Explanation
Prime factorising 11979, we get,
11979=3×3×11×11×11
=32×113.
We know, a perfect cube has multiples of 3 as powers of prime factors.
Here, number of 3's is 2 and number of 11's is 3.
So we need to multiply another 3 to the factorization to make 11979 a perfect cube.
Hence, the smallest number by which 11979 must be multiplied to obtain a perfect cube is 3.
Hence, option D is correct.
On prime factorisation of the numbers individually, we get,
64=2×2×2_×2×2×2_ =23×23=43.
729=3×3×3_×3×3×3_ =33×33=93.
Therefore,
3√64×729 =3√43×93 =4×9=36.
Hence, option C is correct.
Given, to find 3√12167×1728.
Prime factorising, we get,
12167=23×23×23=233
and 1728 =2×2×2×2×2×2×3×3×3=23×23×33.
Then,
3√12167×1728
=3√233×3√23×23×33.
=23×2×2×3
=276.
Hence, option A is correct.
216=2×2×2_×3×3×3_=23×33=63.
2197=13×13×13_=133.
3√2162197=3√2163√2197 =3√633√133 =613.
Thus, option C is correct.
Given, the number is 388.
Here, the units digit is 8.
We know, the cube of 8, i.e. 83=512, whose units place is 2.
Therefore, the units digit of the cube of 388 is 2.
Given, the number is 109.
Here, the units digit is 9.
We know, the cube of 9, i.e. 93=729, whose units place is 9.
Therefore, the units digit of the cube of 109 is 9.
A) 64=2×2×2_×2×2×2_=43.
B) 729=3×3×3_×3×3×3_=33×33=93.
C) 243=3×3×3_×3×3=35.
D) 81=3×3×3_×3=34.
Given, the number is 77774.
Here, the units digit is 4.
We know, the cube of 4, i.e. 43=64, whose units place is 4.
Therefore, the units digit of the cube of 77774 is 4.
On prime factorising, we get,
274625000=(5×5×5)×(5×5×5)×(2×2×2)×(13×13×13)
=53×53×23×133.
Then, cube root of 274625000 is:
3√274625000=3√53×53×23×133=5×5×2×13=650.
Therefore, option A is correct.
614125=5×5×5×17×17×17
=53×173.
Then, cube root of 614125 is:
3√614125=3√53×173=5×17=85.
Therefore, option C is correct.
571787=83×83×83_ =833.
Then, −571787 =(−83)3.
Therefore, cube root of −571787 is:
3√−571787=3√(−83)3=−83.
Therefore, option B is correct.
175616=8×8×8×7×7×7
=83×73.
Then, cube root of 175616 is:
3√175616=3√83×73=8×7×=56.
On prime factorizing, we get,
592704=2×2×2×2×2×2×3×3×3×7×7×7
=23×23×33×73=843.
Thus, cube root of 592704 is:
3√592704=3√843 =84.
250047 =3×3×3_×3×3×3_×7×7×7_
=33×33×73=633.
Then, cube root of 250047 is:
3√250047=3√633=63.
226981=61×61×61_ =613.
Then, −226981 =(−61)3.
Therefore, value of 3√−226981 is:
3√−226981=3√(−61)3=−61.
438976 =2×2×2_×2×2×2_×19×19×19_
=23×23×193=763.
Then, cube root of 438976 is:
3√438976=3√763=76.
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