 26000 \times 7$

$= 205000 : 212000 : 282000 = 205 : 212 : 282$

$\therefore$ A's share

$=Rs.(69900\times \dfrac{205}{699})=RS.20500$
B's share

$=Rs.(69900\times \dfrac{212}{699})=RS.21200$
C's share

$=Rs.(69900\times \dfrac{282}{699})=RS.28200$

A shop-keeper purchases

$11$ knives in Rs.

$10$ and sells them at the rate of

$10$ knives for Rs.

$11$ . He earns a profit of

0%
$11$ $\%$
0%
$15$ $\%$
0%
$17$ $\%$
0%
$21$ $\%$

Explanation

C.P. of $1$ knife $=\dfrac{10}{11}$
S.P of $1$ knife $= \dfrac{11}{10}$
Profit $=$ S.P $-$ C.P
Profit = $\dfrac{11}{10} - \dfrac{10}{11} = \dfrac{121 - 100}{110} = \dfrac{21}{110}$

Profit $\%$ $= \dfrac{\text {profit}}{\text {C.P.}} \times 100$

Profit $\%$ $= \dfrac{\dfrac{21}{110}}{\dfrac{10}{11}} \times 100$

$\Rightarrow \dfrac{21}{110} \times \dfrac{11}{10} \times 100 = 21$ $\%$

Which of the following subjects is not included in the union list ?

0%
Defence
0%
Income tax
0%
Railway
0%
Sales tax

If the cost of

$7$ kg of rice is Rs.

$168$ , what is the cost of

$105$ kg of rice?

0%
Rs. $2,580$
0%
Rs. $2,630$
0%
Rs. $2,520$
0%
Rs. $2,500$

Explanation

Cost of

$1$ kg of rice

$=\dfrac{168}{7}$

$=Rs\ 24$

Thus cost of

$105$ kg rice is given as

$Rs\ (24\times 105)$ that is equal to

$Rs\ 2520$

A shopkeeper makes a profit of

$20$

$\%$ even after giving a discount of

$10$

$\%$ on the advertised price of a T. V. set. If he makes a profit of Rs.

$450$ , the advertised price (in rupees) is

0%
$2700.00$
0%
$\displaystyle2842\frac{2}{19}$
0%
$3000.00$
0%
$6750.00$

Explanation

Let the advertised price be Rs.

$100$

$\therefore$ S.P.of the T.V. set

$=100-10=$ Rs.

$90$
Since he gains

$20\%$

$\therefore$ C.P.of the T.V. set

$\displaystyle=\frac{100\times90}{120}=$ Rs.

$75$

$\therefore$ Profit

$=90-75=$ Rs.

$15$
If profit is Rs.

$15$ , then advertised Price

$=$ Rs.

$100$

$\therefore$ Profit is Rs.

$450$ advertised Price

$\displaystyle=\frac{100}{15}\times450=$ Rs.

$3000$

If the list price of a book is reduced by Rs 5, a person can buy 5 more books for RsThen the original cost of the book is

0%
Rs 15
0%
Rs 20
0%
Rs 25
0%
Rs 30

Explanation

Let the original list price of the book be=Rs x

Original number of books purchased=

$\frac { 300 }{ x }$

When the price of the book is reduced by 5

New Number of books purchased will be=

$\frac { 300 }{ x-5 }$

New number of books purchased-Original number of books purchased=5

$\therefore \frac { 300 }{ x-5 } -\frac { 300 }{ x } =5$

$\Rightarrow \frac { 300x-300x+1500 }{ x\left( x-5 \right) } =5$

$\Rightarrow { x }^{ 2 }-5x=300$

$\Rightarrow { x }^{ 2 }-20x+15x-300=0$

$\Rightarrow { x }\left( x-20 \right) +15\left( x-20 \right) =0$

$\Rightarrow \left( x-20 \right) \left( x+15 \right) =0$

$\Rightarrow x-20=0\quad or\quad x+15=0$

$\Rightarrow x=20\quad or\quad x=-15$

$\therefore x=20$

the original cost of book is Rs 20

Successive discounts of

$\displaystyle12\frac{1}{2}\%$ and

$\displaystyle7\frac{1}{2}\%$ are given on the marked price of the table. If the customer pays Rs 2590, then what is the marked price of the table?

