MCQ Questions for Class 8 Maths Factorisation Quiz 4

Factorise:

$x^3 -3x^2+x-3$

0%
$(x^2 + 7)(x-3)$
0%
$(x^2 + 1)(x-3)$
0%
$(x^2 - 1)(x-2)$
0%
$(x^2 + 7)(x-2)$

Explanation

$x^3 -3x^2+x-3$

$=x^2(x-3)+1(x-3)$

$=(x^2 + 1)(x-3)$

Factorise:

$ab^2 + (a-1)b -1$

0%
$(b+ 1) (a-1)$
0%
$(b+ 1) (b-1)$
0%
$(b+ 1) (ab-1)$
0%
$(b- 1) (ab-1)$

Explanation

$ab^2 + (a-1)b -1$

$=ab^2+ab-b-1$

$=ab(b+1)-1(b+1)$

$=(b+ 1) (ab-1)$

Factorise:

$9x^3-6x^2+ 12x$

0%
$3x (3x^2-2x + 4)$
0%
$x (3x^2-2x + 4)$
0%
$x (3x^2-2x - 4)$
0%
$3x (3x^2-x + 7)$

Explanation

factorising

$9x^3-6x^2+ 12x$
Take

$3x$ as common,

$=3x (3x^2-2x + 4)$

Factorise:

$12x + 15$

0%
$3(4x + 5)$
0%
$(4x + 5)$
0%
$3(4x - 5)$
0%
None of the Above

Explanation

$12x + 15$
Taking 3 as common,

$3(4x + 5)$
Answer

$3(4x + 5)$

Factorise:

$6a(a -2b) + 5b(a -2b)$

0%
$(a-b) (6a + 5b)$
0%
$(a-2b) (6a + 5b)$
0%
$(a-2b) (3a + 5b)$
0%
$(a-b) (3a + 5b)$

Explanation

$6a(a -2b) + 5b(a -2b)$
taking (a -2b) common,

$=(a-2b) (6a + 5b)$

Evaluate:

$\displaystyle \left( { 7a }^{ 2 }-5a \right) \div 5a$

0%
$\displaystyle 7a-1$
0%
$\displaystyle 7a-5$
0%
$\displaystyle \frac { 1 }{ 5 } \left( 7a-5 \right)$
0%
$\displaystyle \frac { 1 }{ 5 } \left( 7a-1 \right)$

Explanation

$\displaystyle \left( { 7a }^{ 2 }-5a \right) \div 5a=\frac { { 7a }^{ 2 }-5a }{ 5a }$

$\dfrac { a\left( 7a-5 \right) }{ 5a } =\dfrac { 1 }{ 5 } \left( 7a-5 \right)$

Evaluate:

$\displaystyle ( 6{ x }^{ 2 }-4x) \div 2x$

0%
$\displaystyle 2x-3$
0%
$\displaystyle 3x-2$
0%
$\displaystyle 3{ x }^{ 2 }-2$
0%
$\displaystyle 12x-8$

Explanation

$\displaystyle \left( 6{ x }^{ 2 }-4x \right) \div 2x=\frac { 6{ x }^{ 2 }-4x }{ 2x }$

$=\dfrac { 2x\left( 3x-2 \right) }{ 2x }$

$\displaystyle =3x-2$

Simplify:

$\displaystyle \left( 12a-36 \right) \div 6$

0%
$\displaystyle 2a+6$
0%
$\displaystyle a-3$
0%
$\displaystyle 2a-6$
0%
$\displaystyle a+3$

Explanation

$\displaystyle \left( 12a-36 \right) \div 6=\frac { 12a-36 }{ 6 } =\frac { 12\left( a-3 \right) }{ 6 }$

$\displaystyle =2\left( a-3 \right)$

$\displaystyle =2a-6$

Simplify:

$\displaystyle 9\left( { a }^{ 4 }{ b }^{ 6 }-{ a }^{ 6 }{ b }^{ 4 } \right) \div 3{ a }^{ 4 }{ b }^{ 4 }$

0%
$\displaystyle 3(b-a)$
0%
$\displaystyle 3(a-b)$
0%
$\displaystyle 3\left( { a }^{ 2 }-{ b }^{ 2 } \right)$
0%
$\displaystyle 3\left( { b }^{ 2 }-{ a }^{ 2 } \right)$

