MCQ Questions for Class 8 Maths Comparing Quantities Quiz 8

A consumption tax imposed by the government on the sale of goods and services is called

0%
VAT
0%
sales tax
0%
income tax
0%
business tax

In the tax saver fixed deposit accounts, the deposit holder saving in which tax?

0%
income tax
0%
sales tax
0%
property tax
0%
land tax

Cost Comparison of Tools

Item	Cost at John's Tools	Cost at Lin's Tools
Hammer	$$15$	$$18$
Drill	$$50$	$$55$
Electric saw	$$30$	$$25$

If a distributor receives a

$10$ % discount from Johns Tools and a

$15$ % discount from Lins Tools, how much more would they pay, in dollars, to buy a drill and electric saw from Johns Tools than Lins Tools?

0%
$\$4$
0%
$\$5$
0%
$\$2$
0%
$\$7$

Explanation

John's tool

$10\%$ discount

$=$

$\dfrac{50+30}{100}\times 10=8$

Lin's tool

$15\%$ discount

$=$

$\dfrac{55+25}{100}\times 15=12$

The cost to buy a drill and electric saw from Johns tools than Lins tools

$= 12 - 8 = \$4$

If paintbrushes cost

$1.50$ each and canvases cost 6 times that much, which of the following represents the cost, in dollars, of

$p$ paintbrushes and

$c$ canvases?

0%
$7.5pc$
0%
$10.5pc$
0%
$9c+1.5p$
0%
$10.5(p+c)$

Explanation

Cost of

$1$ paintbrush

$=1.50$

Hence cost of

$p$ paintbrushes

$=(p\times 1.5)$

Also,

Cost of

$1$ canvas

$=1.50\times 6=9$

Hence cost of

$c$ canvases

$=(c\times 9)$ .

So,

Cost of

$p$ paintbrushes and

$c$ canvases

$=1.5p+9c$

The population of an invasive species of moth doubles every

$5$ years. If the initial population is

$300$ , what will be the population after

$15$ years?

0%
$900$
0%
$1200$
0%
$2000$
0%
$2400$

Explanation

Population of an invasive species of moth doubles every

$5$ years.

Let the initial population be

$x$

So after

$5$ years, population will be

$2\times x=2x$

After

$10$ years, population will be

$2\times 2x=4x$

After

$15$ years, population will be

$2\times 4x=8x.$

Here, initial population is

$x=300$ .

After

$15$ years, population will be

$8x=8\times 300=2400$

Hence, the population after

$15$ years is

$2400$

FURNITURE SET

Set	$A$	$B$	$C$
Tables	$1$	$2$	$3$
Chairs	$7$	$5$	$2$

PRICES

Year	$2002$	$2007$	$2012$
Table	$$60$	$$80$	$$100$
Chair	$$30$	$$35$	$$40$

A furniture company sells three sets of furniture: set

$A$ , set

$B$ , and set

$C$ . Each set consists of a different number of tables and chairs as shown in the first table above. The second table shows the sale prices in dollars of each table and chair in three different years. Based on the prices shown, calculate the greatest possible sale price in dollars of a furniture set bought in

$2007$ .

0%
$$270$
0%
$$335$
0%
$$320$
0%
$$325$
0%
$$315$

Explanation

Consider furniture set

$A$ : it consists

$1$ table and

$7$ chairs.
The price of set

$A$ in

$2007$ :

$1\times$80+7\times$35=$325$
Consider furniture set

$B$ : it consists

$2$ tables and

$5$ chairs.
The price of set

$B$ in

$2007$ :

$2\times$80+5\times$35=$335$
Consider furniture set

$C$ : it consists

$3$ tables and

$2$ chairs.
The price of set

$B$ in

$2007$ :

$3\times$80+2\times$35=$310$
The greatest of these three is

$\$335$ .
Hence,option

$B$ is correct.

Spice prices of distributor A

Spice	Price Per Kilogram
Cinnamon	$$7.00$
Nutmeg	$$10.00$
Ginger	$$5.00$
Cloves	$$9.00$

If a customer buys

$2$ kilograms each of cinnamon and ginger and then sells to another person, then what is his net profit if he earns a profit of

$$3$ per

$100$ grams?

0%
$$192$
0%
$$120$
0%
$$126$
0%
$$1200$

Explanation

Given that a person buys 2 kg cinnamon and 2 kg ginger and sell both with profit of $ 3 per kg

Than the total weight of cinnamon and ginger =2+2=4 kg =40000 gms

He earn profit of $3 per 100 gms

Than he get profit =

$\dfrac{$3}{100}\times 40000=$120$

A hardware store sells lightbulbs in different quantities. The figure above shows the cost of various quantities. According to the figure, what is the cost of a single lightbulb?