0%
Rs 3,108
0%
Rs 3,148
0%
Rs 3,200
0%
Rs 3,600

Explanation

b'Marked price

$=$ Rs 100. Price after 1st discount

$\displaystyle=Rs\:87\frac{1}{2}$

Price after 2nd discount

$\displaystyle=Rs\:92\frac{1}{2}\%$ of

$\displaystyle87\frac{1}{2}$

But customer pays Rs 2590.

$\displaystyle\therefore M.P.=(2590\times100)\div\left(92\frac{1}{2}\%\:of\:87\frac{1}{2}\right)=Rs\:3,200$ .'

By selling a suitcase for Rs. 570, a man loses 5%. At what price must he sell it to gain 5%?

0%
Rs. 630
0%
Rs. 650
0%
Rs. 580
0%
Rs. 620

Explanation

Selling Price=Rs.570

Loss =5%

$\therefore C.P =\frac{100}{100-loss\%}\times S.P$

$\Rightarrow \frac{100}{95}\times 570=Rs.600$

Now C.P of the suitcase=600

Gain%=5%

$\therefore S.P=\frac{100+gain \%}{100} \times C.P$

$=\frac{105}{100}\times 600=Rs.630$

Hence he sell Rs.630 to gain 5%.

The best source of revenue for the State Government is

0%
Sales tax
0%
Entertainment tax
0%
Excise duty
0%
Motor vehicle tax

An agent makes a profit of

$20$ per cent even after giving

$10$ per cent discount on the advertised price. If he makes a profit of Rs.

$750$ on the sale of a scooter, the advertised price is

0%
Rs. $4500$
0%
Rs. $4750$
0%
Rs. $5000$
0%
Rs. $5250$

Explanation

Let the advertised price of a scooter

$=$ Rs. x

$\therefore$ Sale price of a scooter

$\displaystyle=Rs.\frac{90}{100}x=Rs.\frac{9}{10}x$

If the C.P. of scooter

$=$ Rs. y, then

$\displaystyle\frac{9}{10}x=\frac{100+20}{100}y=\frac{6}{5}y$

$\displaystyle\therefore y=\frac{3}{4}x$

but, Profit = S.P. - C.P.

$\displaystyle Rs.750=\frac{9}{10}x-y$

$\displaystyle Rs. 750=\frac{9}{10}x-\frac{3}{4}x$

$\displaystyle Rs.750=\frac{3}{20}x$

$\displaystyle x=Rs.\frac{20}{3}\times750=Rs. 5000$

Find the compound interest on Rs 1,200 for 2 years at 10% per annum

0%
Rs 252
0%
Rs 225
0%
Rs 300
0%
Rs 350

Explanation

Compound Interest

$C.I=A-P$
Formula for amount when compound interest is applied :

$A=P\left (1+\dfrac {r}{100}\right )^n$
Given

$P=1,200; n=2; r=10$

$\therefore A=1,200\left (1+\dfrac {10}{100}\right )^2=1,200\left (\dfrac {11}{10}\right )^2=\dfrac {1,200\times 121}{100}=Rs\ 1,452$

$CI=1,452-1,200=Rs\ 252$

XYZ Ltd. incurs a net loss of Rs. 5, 000 during are accounting years. Depreciation for the relevant year amount to Rs. 1000, preliminary expenses written off during the accounting years is Rs. 3, 000 and a loss of Rs. 4, 000 is due to sale of plant and mach ____________.

0%
Rs. 3, 000
0%
Rs. 2, 000
0%
Rs. 5, 000
0%
Rs. 4, 000

Sita's salary was reduced by 10%. In order to reach her salary back to the original amount it must be raised by

0%
$11\dfrac {1}{9}$ %
0%
$12\dfrac {1}{9}$ %
0%
$13\dfrac {1}{9}$ %
0%
$14\dfrac {1}{9}$ %

Explanation

Given that, sita's salary was reduced by 10 percent,

we have to find order to reach her salary back to the original amount it must be raised.