Explanation

$\displaystyle 9\left( { a }^{ 4 }{ b }^{ 6 }-{ a }^{ 6 }{ b }^{ 4 } \right) \div 3{ a }^{ 4 }{ b }^{ 4 }=\frac { 9\left( { a }^{ 4 }{ b }^{ 6 }-{ a }^{ 6 }{ b }^{ 4 } \right) }{ 3{ a }^{ 4 }{ b }^{ 4 } }$

$\displaystyle =\frac { 9{ a }^{ 4 }{ b }^{ 4 }\left( { b }^{ 2 }-{ a }^{ 2 } \right) }{ 3{ a }^{ 4 }{ b }^{ 4 } }$

$\displaystyle = 3\left( { b }^{ 2 }-{ a }^{ 2 } \right)$

Divide:

$\displaystyle \left( { x }^{ 8 }{ y }^{ 7 }{ z }^{ 6 }-{ z }^{ 6 }{ y }^{ 7 }{ x }^{ 8 } \right)$ by

$\displaystyle { y }^{ 7 }{ x }^{ 8 }{ z }^{ 6 }$

0%
$\displaystyle -1$
0%
$\displaystyle 1$
0%
$\displaystyle 0$
0%
$\dfrac 12$

Explanation

$\displaystyle \left( { x }^{ 8 }{ y }^{ 7 }{ z }^{ 6 }-{ z }^{ 6 }{ y }^{ 7 }{ x }^{ 8 } \right) \div { y }^{ 7 }{ x }^{ 8 }{ z }^{ 6 }$

$\displaystyle =\frac { { x }^{ 8 }{ y }^{ 7 }{ z }^{ 6 }-{ x }^{ 8 }{ y }^{ 7 }{ z }^{ 6 } }{ { x }^{ 8 }{ y }^{ 7 }{ z }^{ 6 } } =\frac { 0 }{ { x }^{ 8 }{ y }^{ 7 }{ z }^{ 6 } } =0$

Evaluate:

$\displaystyle \left( 4{ x }^{ 8 }-{ 5x }^{ 6 }+{ 6x }^{ 4 } \right) \div { x }^{ 4 }$

0%
$\displaystyle { 4x }^{ 4 }-{ 5x }^{ 10 }+6x$
0%
$\displaystyle { 4x }^{ 5 }-{ 5x }^{ 3 }+6x$
0%
$\displaystyle { 4x }^{ 3 }-5x+6$
0%
$\displaystyle { 4x }^{ 4 }-{ 5x }^{ 2 }+6$

Explanation

$\displaystyle \left( 4{ x }^{ 8 }-{ 5x }^{ 6 }+{ 6x }^{ 4 } \right) \div { x }^{ 4 }=\frac { 4{ x }^{ 8 }-{ 5x }^{ 6 }+{ 6x }^{ 4 } }{ { x }^{ 4 } }$

$\displaystyle =\frac { { x }^{ 4 }\left( { 4x }^{ 4 }-{ 5x }^{ 2 }+6 \right) }{ { x }^{ 4 } }$

$\displaystyle ={ 4x }^{ 4 }-{ 5x }^{ 2 }+6$

Simplify:

$\displaystyle \left( { a }^{ 2 }{ b }^{ 2 }{ c }^{ 3 }-{ a }^{ 2 }{ b }^{ 2 }{ c }^{ 3 }+{ a }^{ 2 }{ b }^{ 2 }{ c }^{ 3 } \right) \div { a }^{ 2 }{ b }^{ 2 }{ c }^{ 3 }$

0%
$\displaystyle 1$
0%
$\displaystyle -1$
0%
$\displaystyle 0$
0%
None of these

Explanation

$\displaystyle \left( { a }^{ 2 }{ b }^{ 2 }{ c }^{ 3 }-{ a }^{ 2 }{ b }^{ 2 }{ c }^{ 3 }+{ a }^{ 2 }{ b }^{ 2 }{ c }^{ 3 } \right) \div { a }^{ 2 }{ b }^{ 2 }{ c }^{ 3 }$