0%
$$0.56$
0%
$$1.80$
0%
$$2.50$
0%
$$3.60$

Explanation

From the graph we can see that cost of

$5$ lightbulbs is

$$9$

Hence, cost of

$1$ lightbulb

$=\dfrac95=$1.80$

1421426_493967_ans_89575a3bb2064a95aa8e61513bb2ee59.png

In January the price of a certain item was

$\$120$ . In February the price increased by

$10$ percent. During a sale in March, the February price was discounted by

$10$ percent. What was the price of the item during the sale in March?

0%
$\$106.80$
0%
$\$118.80$
0%
$\$120.00$
0%
$\$121.20$

Explanation

C.P(Cost Price) of a certain article is

$$120$

In February the cost price increased by 10 percent which means=

$10\%\ of C.P+C.P$

$=10\%\ of\ 120+120$

$=\dfrac{10}{100}\times 120+120$

$=12+120$

$=132$

In March the price was discounted by

$10\%$ which means we have to subtract

$10\%$ from the amount we get in February

$=132-10\%\ of\ 132$

$=132-\dfrac{10}{100}\times 132$

$=132-13.2$

$=118.8$ $

In the half yearly exam only

$70\%$ of the students were passed. Out of these (passed in half yearly) only

$60\%$ students are passed in annual exam. Out of those who did not pass the half yearly exam,

$80\%$ passed in annual exam. What per cent of the students passed the annual exam?

0%
$42\%$
0%
$56\%$
0%
$66\%$
0%
$38\%$

Explanation

Let the total students be

$x$ .

Given that,

$70\%$ students passed in half yearly examination.

Then, passed students in half yearly

$=\dfrac{70}{100}\times x=0.70x$

Out of these passed in half yearly,

$60\%$ students passed in annual exam.

Then, passed students in annual examination

$=\dfrac{60}{100}\times 0.70x=0.42x$

The number of students who did not pass in half yearly examination

$=x-0.70x=0.30x$

Given out of these who did not pass the half yearly examination,

$80\%$ students passed in annual exam.

Then, out of these student who did not pass in half yearly examination, number of students who passed in annual exam

$=\dfrac{80}{100}\times 30x=0.24x$

Then, total number of students who passed annual examination

$=0.42x+0.24x=0.66x$

Therefore,

$\%$ of students who passed the annual exam

$=\dfrac{0.66x}{x}\times 100=66\%$

Hence,

$66\%$ students passed the annual exam.

A barrel of crude oil is extracted from shale at a cost of

$\$51$ , and then transported to and from the refinery at a cost of

$\$6$ each direction. Oil is processed three times at the refinery plant, at a cost of

$\$9$ each time. What is the profit, in dollars per barrel, if one barrel is sold for

$\$93$ ? (Profit is equal to revenue minus expenses.)

0%
$1$
0%
$2$
0%
$3$
0%
$4$

Explanation

Costing in the process of making and transporting oil are:

Cost of extraction

$=\$51$

Cosr of transportation to and from refinery=

$\$(6+6)=$12$

Cost of processing

$3$ times at

$\$9$ each time

$=\$(3\times 9)=\$27$

Total Cost

$= \$(51+12+27)=$

$$90$

Selling Price=

$$93$

Profit

$=\$(93-90)=$3$

If an article is sold at

$8\%$ profit instead of

$8\%$ loss, it would have brought Rs.

$12$ more, what is the cost price of the article?

0%
Rs. $60$
0%
Rs. $70$
0%
Rs. $72$
0%
Rs. $75$

Explanation

Let the Cost Price (C.P) be Rs

$x$ and then at

$8\%$ of profit

Selling Price(S.P) would be :

Gain

$\%$ =

$\dfrac{(S.P - C.P)}{C.P} \times 100$

$\Rightarrow 8 \% =\dfrac{S.P- x}{x}\times100$

$\Rightarrow \dfrac{8x}{100} = S.P - x$

$\Rightarrow S.P = \dfrac{8x}{100} + x$

$\Rightarrow S.P = \dfrac{108x}{100}$ .....(1)

Now, If the loss is

$8 \%$

$\Rightarrow \dfrac{8x}{100}= x - S.P$

$\Rightarrow S.P = \dfrac{92x}{100}$ ...(2)

Now we have the condition from 1 and 2 we get :

$S.P (profit) = S.P(loss) + 12$

$\Rightarrow \dfrac{108x}{100} = \dfrac{92x}{100} +12$

$\Rightarrow \dfrac{(108 - 92 )}{100} x = 12$

$\Rightarrow \dfrac{16}{100}x = 12$

$\Rightarrow 16x = 12 \times 100$

$\Rightarrow x = \dfrac{12\times 100 }{16}$

$\Rightarrow x = 75$

$\Rightarrow C.P =$ Rs

$75$

The Cost Price of the article is

$Rs 75$ .