Let, Sita’s salary $=100$

, then remaining salary $=100-10$ of $100$

$=100-\dfrac{100-10}{100}$

$=Rs. 90$

Order to reach her salary back to the original amount it must be raised by $10$

$=\dfrac{10\times 100}{90}$

$=\dfrac{100}{9}$

$=11\dfrac {1}{9}\%$

Which discount series is profitable to the buyer 25%,12%,3%, or 18%, 1.7%,5%?

0%
First
0%
Second
0%
Both
0%
Neither

Explanation

Given that, series is profitable $25$ %, $12$ %, $3$ %, or $18$ %, $1.7$ %, $5$ %.

Now,series $25$ %, $12$ %, $3$ % is profitable in compare to series $18$ %, $1.7$ %, $5$ %.

Because $25$ percent is greater than $18$ percent

And 12 percent is greater than 1.7 percent

Hence this is the answer.

Four dealers advertise the same list price for a TV set. Which one of the following discount series is more advantageous to the customer?

0%
25% and 8%
0%
22% and 8%
0%
25% and 9%
0%
25% and 10%

Which discount series is profitable to the buyer first -: 25%, 12%,3%, or second -: 18%, 1.7%,5%?

0%
First
0%
Second
0%
Both
0%
Neither

Explanation

First discount series is better as the total discount which a customer will get is more.

in first total discount will be=

$25\%$ +

$12\%$ +

$3\%$ =

$40\%$

in second discount will be=

$18\%$ +

$1.7\%$ +

$5\%$ =

$24.7\%$

so first series is better.

A dealer earned a profit of

$5\%$ by selling a radio for Rs.

$714$ , What is cost price of the radio?

0%
$Rs.480$
0%
$Rs.680$
0%
$Rs.780$
0%
$Rs.700$

Explanation

Let the cost price of the radio be Rs.

$x$ .
And, profit

$=5$ %
Now, selling price

$=Rs.(x+5\%\ of\ x)=Rs.\cfrac{105}{100}x$

$\therefore$

$\cfrac{105}{100}x=714$

$\Rightarrow x=714\times \cfrac{100}{105}=680$
Hence, the cost price of the radio is Rs.

$680$

Ramu marked his bicycle atHe sold it without offering any discount. The price at which he bought it wasFind his profit percentage.

0%
60
0%
80
0%
50
0%
30

Explanation

Profit %

$= \frac {SP-CP}{CP} \times 100 = \frac {800-500}{500} \times 100 = 60$ %

Mr. Rai bought a machine that was tested at RsHe was given successive discounts of 20% and 10%, then the price he paid was

0%
Rs 120.40
0%
Rs 220.40
0%
Rs 230.40
0%
none of these

Explanation

List price of the machine=Rs320

after the first discount of 20% price will be

$=320-\frac { 20 }{ 100 } \times 320=256$

now a discount of 10% was given on Rs256

price of the machine will be,

$=256-\frac { 10 }{ 100 } \times 256=230.40$

The price he paid was Rs230.40

A man borrowed

$Rs,500$ at a rate of

$6\%$ per annum. At the end of 3

$\displaystyle \frac{1}{2}$ years, he paid back

$Rs. 350$ and gave his radio for the balance amount. The price of the radio is

0%
$Rs. 255$
0%
$Rs. 250$
0%
$Rs. 300$
0%
$Rs. 350$

Explanation

Given principal

$P=Rs.500$

Rate of interest

$R=6\%$

Time

$T=3\dfrac{1}{2}$ years

$=\dfrac{7}{2}$ years

Interest

$I=\dfrac{PTR}{100}$

$\therefore \displaystyle I = \frac{\displaystyle 500 \times \frac{7}{2} \times 6}{100} = Rs. 105$

Amount

$= P + I$

$= Rs.(500 + 105)$

$= Rs. 605$

So, price of radio

$=Rs.( 605 - 350) = Rs. 255$

Hence, the price of the radio is

$Rs.255$

A water filter is available for 500 down payment followed by two instalments of 600 each. If the total interest paid is 100, then what is the cash price of the water filter?

0%
1600
0%
1700
0%
1500
0%
1400

Explanation

Total amount paid

$= Rs 500 + 2(600) = Rs 1700$
In this

$Rs 100$ is interest , so actual price

$= Rs 1700 - 100 = Rs 1600$

$X$ sells an article to

$Y$ at

$15\%$ profit.

$Y$ sells it to

$Z$ at

$10\%$ profit. What is

$X's$ cost price, if

$Y$ makes a profit of

$23?$

0%
$200$
0%
$180$
0%
$150$
0%
$120$

Explanation

Let the

$CP$ of the article be

$Rs. 100$ .

Then for

$X\ to\ Y$ :
Given,

$Profit = 15$ %

$\Rightarrow \dfrac {SP-CP}{CP} \times 100 = 15$

$\Rightarrow \dfrac { S_x-100}{100} \times 100 = 15$

$\Rightarrow S_X = Rs 115$

Now, for

$Y\ to\ Z$ ,

$CP = Rs 115$
Given,

$Profit = 10$ %

$\Rightarrow \dfrac {SP-CP}{CP} \times 100 = 10$

$\Rightarrow \dfrac { S_Y- 115}{115} \times 100 = 10$

$\Rightarrow S_Y = Rs 126.5$

So, profit for Y

$= 126.5 - 115 = Rs 11.5$ when CP of article for X

$= Rs 100$

But given profit

$= Rs 23$

So, actual CP

$= Rs. \dfrac {23}{11.5} \times 100 = Rs. 200$

A dealer purchases

$15$ articles for

$\text{Rs }25$ and sells

$12$ articles for

$\text{Rs }30.$ Find the profit percentage.

0%
$50\%$
0%
$40\%$
0%
$20\%$
0%
$10\%$

Explanation

C.P. of

$15$ articles is

$\text{Rs }25$

$\therefore$ C.P. of each article

$= \dfrac {20}{15} = \dfrac {5}{3}$
S.P. of

$12$ articles is

$\text{Rs }30$

$\therefore$ S.P. of each article

$= \dfrac {30}{12} = \dfrac {5}{2}$

Now, Profit

$\% = \dfrac {S.P. - C.P.}{C.P.} \times 100 = \frac {\dfrac {5}{2}- \dfrac {5}{3}}{ \dfrac {5}{3}} \times 100 = 50 \%$

On selling a pen for Rs. 18 , a man losses

$\dfrac { 1 }{ 10 }$ of its cost price. The cost price of the pen is

0%
Rs. 16.20
0%
Rs 19.80
0%
Rs 20
0%
Rs 25

A trader marked a watch 40% above the cost price and then gave a discount of 10% He made a net profit of Rs 468 after paying a tax of 10% on the gross profit What is the cost price of the watch?

0%
Rs 1,200
0%
Rs 1,800
0%
Rs 2,000
0%
Rs 2,340

Explanation

Let the cost price of watch

$=$ Rs

$100$

Marker price

$=100+40=$ Rs

$140$

Then selling price =

$\dfrac{90}{100}\times 140=126$ Rs

So gain

$=126-100=26$ Rs

Net gain

$= 26-10\%$ of

$26=26\times 0.9=23.4$

Thus for the cost price of Rs

$100$ net gain is Rs

$23.4$

According to the given condition,

cost price =

$\dfrac{468}{23.4}\times 100=$ Rs

$2000$

The compound interest on

$Rs. 10,000$ in

$\displaystyle2\frac{1}{2}$ years at

$4\%$ per annum is

0%
$Rs. 1,032.32$
0%
$Rs. 1,045.50$
0%
$Rs. 1,100.25$
0%
$Rs. 1,150.70$

Explanation

Given principal

$=Rs.10,000$

Time

$=2.5$ years

Rate of interest

$=4\%$

Compound interest for first year

$=\dfrac{PTR}{100}=Rs.\dfrac { 10000\times 1\times 4 }{ 100 } =Rs.400$

Amount at the end of first year

$=Rs.(10000+400)=Rs.10400$

Amount for first year

$=$ Principal for second year

$=Rs.10400$

Compound interest for second year

$=\dfrac{PTR}{100}=Rs.\dfrac { 10400\times 1\times 4 }{ 100 } =Rs.416$

For next

$6$ months,

Principal

$=Rs.(10400+416)=Rs.10816$

Time

$=6\ months=\dfrac{1}{2}\ years$

Compound interest for next six months will be

$=\dfrac{PTR}{100}=Rs.\dfrac { 10816\times 1\times 4 }{ 100\times 2 } =Rs.216.32$