In a certain store, the profit is

$320$ % of the cost. If the cost increases by

$25$ % but the selling price remains constant, approximately what percentage of the selling price is the profit?

0%
$30$ %
0%
$70$ %
0%
$100$ %
0%
$250$ %

Explanation

Let

$C.P.= Rs. 100$ . Then,

$Profit = Rs. 320, S.P. = Rs. 420$ .
New

$C.P. = 125$ % of

$Rs. 100 = Rs. 125$
New

$S.P. = Rs. 420$ .

$Profit = Rs. (420 - 125) = Rs. 295$ .

$\therefore$ Required percentage

$=\left (\dfrac {295}{420}\times 100\right )$ %

$= \dfrac {1475}{21}$ %

$= 70$ % (approximately).

The question given below consists of a question followed by three statements. You have to study the question and the statements and decide which of the statement(s) is/are necessary to answer the question.

By selling an article what is the profit percent gained?
I.

$5\%$ discount is given on list price.
II. If the discount is not given,

$20\%$ profit is gained.
III. The cost price of the articles is

$\text{Rs. } 5000$ .

0%
Only I and II
0%
Only II and III
0%
Only I and III
0%
All I, II and III
0%
None of these

Explanation

I. Let the list price be

$\text{Rs. } x$
Then,

$\text{S.P.} = 95\%$ of

$\text{Rs. } x = \text{Rs. } \left (x\times \dfrac {95}{100}\right ) = \text{Rs. } \dfrac {19x}{20}$
II. When

$\text{S.P.} = \text{Rs. } x$ and gain

$= 20\%$
Then,

$\text{C.P.} =\text{Rs. } \left (\dfrac {100}{120}\times x\right ) =\text{Rs. } \dfrac {5x}{6}$

$\therefore \text{Gain} = \left (\dfrac {19x}{20} - \dfrac {5x}{6}\right ) = \left (\dfrac {57x - 50x}{60}\right ) = \dfrac {7x}{60}$

$\therefore \text{Gain}\%$

$=\left (\dfrac {7x}{60}\times \dfrac {6}{5x} \times 100\right )\%$

$= 14\%$ .
Thus, I and II only give the answer.

$\therefore$ Correct answer is (A).

A trader marks

$10\%$ higher than the cost price. He gives a discount of

$10\%$ on the marked price. In this kind of sales how much percent does the trader gain or lose?

0%
$5\%$ gain
0%
$2\%$ gain
0%
$1\%$ loss
0%
$3\%$ loss

Explanation

Let the cost price be

$\text{Rs }100$

Then the mark-up price is

$10\%$ above the cost price.

Mark price

$=(100+10\% \ \text{of}\ 100)=$

$\text{Rs.}$

$110$

Trader gives

$10\%$ discount on the marked price, then the

Selling price

$=(110-10\% \ \text{of}\ 110)=$

$\text{Rs.}$

$99$

Therefore, Loss

$=$ cost price

$-$ selling price

Loss

$=100-99= \text{Rs }1$ on cost price of

$\text{Rs }100$

Thus loss percent is

$1\%$ .

The first year's interest on a sum of money lent at

$8$ % compound interest is

$Rs. 48$ . The second year's amount is

0%
$Rs. 48$
0%
$Rs. 51.48$
0%
$Rs. 56.48$
0%
$Rs. 96$

At the "

$30\%$ off" book sale, a calculus book costs

$\$24$ . What is the original price of the book?

0%
$\$72.80$
0%
$\$77$
0%
$\$80$
0%
$\$82.60$

Explanation

Let the original price of the book be

$x$ .

After

$30 \%$ discount on the original price the rate is

$$24$

Therefore,

$30 \%$ on

$x$ is

$$24$

$\Rightarrow \dfrac{30}{100}\times$

$x$ =

$24$

$\Rightarrow \dfrac{3}{10}\times$

$x$ =

$24$

$\Rightarrow x=\dfrac{24 \times 10}{3}$

$\Rightarrow x=\dfrac{240}{3}$

$\Rightarrow x=$80$

A men's clothing retailer order

$25,400$

$worth of outer garments and receives a discount of$

$15$

$% followed by an additional discount of$

$10$ $%. What is the cost of the clothing after these two discounts?

0%
9431
0%
19431
0%
1943
0%
19234

Explanation

First he got

$15$

$\%$ discount, therefore after discount the cost of clothing is

$\left (1-\dfrac{15}{100}\right) \times 25400 = 21590$
Now he got additional

$10$

$\%$ discount
Now the cost of clothing is

$\left (1-\dfrac{10}{100}\right) \times 21590 = 19431$

The price of commodity

$X$ increases by

$40$ paise every year, while the price of commodity

$Y$ increases by

$15$ paise every year. If in

$2001$ , the price of commodity

$X$ was Rs.