Total compound interest

$=Rs.(400+416+216.32)=Rs.1032.32$

If CP of 60 articles is equal to the SP of 50 articles Then gain % is__

0%
20%
0%
30%
0%
10%
0%
60%

Explanation

Let the CP of each article

$= x$
Then CP of

$50$ articles

$= 50 x$

Given, CP of

$60$ articles

$=$ SP of

$50$ articles.
So, SP of

$50$ articles

$= 60 x$

Now, Gain %

$= \dfrac {SP - CP}{CP} \times 100 = \dfrac {60x-50x}{50x} \times 100 = 20$ %

Ramesh invests Rs. 12,800 for three years at the rate of 10% per annum compound interest. Find the interest he earns for the second year.

0%
Rs. 1,162
0%
Rs. 1,243
0%
Rs. 1,408
0%
Rs. 1,591

Explanation

$=Rs.12800$

Rate of interest

$=10$ %

Interest for the first year

$=\dfrac{PRT}{100}$

$\Rightarrow \dfrac{12800\times 10\times 1}{100}=Rs.1280$

Amount after first year

$=12800+1280=Rs.14080$

For Second year

Principal

$=Rs.14080$

$=10$ %

$=1$ year

then Interest for second year

$=\dfrac{PRT}{100}$

$\Rightarrow \dfrac{14080\times 10\times 1}{100}=Rs.1408$

A sum of Rs.

$13,500$ is invested at

$16\%$ per annum compound interest for

$5$ years. Calculate the interest for the second year, correct to the nearest rupee.

0%
Rs. 2,106
0%
Rs. 2,279
0%
Rs. 2,506
0%
Rs. 2,792

Explanation

Sum=Rs 13,500

Rate=16%

Amount at the end of first year

$=P\left(1+\frac{R}{100}\right)^T$

$\Rightarrow 13500\left(1+\dfrac{16}{100}\right)$

$\Rightarrow 13500\times \dfrac{116}{100}=Rs.15,660$

For the second year

Sum

$=Rs\,15,660$

Then amount after second year

$=15660\left(1+\dfrac{16}{100}\right)$

$\Rightarrow 15,660\times \dfrac{116}{100}=Rs.18165.6$

$\therefore$ Interest for second year

$=18,165.6-15,660$

$=Rs\,2505.6$

Rounding off

$Rs\,2505.6$ we get

$Rs\,2,506$

Therefore interest for the second year is

$Rs\,2,506$

During every financial year, the value of a machine depreciates by 12%. Find the original cost of a machine which depreciates to Rs. 2,640 during the second financial year of its purchase.

0%
3409
0%
3333
0%
2365
0%
8551

Explanation

$\textbf{Step 1: Calculating the cost for the }\mathbf{1^{st}} \textbf{ year}$

$\text{Consider the original value to be x,}$

$\text{After the first year the value reduces to}$

$=x-\dfrac{12}{100}x=x-0.12x=0.88x$

$\textbf{Step 2: Calculating the cost for the }\mathbf{2^{nd}}\textbf{ year}$

$\text{The value reduces to}$

$=0.88x-\dfrac{12}{100}0.88x=0.88x\times(1-0.12)=0.7744x$

$\implies 0.7744x=2640$

$\implies x=3409$

$\textbf{Hence, The original value is Rs.3409}$

the market value of 120 shares;

0%
$7200$
0%
$2389$
0%
$6800$
0%
$6500$

Explanation

As the discount is Rs.15 then market value of 1 share

$=75-15=Rs.60$

$\therefore$ Market Value of 120 share

$=120\times 60= Rs. 7200$

Saurabh invests

$Rs.\ 48,000$ for

$7$ year at

$10\%$ per annum compound interest. Calculate the interest for the first year.

0%
$Rs.\ 4,800$
0%
$Rs.\ 4,900$
0%
$Rs.\ 5,000$
0%
$Rs.\ 5,100$

Explanation

Given:

$P=Rs.\ 48000$

$r=10\%$

$t=1$ year

$CI$ for

$1^{st}$ year

$=$

$SI$ for

$1^{st}$ year

$=\dfrac{PRT}{100}$

$=\dfrac{48000\times 10\times 1}{100}$

$=Rs.\ 4800$

Hence, option

$A$ is correct.