$4.20$ and that of

$Y$ was Rs.

$6.30$ , in which year commodity

$X$ will cost

$40$ paise more than the commodity

$Y$ ?

0%
2010
0%
2011
0%
2012
0%
2013

Explanation

Suppose commodity

$X$ will cost

$40$ paise more than

$Y$ after

$z$ years.

Then,

$\left( 4.20+0.40z \right) -\left( 6.30+0.15z \right) =0.40$

$\Rightarrow 0.25z=0.40+2.10$

$\Rightarrow z=\dfrac { 2.50 }{ 0.25 } =\dfrac { 250 }{ 25 } =10$ .

$\therefore$

$X$ will cost

$40$ paise more than

$Y$

$10$ years after

$2001$ which is

$2011$ .

If an item is purchased at

$150$

$and sold at$

$165$ , what percent of the original cost is the profit?

0%
$110$ percent
0%
$89$ percent
0%
$100$ percent
0%
$9$ percent
0%
$10$ percent

Explanation

Given:

cost price

$=150$ dollar

Selling price

$=165$ dollar

Profit

$=$ selling price

$-$ cost price

$=165-150=15$ dollar

Percent of the original cost

$=\dfrac{15}{150}\times 100$

$=10\%$

Option 'E'.

Which set of the statement can give the percentage of discount given?
I.

$23.5$ % profit was earned by selling an almirah for

$Rs. 12,350$ .
II. If there were no discount, the earned profit would have been

$30$ %.
III. The cost price of the almirah was

$Rs. 10,000$ .

0%
I and II
0%
II and III
0%
I and III
0%
Any two of the three
0%
None of these

Explanation

$(1)$

$S.P. = Rs. 12350, Gain = 23.5$ %

$\therefore C.P. = Rs. \left (\dfrac {100}{123.5}\times 12350\right ) = Rs. 10,000$ .

$(2)$

$M.P. = 130$ % of

$C.P. = 130$ % of

$Rs. 10,000 = Rs, 13,000$ .

From

$(1)$ and

$(2)$ , discount

$= Rs. (13000 - 12350) = Rs. 650$ .

Discount %

$= \left (\dfrac {650}{13000}\times 100\right )$ %

$= 5$ %.

Thus,

$(1)$ and

$(2)$ give the answer.

$(2)$ and

$(3)$ can not give the answer. Because we require profit percentage with discount and profit percentage without discount. So

$(2)$ and

$(3)$ are not sufficient to give the discount percentage.

Also,

$(1)$ and

$(3)$ can not give the answer because C.P. can already be calculated with the use of

$(1)$ statement only but we need the discount percentage.

Since

$(3)$ gives only

$C.P. = Rs. 10,000$ ,

$(1)$ and

$(2)$ give the answer.
Therefore,

$(1)$ and

$(2)$ give the answer.

$\therefore$ Correct answer is (A).

The calculation of interest on the interest of principal amount is called

0%
simple interest
0%
compound interest
0%
multiple interest
0%
interest quarterly compounded

Explanation

The calculation of interest on the interest of principal amount is called

$Compound\,\,interest$ .

Compound interest is the addition of interest to the principal sum of a loan or deposit, or in other words, interest on interest.

It is the result of reinvesting interest, rather than paying it out, so that interest in the next period is then earned on the principal sum plus previously accumulated interest.

Compound interest is standard in finance and economics.

Anagha borrowed Rs.

$70,000$ from her friend at the rate of

$3.5\%$ p.a.compounded yearly. She returned the amount after three years. So calculate interest of first year and second year .

0%
$Rs.2,450, 85.75$
0%
$Rs.2,450, 2,450$
0%
$Rs.2,450, 2,535.75$
0%
$Rs.2,450, 2100$

Explanation

$P=70000,R=3.5$ %

Interest in

$1$ st year

$=\cfrac { P\times R\times T }{ 100 }$

$=\cfrac { 70000\times 3.5\times 1 }{ 100 }$

$=2450$

Now,

$(2450+P)$ will be principal amount for

$2$ nd year since interest is compounded yearly

Interest in

$2$ nd year

$=\cfrac { { P }^{ ' }\times R\times T }{ 100 }$

$=\cfrac { (2450+70000)\times 3.5\times 1 }{ 100 }$

$=724.5\times 3.5=2535.75$

Megha lended Rs.

$8000$ as a loan for

$4$ years at the rate

$4\%$ compounded annualy. Calculate the interest she will recive by the method of simple interest.

0%
$8963.26$
0%
$9358.86$
0%
$1358.86$
0%
$9863.25$

Explanation

$P=8000,R=4$ %,

$T=4$

Interest in

$1$ st year

$=\cfrac { P\times R\times T }{ 100 }$

$=\cfrac { 8000\times 4\times 1 }{ 100 }$

$=320$

Now, Principal amount will be

$(P+320)$ since the interest in compounded annually.