Calculate the amount at the end of the second year.

0%
Rs. $42,856$
0%
Rs. $48,140$
0%
Rs. $52,937$
0%
Rs. $58,080$

Explanation

Given,

Sum

$(P)=Rs.48000$

Rate

$=10\%$

Time

$=2\ year$

$Amount=P\left(1+\dfrac{R}{100}\right)^t$

$= 48000\left(1+\dfrac{10}{100}\right)^2$

$= 48000\times \dfrac{110}{100}\times \dfrac{110}{100}\\=Rs.58080$

A trader buys good at

$20\%$ discount on marked price. If he wants to make a profit of

$25\%$ after allowing a discount of

$20\%$ . By what percent should his marked price be greater than the original marked price?

0%
$15\%$
0%
$65\%$
0%
$25\%$
0%
$20\%$

Explanation

Let the marked price be Rs.

$100$ .

The trader buys at discount of

$20\%$ .

Hence, his cost price

$=100-20\%$ of

$100$

$=$ Rs.

$80$ .

He wants to make profit

$25\%$ , hence his selling price is

$=80+25\%$ of

$80$

$=$ Rs.

$100$ .

However, he wants to get this Rs.

$100$ after allowing a discount of

$20\%$ , i.e. he will sell at

$80\%$ of his marked price.

Hence, his marked price

$=\dfrac {100}{0.8}=$ Rs.

$125$ which is

$25\%$ more than the original marked price.

A shopkeeper announces a discount of

$15\%$ on his goods. If the marked price of an article, in his shop is

$Rs. 6,000$ ; how much a customer has to pay for it, if the rate of Sales Tax is

$10\%$ ?

0%
$Rs. 5,610$
0%
$Rs. 5,804$
0%
$Rs. 5,906$
0%
None of these

Explanation

Given,

$M.P=Rs.6000$

Sales tax

$=10\%$

S.P including sales tax

$=Rs.(6000+\dfrac{10}{100}\times 6000)$

$= Rs(6000+600)$

$=Rs.6600$

Discount

$=15\%$

$\therefore$ S.P after discount

$=Rs.(6600-15\% \ of\ 6600)$

$=Rs.( 6600- \dfrac{15}{100}\times 6600)$

$=Rs.( 6600-990)$

$=Rs.5610$

Hence, the customer has to pay

$Rs.5610$

The rate of Sales Tax

0%
8%
0%
10%
0%
12%
0%
14%

Explanation

Let the M.P =Rs.x

C.P=Rs.1700

$\therefore x-15\% of x=1700$

$\Rightarrow x-\frac{15}{100}x=1700$

$\Rightarrow \frac{85x}{100}=1700$

$\Rightarrow 85x=170000$

$\Rightarrow x=\frac{170000}{85}=Rs.2000$

If he raised the printed price of the article=20%

$\therefore$ S.P of the article

$=2000+\frac{20}{100}\times 2000$

$\Rightarrow 2000+400=Rs.2400$

S.P of the article including the tax=Rs.2688

Let the rate of sales tax=y%

Then

$2400+y\% of 2400=2688$

$\Rightarrow \frac{y}{100}\times 2400=2688-2400$

$\Rightarrow 24y=288$

$\Rightarrow y=\frac{288}{24}=12$ %

The rate of sales tax

0%
$3\%$
0%
$4\%$
0%
$5\%$
0%
$6\%$

Explanation

Let the List Price =Rs. x

Rebate=20%

$\therefore x-20\% of x=2400$

$\Rightarrow \frac{80x}{100}=2400$

$\Rightarrow x=\frac{2400\times 100}{80}=Rs.3000$

Shopkeeper mark the price 10% above the List price

$\therefore M.P=3000+\frac{10}{100}\times 3000=Rs.3300$

S.P Of the article including sales tax=Rs.3498

Let the rate of sales tax=y%

$\therefore 3300+y\% of 3300=3498$

$\Rightarrow \frac{y}{100}\times 3300=3498-3300$

$\Rightarrow 33y=198$

$\Rightarrow x=\frac{198}{33}=6$ %

When the rate of sale-tax is decreased from 9% to 6% for a coloured T.V.; Mrs. Geeta will save Rs. 780 in buying this T.V. Find the list price of the T.V.

0%
$Rs. 20,000$
0%
$Rs. 24,000$
0%
$Rs. 26,000$
0%
$Rs. 30,000$

Explanation

Let the List price of the T.V=Rs.x

Then according to the question

$(x+9\% of x)-(x+6\% of x)=780$

$\Rightarrow x+\frac{9x}{100}-x-\frac{6x}{100}=780$

$\Rightarrow \frac{9x}{100}-\frac{6x}{100}=780$

$\Rightarrow 3x=78000$

$\Rightarrow x=\frac{78000}{3}=Rs. 26000$

The catalogue price of an article is Rs. 20,The dealer allows two successive discounts 15% and 10%. If Sales Tax at the rate of 10% is charged on the remaining amount. Find:

The final total price that customer has to pay for the article.

0%
Rs. 13,830
0%
Rs. 16,830
0%
Rs. 19,830
0%
None of these

Explanation

M.P of the article =Rs.20000

Discount=15% and 10%

C.P after discount

$=20000\times \frac{85}{100}\times \frac{90}{100}=Rs.15300$

Rate of sales tax=10%

Sales tax amount=10% of 15300

$=\frac{10}{100}\times 15300=Rs.1530$

Final price of the article

$=15300+1530=Rs.16830$

A price paid by a customer to buy this article.

0%
$Rs. 1,590$
0%
$Rs. 1,080$
0%
$Rs. 1,260$
0%
$Rs. 1,175$

Explanation

S.P of the article =Rs.1000

rate of sales tax=8%

The price paid by the customer to buy the article

$=1000+8\% of 1000$

$\Rightarrow 1000+\frac{8}{100}\times 1000$

$\Rightarrow 1000+80=Rs.1080$

The price paid by the shopkeeper.

0%
$Rs. 2,400$
0%
$Rs. 2,100$
0%
$Rs. 1,890$
0%
$Rs. 1,960$

Explanation

Printed price

$=Rs 2500$

Discount Rate

$=30 \%$

Price after discount

$=2500-30\% \quad of \quad 2500$

$\Rightarrow 2500-\dfrac{30}{100}\times 2500$

$\Rightarrow 2500-750=Rs.1750$

Rate of sales tax

$=8 \%$

$\therefore$ Price paid by the shopkeeper

$=1750+\dfrac{8}{100}\times 1750$

$\Rightarrow 1750+140=Rs.1890$

The Sales Tax amount a customer has to pay.

0%
Rs. 1,530
0%
Rs. 1,260
0%
Rs. 1,950
0%
Rs. 1,420

Explanation

M.P of the article =Rs.20000

Discount=15% and 10%

C.P after discount

$=20000\times \frac{85}{100}\times \frac{90}{100}=Rs.15300$

Rate of sales tax=10%

Sales tax amount=10% of 15300

$=\frac{10}{100}\times 15300=Rs.1530$

The catalogue price of a colour T.V. is Rs. 24,000. The Shopkeeper gives a discount of 8% on the list price. He gives a further off season discount of 5% on the balance. But Sales Tax at 10% is charged on the remaining amount. Find:

The final price he has to pay for the T.V.

0%
Rs. 26,077.60
0%
Rs. 25,773.60
0%
Rs. 24,667.60
0%
Rs. 23,073.60

Explanation

List price=Rs. 24000

Discount=8%

Price after first discount

$=24000-\frac{8}{100}\times 24000$

$\Rightarrow 24000-1920=Rs.22080$

Another discount=5%

Price after second discount

$=22080-\frac{5}{100}\times 22080$

$\Rightarrow 22080-1104=Rs. 20976$

Sales tax=10%

Amount of sales tax

$=\frac{10}{100}\times 20976=2097.6$

Final price of the T.V

$=20976+2097.60=23073.6$

A toy is purchased for Rs. 591.36 which includes 12% rebate on the printed price and 12% Sales Tax on the sale price of the toy. Find the printed price of the toy.