Interest in

$2$ nd year

$=\cfrac { { P }^{ ' }\times R\times T }{ 100 }$

$=\cfrac { 8320\times 4\times 1 }{ 100 }$

$=332.8$

Now,

$P''=332.8+P'$

Interest in

$3$ rd year

$=\cfrac { 8652.8\times 4\times 1 }{ 100 } =346.112$

Interest in

$4$ th year

$=\cfrac { (346.112+8652.8)\times 4\times 1 }{ 100 } =359.956$

Total interest

$=320+332.8+346.112+359.95$

$=1358.86$

Ranjana borrowed the money Rs

$1,00,000$ for

$3$ years at the rate

$3.5\%$ p.a. compounded annually. Calculate interest to be paid.

0%
$10871.78$
0%
$1000.8$
0%
$8710.68$
0%
$245$

Explanation

$\Rightarrow$ Here, Principal amount for first year =

$Rs.1,00,000$

$\Rightarrow$ First year Interest =

$\dfrac{100000\times 3.5}{100}=Rs.3500$

$\Rightarrow$ Principal amount for second year =

$Rs.1,00,000+Rs.3500=Rs.1,03,500.$

$\Rightarrow$ Second year interest =

$\dfrac{103500\times 3.5}{100}=Rs.3622.5$

$\Rightarrow$ Principal amount for third year =

$Rs.1,03,500+Rs.3622.5=Rs.1,07,122.5$

$\Rightarrow$ Third year interest =

$\dfrac{107122.5\times 3.5}{100}=Rs.3749.28$

$\therefore$ Total Interest =

$Rs.3500+Rs.3622.5+Rs.3749.28=Rs.10871.78$

The bank offers senior citizens intrest at the rate

$9\%$ p.a compounded yearly on a fixed deposit. What interest will be received at the end of

$5$ years if Rs.

$10,000$ are deposited. Calculate by the method of simple interest.

0%
$5386.23$
0%
$5500.23$
0%
$6523.65$
0%
$4367.78$

Explanation

$P=10000,R=9,T=5$ yrs

Interest in

$1$ st year

$=\cfrac { P\times R\times T }{ 100 }$

$=\cfrac { 10000\times 9\times 1 }{ 100 }$

$=900$

$P'=(900+10000)$

Interest in

$2$ nd year

$=\cfrac { 10900\times 9\times 1 }{ 100 } =981$

Interest in

$3$ rd year

$=\cfrac { 11881\times 9\times 1 }{ 100 }$

$=1069.29$

Interest in

$4$ th year

$=\cfrac { 12950.29\times 9\times 1 }{ 100 }$

$=1165.5261$

Interest in

$5$ th year

$=\cfrac { 14115.81\times 9\times 1 }{ 100 }$

$=1270.42$

Total interest

$=900+981+1069.29+1165.52+1270.42$

$=5386.23$

A businessman borrowed the Rs.

$45$ lakh for two years at the rate

$2.5\%$ p.a. compounded annually. Calculate the compound interest by simple interest method.

0%
$2,23000$
0%
$2,27,812.5$
0%
$5,65,563$
0%
$2,00,000$

Explanation

$\Rightarrow$ Here, Principal amount for first year is

$Rs.45,00,000$ and

$R=2.5\%$ .

$\Rightarrow$ Interest for first year =

$\dfrac{4500000\times 2.5}{100}=Rs.1,12,500$

$\Rightarrow$ Principal amount for second year =

$Rs.4500000+Rs.112500=Rs.46,12,500$

$\Rightarrow$ Second year interest =

$\dfrac{4612500\times 2.5}{100}=Rs.1,15,312.5$

$\Rightarrow$ Total interest for 2 yeras =

$Rs.1,12,500+Rs.1,15,312.5=Rs.2,27,812.5$

Amar gave Rs.

$50,000$ as a loan to Amir at the rate of

$4\%$ p.a. Amir return the amount after two years. Calculate the interest on the first year's interest.

0%
$200$
0%
$70$
0%
$80$
0%
$60$

Explanation

$1$ year interest

$=\cfrac { P\times R\times T }{ 100 }$

$=\cfrac { 50000\times 4\times 1 }{ 100 } =2000$

Interest of

$1$ year interest

$=\cfrac { \left( { P }^{ ' }\times R\times T \right) }{ 100 }$

$=\cfrac { 2000\times 4\times 1 }{ 100 }$

$=80$

An industrialist borrowed the

$Rs\ 75,000$ for two years at the rate

$2.5\%$ p.a.compounded annually. Calculate the total amount compound interest by simple interest method.