0%
Rs. 300
0%
Rs. 450
0%
Rs. 550
0%
Rs. 600

Explanation

Let the sales price of the toy=Rs.x

Then according to the question

$\Rightarrow x-\frac{12x}{100}=591.36$

$\Rightarrow \frac{100x-12x}{100}=591.36$

$\Rightarrow 88x=591.36\times 100$

$\Rightarrow x=\frac{59136}{88}=Rs.672$

Let the printed price =Rs.y

$\therefore y+\frac{12y}{100}=672$

$\Rightarrow \frac{100y+12y}{100}=672$

$\Rightarrow y=\frac{672\times 100}{112}=Rs.600$

The final price he has to pay for the colour T.V.

0%
$Rs. 12,960$
0%
$Rs. 15773$
0%
$Rs. 16,222$
0%
$Rs. 18,100$

Explanation

M.P=Rs.18000

Discount=20%

Price after discount

$=\frac{80}{100}\times 18000=14400$

Off seasons discount=10%

Final price of the T.V=

$14400-\frac{10}{100}\times 14400= Rs.12960$

A plot is sold for Rs.

$18,700$ with a loss of

$15\%$ . At what price it should be sold to get profit of

$15\%$ ?

0%
$25300Rs$
0%
$54000Rs$
0%
$25600Rs$
0%
$25900Rs$

Explanation

Let at Rs.

$x$

It can earn

$15\%$ profit

$\Rightarrow 85:18700=115:x$ [as, loss

$=100-15$ , profit

$=100+15$ ]

$\Rightarrow x=\dfrac{18700\times1}{85}$

$\Rightarrow x=$ Rs.

$25300$

So, the plot is sold of Rs.

$25300$

A man sells an article at a gain of

$20\%$ . If he had bought it for

$20 \%$ less and sold it for

$264$ less, he would have still gain

$20\%$ .The cost price of the article is ?

0%
Rs. $1100$
0%
Rs. $2400$
0%
Rs. $2600$
0%
Rs. $2650$

Explanation

Let C.P. be

$X$

Hence, S.P.

$= X+20\%$ of

$X=X+\dfrac{20}{100}\times X= 1.2 X$
If he had bought it for

$20\%$ less

Then, new C.P.

$= X - 20\%$ of

$X =X-\dfrac{20}{100}X= 0.8X$
And new S.P.

$= 1.2X - 264$

Gain

$= 20\%$

$\Rightarrow \dfrac{(1.2X-264)-.8X}{.8X}=\dfrac{20}{100}$

$\Rightarrow \dfrac{.4X-264}{.8X}=\dfrac{20}{100}$

$\Rightarrow 40x-26400=16x$

$\Rightarrow 24x=26400$

$\Rightarrow X = 1100$
Thus, C.P. of the article

$=$ Rs.

$1100$ .

A shopkeeper buys an article for Rs. 7,500 and increases its price. He sells this article for Rs. 9,156 including 9% sales tax on the increased price. Calculate, by how much per cent does the shopkeeper increases the price of the article.

0%
$10\%$
0%
$12\%$
0%
$14\%$
0%
$16\%$

Explanation

Let shopkeeper increase the price Rs.x

$\therefore x+9\% of x=9156$

$\Rightarrow x+\frac{9x}{100}=9156$

$\Rightarrow \frac{109x}{100}=9156$

$\Rightarrow 109x=915600$

$\Rightarrow x=\frac{915600}{109}=Rs.8400$

Increment

$=8400-7500=Rs.900$

% increment

$=\frac{900}{7500}\times 100=12$ %

The price paid by the customer

0%
$Rs. 582.50$
0%
$Rs. 532.50$
0%
$Rs. 572.50$
0%
$Rs. 562.50$

Explanation

Marked Price of the article=Rs.500

The retailer sell the article to the customer at marked price at 12.5% sales-tax

Then price paid by the customer=500+12.5% of 500

$\Rightarrow 500+\frac{12.5}{100}\times 500$

$\Rightarrow 500+62.5=Rs.562.50$

CBSE Questions for Class 8 Maths Comparing Quantities Quiz 6 - MCQExams.com

0:0:1

Practice Class 8 Maths Quiz Questions and Answers

CBSE Questions for Class 8 Maths Comparing Quantities Quiz 6 - MCQExams.com

0:0:1

Practice Class 8 Maths Quiz Questions and Answers

Support mcqexams.com by disabling your adblocker.