0%
$2750$
0%
$3750$
0%
$78,795$
0%
$78,796.87$

Explanation

$P=75000,R=2.5$ %, Time

$=2$ yrs

Interest in

$1$ st year

$=\cfrac { P\times R\times T }{ 100 }$

$=\cfrac { 75000\times 2.5\times 1 }{ 100 }$

$=1875$

$P'=(1875+P)$

Interest in

$2$ nd year

$=\cfrac { { P }^{ ' }\times R\times T }{ 100 }$

$=\cfrac { 76875\times 2.5\times 1 }{ 100 }$

$=1921.875$

Total interest

$=1875+1921.875$

$=3796.875$

Total amount=Principal

$+$ Total interest

$=75000+3796.875$

$=78796.875$

Aman gave Rs.

$9500$ as a loan to Megh at the rate of

$4\%$ p.a. compounded yearly. Megh returned the amount after two years. Calculate the interest on the first year's interest.

0%
$380$
0%
$270$
0%
$15.2$
0%
$40$

Explanation

$P=9500,R=4,T=2$ years

Interest in

$1$ year

$=\cfrac { P\times R\times 1 }{ 100 }$

$=\cfrac { 9500\times 4 }{ 100 }$

$=380$

Interest on interest

$=\cfrac { 380\times 4\times 1 }{ 100 }$

$=15.2$

A man lends Rs.

$12,500$ at

$12$ % for the first year, at

$15$ % for the second year and at

$18$ % for the third year. If the rates of interest are compounded yearly; find the difference between the C.I. for the first year and the compound interest for the third year.

0%
$\text{Rs }1,498$
0%
$\text{Rs }1,598$
0%
$\text{Rs }1,298$
0%
$\text{Rs }1,398$

Ajay had purchased a second hand scooter for Rs.

$18000$ and spent Rs

$1800$ for repairs. After

$1$ year he wanted to sell the scooter. At what price should he sell it to gain

$\cfrac{100}{9}$ % , if

$\cfrac {100}{11}$ % is to be deducted at the end of every year on account of depreciation?

0%
$10,000$
0%
$20,000$
0%
$30,000$
0%
$40,000$

Explanation

$C.P$ of the scooter=Rs.

$18000$

Gain=

$\dfrac{100}{9}\%$

$SP=\dfrac{(100+\dfrac{100}{9})}{100}\times 18000$

$=\dfrac{100}{9}\times 180=Rs.20000$

The annual production in cement industry is subject to business cycles. The production increases for two consecutive years consistently by

1818?

0%
$24$ % increase
0%
$25$ % increase
0%
$42$ % increase
0%
$45$ % increase

Explanation

After every

$2$ years

$18$ % increase/year third year

$12$ % decrease

Base year is

$2008$

$2008+2=2010$

$2010,$ effect

$=18+18=36$

$2010+1=2011$

$2011$ , effect

$=36-12=24$

$2012$ effect

$=24+18=42$

$\therefore$ In

$2012$ , total effect will be

$42$ % increase.

A bank pays interest at the rate of

$8\%$ per annum compounded yearly. Find the interest by simple interest method if

$Rs.\ 8000$ was deposited for

$3$ years.

0%
$Rs.\ 1000$
0%
$Rs.\ 2077.7$
0%
$Rs.\ 2000$
0%
$Rs.\ 3456$

Explanation

$P=Rs.\ 8000,R=8$ %, Time period

$=3$ years

Interest in

$1$ st year

$=\cfrac { P\times R\times T }{ 100 }$

$=\cfrac { 8000\times 8\times 1 }{ 100 }$

$=Rs.\ 640$

Principal amount for

$2$ nd year will be,

$P'=P+640$

$=Rs.\ 8000+Rs.\ 640$

$=Rs.\ 8640$

Interest in

$2$ nd year

$=\cfrac { 8640\times 8 }{ 100 }$

$=Rs.\ 691.2$

Principal amount for

$2$ nd year will be,

$P''=P'+691.2$

$=Rs.\ 8640+Rs.\ 691.2$

$=Rs.\ 9331.2$

Interest in

$3$ rd year

$=\cfrac { 9331.2\times 8 }{ 100 }$

$=Rs.\ 746.5$

So, total interest

$=640+691.2+746.5$

$=Rs.\ 2077.69$

$\approx Rs.\ 2077.7$

The population of a town

$3$ years ago was Rs.

$50,000$ .If the population in these three years has increased at the rate of

$10\%,15\%$ and

$8\%$ respectively, find the present population.

0%
Rs. $68,210$
0%
Rs. $68,310$
0%
Rs. $68,410$
0%
Rs. $68,510$

Explanation

Let

$P=.50,000$ and

$R_1=10\%,\\ R_2=15\%,\\ R_3=8\%$ .

Present population =

$P\times \left (1+\dfrac{R_1}{100}\right)\left (1+\dfrac{R_2}{100}\right)\left (1+\dfrac{R_3}{100}\right)$
On substituiting the given values,

Present population

$=$

$50000\times \left (1+\dfrac{10}{100}\right)\times \left (1+\dfrac{15}{100}\right)\times \left (1+\dfrac{8}{100}\right)$

$=$

$50000\times \dfrac{11}{10}\times \dfrac {23}{20}\times \dfrac{27}{25} =68310$

Therefore, present population

$=$

$68310$ .

A sum of

$Rs.\ 15,000$ is invested for

$3$ years at

$10 \%$ per annum compound interest. Calculate the interest for the second year.

0%
$Rs.\ 1,680$
0%
$Rs.\ 1,650$
0%
$Rs.\ 1,710$
0%
$Rs.\ 1,640$

The price of

$282$ apples is Rs.

$1974$ . What will be the price of

$24$ dozens of apples?

0%
Rs. $2016$
0%
Rs. $2106$
0%
Rs. $2160$
0%
Rs. $2006$

By selling on article for

$Rs \ 950$ , a man loses

$5 \%$ . If he had sold it for

$Rs. 1,220$ , the gain would be

0%
$20 \%$
0%
$22 \%$
0%
$24 \%$
0%
$26 \%$

Explanation

Selling price of article

$= 950$ Rs, Loss

$= 5\%$

We know that

$SP=CP-Loss$

$\Rightarrow 950=CP-5\%\ of\ CP$

$\Rightarrow 950=CP-0.05\times CP$

$\Rightarrow 950=0.95\times CP$

$\therefore CP=\dfrac{950}{0.95}=1000\ Rs$

Now, Selling Price

$(SP)= 1220$ Rs

Here

$SP > CP$ , there will be a profit.

$\therefore$ Profit

$=SP-CP=1220-1000=220\ Rs$

$\Rightarrow Profit\ percentage =\dfrac{Profit\times 100}{CP}=\dfrac{220\times 100}{1000}=22\%$

If SP of an article is

$\displaystyle\frac{5}{4}$ of its CP then the profit percentage in the transaction is :

0%
$10$
0%
$20$
0%
$30$
0%
$25$

Explanation

Let

$CP = x$

Given that,

$SP=\dfrac{5}{4}CP=\dfrac{5x}{4}$

$\therefore profit = SP-CP=\dfrac{5}{4}SP-SP=\dfrac{SP}{4}=\dfrac{x}{4}$

$\therefore profit\ percentage=\dfrac{profit\times100}{CP}=\dfrac{\dfrac{x}{4}\times100}{x}=25\%$

Find the compound interest on Rs.

$70,000$ for

$2$ years, compounded annually at

$10\%$ per annum.

0%
$14,400$
0%
$14,700$
0%
$14,300$
0%
$14,100$

Explanation

Here,

$P=$ Rs

$70000$ ,

$R=10\%\ p.a$

interest for the first year

$=\cfrac{P\times R\times T}{100}$

$=\cfrac{70000\times 10\times 1}{100}$

$=$ Rs

$7000$

The amount after the first year

$=$ Rs

$77000$

Principal for the second year

$=$ Rs

$77000$

Interest for the second year

$=$ Rs

$\cfrac{77000\times 10\times 1}{100}$

$=$ Rs

$7700$

The final amount

$=$ Rs

$77000$ + Rs

$7700$

$=$ Rs

$84700$

Compound interest

$=$ Rs

$84700 -70000$

$=$ Rs

$14700$

The amount on Rs.

$20,500$ at

$7%$ per annum compunded annually for

$2$ years, is:

0%
$22470$
0%
$23470$
0%
$24470$
0%
$25470$

Explanation

$\Rightarrow$

$P=Rs.20,500,\,R=7\%$ and

$T=2\,years$

$\Rightarrow$

$A=P(1+\dfrac{R}{100})^T$

$\Rightarrow$

$A=20500\times (1+\dfrac{7}{100})^2$

$\Rightarrow$

$A=20500\times (\dfrac{107}{100})^2$

$\Rightarrow$

$A=20500\times (1.07)^2$

$\Rightarrow$

$A=20500\times 1.1449$

$\therefore$

$A=Rs.23470.$

A sum of Rs

$15,000$ is invested for

$3$ years at

$13$ % per annum compound interest. Calculate the approx interest for the second year.

0%
$2100$
0%
$2200$
0%
$2300$
0%
$2400$

Explanation

Interst for the first year

$=Rs \cfrac{15000\times 13\times 1}{100}$

$=Rs1950$

Amount after the first year

$=Rs15000+Rs1950$

$Rs16950$

Interest for the second year

$=Rs\cfrac{16950\times 13\times 1}{100}$

$=Rs2203.5$

$=Rs2200$ (approx)

A sum of Rs.

$15,000$ is invested for

$3$ years at

$13$ % per annum compound interest. Calculate the compound interest.

0%
$6500.435$
0%
$6689.245$
0%
$6643.455$
0%
$6276.585$

Explanation

We have,

$P=Rs.\ 15000$

$T=3\ years$

$R=13\%$

$C.I=?$

We know that

$A=P\left(1+\dfrac{R}{100}\right)^T$

$A=15000\left(1+\dfrac{13}{100}\right)^3$

$A=15000\left(\dfrac{113}{100}\right)^3$

$A=15000\left(\dfrac{113\times 113\times 113}{100\times 100\times 100}\right)$

$A=15\left(\dfrac{113\times 113\times 113}{1000}\right)$

$A=Rs.\ 21,643.455$

So, the compound interest

$=21.643.455-15000=Rs.\ 6643.455$

Raman borrowed Rs.

$1,20,000$ for

$4$ years at

$8$ % per year compound interest. Calculate the final amount at the end of four years.

0%
$1,63,250$
0%
$1,53,250$
0%
$1,63,700$
0%
$1,66,250$

Explanation

We have,

$P=Rs.\ 120, 000$

$T=4\ years$

$R=8\%$

$A=?$

We know that

$A=P\left(1+\dfrac{R}{100}\right)^T$

So,

$A=120000\left(1+\dfrac{8}{100}\right)^4$

$A=120000\left(\dfrac{108}{100}\right)^4$

$A=120000\left(\dfrac{108\times 108\times 108\times 108}{100\times 100\times 100\times 100}\right)$

$A=12\left(\dfrac{11664\times 11664}{10000}\right)$

$A=Rs.\ 163258.675\approx Rs.\ 163250$

Hence, this is the answer.

Find the compound interest on Rs.

$2,000$ for

$3$ years, compounded annually at

$12\%$ per annum.

0%
$764$
0%
$810$
0%
$820$
0%
$850$

Explanation

Given:

$P=Rs\ 2000$

$T=3$ years

$R=12\%$ p.a.

So, Interst for the first year

$=\cfrac{2000\times 12\times 1}{100}$

$=Rs\ 240$

Amount after the first year

$=P+$ Interest for the first year

$=Rs.\ 2000+Rs.\ 240=Rs.\ 2240$

Interst for the second year

$=\cfrac{2240\times 12\times 1}{100}$

$=Rs.\ 268.8$

Hence, the amount after the second year

$=Rs.\ 2240+Rs.\ 268.8=Rs.\ 2508.8$

Interst for the third year

$=\cfrac{2508.8\times 12\times 1}{100}$

$=Rs.\ 301.056$

Amount after the third year

$=Rs.\ 2508.8+Rs.\ 301.056=Rs.\ 2809.856$

Compound interest

$=$ Final amount

$-$ original amount

$=Rs.\ 2809.856-Rs.\ 2000$

$=Rs.\ 809.856$

$\approx Rs.\ 810$

The discount is always on the _________.

0%
Marked Price
0%
Cost Price
0%
Selling Price
0%
Interest

Say true or false:

The service tax is an indirect tax.

0%
True
0%
False

Direct tax is:

0%
service tax
0%
entertainment tax
0%
revenue stamp duty
0%
property tax

The number of items sold by Company C in the year 2011 is

$9.6$ , what percent of the number of items produced by it in that year?

0%
$56$
0%
$64$
0%
$72$
0%
$79$

Explanation

Required percentage

$=\cfrac { \text{Items sold by C in 2011} }{ \text{Items produced by C in 2011}} \times 100$

$=\cfrac { 9.6 }{ 15 } \times 100=64$ %

A particular sum was divided among A, B and C in the ratio

$2:6:7$ respectively. If the amount received by A was Rs.

$4,908$ , what was the difference between the amounts received by B and C?

0%
Rs. $2,454$
0%
Rs. $3,494$
0%
Rs. $2,135$
0%
Rs. $2481$
0%
None of these$$

Explanation

Amount received by A

$=$ Rs.

$4908$
Amount received by B

$=\displaystyle\frac{4908}{2}\times 6=$ Rs.

$14724$
Amount received by C

$=\displaystyle\frac{4908}{2}\times 7=$ Rs.

$17178$
Required difference

$=17178-14724$

$=$ Rs.

$2454$ .

CBSE Questions for Class 8 Maths Comparing Quantities Quiz 8 - MCQExams.com

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Practice Class 8 Maths Quiz Questions and Answers

CBSE Questions for Class 8 Maths Comparing Quantities Quiz 8 - MCQExams.com

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Practice Class 8 Maths Quiz Questions and Answers

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