$\displaystyle =\frac { { a }^{ 2 }{ b }^{ 2 }{ c }^{ 3 }-{ a }^{ 2 }{ b }^{ 2 }{ c }^{ 3 }+{ a }^{ 2 }{ b }^{ 2 }{ c }^{ 3 } }{ { a }^{ 2 }{ b }^{ 2 }{ c }^{ 3 } }$

$= \dfrac {0 + a^2b^2c^3}{a^2b^2c^3}$

$\displaystyle =\frac { { a }^{ 2 }{ b }^{ 2 }{ c }^{ 3 } }{ { a }^{ 2 }{ b }^{ 2 }{ c }^{ 3 } } =1$

Divide:

$\displaystyle \left( -16{ x }^{ 6 }-24{ x }^{ 4 } \right)$ by

$\displaystyle \left( -{ 8x }^{ 3 } \right)$

0%
$\displaystyle { 2x }^{ 3 }+3x$
0%
$\displaystyle { 2x }^{ 2 }+3$
0%
$\displaystyle -{ 2x }^{ 3 }-3x$
0%
$\displaystyle -{ 2x }^{ 2 }-3$

Explanation

$\displaystyle \left( -16{ x }^{ 6 }-24{ x }^{ 4 } \right) \div \left( -{ 8x }^{ 3 } \right) =\frac { -16{ x }^{ 6 }-24{ x }^{ 4 } }{ -{ 8x }^{ 3 } }$

$\displaystyle =\frac { -8{ x }^{ 4 }\left( { 2x }^{ 2 }+3 \right) }{ { 8x }^{ 3 } }$

$\displaystyle =x\left( { 2x }^{ 2 }+3 \right)$

$\displaystyle = { 2x }^{ 3 }+3x$

Evaluate :

$\displaystyle 21{ x }^{ 3 }{ y }^{ 3 }+35{ x }^{ 4 }{ y }^{ 2 }-56{ x }^{ 2 }{ y }^{ 4 }\div -7{ x }^{ 2 }{ y }^{ 2 }$

0%
$\displaystyle -5{ x }^{ 2 }+3xy+8{ y }^{ 2 }$
0%
$\displaystyle 8{ y }^{ 2 }-3xy-5{ x }^{ 2 }$
0%
$\displaystyle 5{ x }^{ 2 }+3xy-8{ y }^{ 2 }$
0%
$\displaystyle 5{ x }^{ 2 }-3xy+8{ y }^{ 2 }$

Explanation

$\displaystyle 21{ x }^{ 3 }{ y }^{ 3 }+35{ x }^{ 4 }{ y }^{ 2 }-56{ x }^{ 2 }{ y }^{ 4 }\div -7{ x }^{ 2 }{ y }^{ 2 }$

$\displaystyle = \frac { 21{ x }^{ 3 }{ y }^{ 3 }+35{ x }^{ 4 }{ y }^{ 2 }-56{ x }^{ 2 }{ y }^{ 4 } }{ -7{ x }^{ 2 }{ y }^{ 2 } }$

$\displaystyle = \frac { 7{ x }^{ 2 }{ y }^{ 2 }\left( 3xy+5{ x }^{ 2 }-8{ y }^{ 2 } \right) }{ -7{ x }^{ 2 }{ y }^{ 2 } }$

$\displaystyle =-\left( 3xy+5{ x }^{ 2 }-8{ y }^{ 2 } \right)$

$\displaystyle = 8{ y }^{ 2 }-3xy-5{ x }^{ 2 }$

Factorisation of the expression

$\displaystyle -15x+5{ x }^{ 3 }$ gives result as

0%
$\displaystyle 5x( 3-{ x }^{ 2 })$
0%
$\displaystyle 5x( { x }^{ 2 }-3)$
0%
$\displaystyle -5x( { x }^{ 2 }-3 )$
0%
$\displaystyle x( { x }^{ 2 }-3)$

Explanation

$\displaystyle -15x+5{ x }^{ 3 }=\left( -5\times 3\times x \right) +\left( 5\times x\times x\times x \right)$

$\displaystyle = -5x( 3-{ x }^{ 2 })$

$\displaystyle = 5x ( { x }^{ 2 }-3)$

Divide:

$\displaystyle 8\left( { x }^{ 3 }{ y }^{ 2 }{ z }^{ 2 }+{ x }^{ 2 }{ y }^{ 3 }{ z }^{ 2 }+{ x }^{ 2 }{ y }^{ 2 }{ z }^{ 3 } \right) \div 2{ x }^{ 2 }{ y }^{ 2 }{ z }^{ 2 }$

0%
$\displaystyle 4(y+z)$
0%
$\displaystyle 4(x)$
0%
$\displaystyle 4(x+y+z)$
0%
$\displaystyle 4x+4y+z$

Explanation

$\displaystyle 8\left( { x }^{ 3 }{ y }^{ 2 }{ z }^{ 2 }+{ x }^{ 2 }{ y }^{ 3 }{ z }^{ 2 }+{ x }^{ 2 }{ y }^{ 2 }{ z }^{ 3 } \right) \div 2{ x }^{ 2 }{ y }^{ 2 }{ z }^{ 2 }$

$\displaystyle =\frac { 8\left( { x }^{ 3 }{ y }^{ 2 }{ z }^{ 2 }+{ x }^{ 2 }{ y }^{ 3 }{ z }^{ 2 }+{ x }^{ 2 }{ y }^{ 2 }{ z }^{ 3 } \right) }{ 2{ x }^{ 2 }{ y }^{ 2 }{ z }^{ 2 } }$

$\displaystyle =\frac { 8{ x }^{ 2 }{ y }^{ 2 }{ z }^{ 2 }\left( x+y+z \right) }{ 2{ x }^{ 2 }{ y }^{ 2 }{ z }^{ 2 } }$

$\displaystyle =4\left( x+y+z \right)$

Find the value of

$\displaystyle \left( { 3x }^{ 3 }+{ 2x }^{ 2 }+x \right) \div 4x$

0%
$\displaystyle { 3x }^{ 2 }+2x+1$
0%
$\displaystyle \frac { 1 }{ 4 } \left( { 3x }^{ 2 }+2x+1 \right)$
0%
$\displaystyle { 3x }^{ 2 }+2x+\frac { 1 }{ 4 }$
0%
$\displaystyle 3x+2$

Explanation

$\displaystyle \left( { 3x }^{ 3 }+{ 2x }^{ 2 }+x \right) \div 4x=\frac { { 3x }^{ 3 }+{ 2x }^{ 2 }+x }{ 4x }$

$\displaystyle =\frac { x\left( { 3x }^{ 2 }+2x+1 \right) }{ 4x }$

$\displaystyle =\frac { 1 }{ 4 } \left( { 3x }^{ 2 }+2x+1 \right)$

Find the value of

$\displaystyle \left( { 7a }^{ 6 }-8{ a }^{ 5 }+9{ a }^{ 4 } \right) \div { a }^{ 3 }$

0%
$\displaystyle { 7a }^{ 3 }-{ 8a }^{ 2 }+9a$
0%
$\displaystyle { 7a }^{ 2 }-8a+9$
0%
$\displaystyle { 7a }^{ 4 }-{ 8a }^{ 2 }+9a$
0%
$\displaystyle { 7a }^{ 2 }-{ 8a }^{ 2 }+9a$

Explanation

$\displaystyle \left( { 7a }^{ 6 }-8{ a }^{ 5 }+9{ a }^{ 4 } \right) \div { a }^{ 3 }=\frac { { 7a }^{ 6 }-8{ a }^{ 5 }+9{ a }^{ 4 } }{ { a }^{ 3 } }$

$\displaystyle =\frac { { a }^{ 3 }\left( { 7a }^{ 3 }-{ 8a }^{ 2 }+9a \right) }{ { a }^{ 3 } }$

$\displaystyle = { 7a }^{ 3 }-{ 8a }^{ 2 }+9a$

Solve:

$\displaystyle 3{ x }^{ 3 }-15{ x }^{ 2 }+21x\div 3x$

0%
$\displaystyle x+5+7x$
0%
$\displaystyle { x }^{ 2 }+5x+7$
0%
$\displaystyle 3{ x }^{ 2 }-5x+7$
0%
$\displaystyle { x }^{ 2 }-5x+7$

Explanation

$\displaystyle 3{ x }^{ 3 }-15{ x }^{ 2 }+21x\div 3x$

$\displaystyle = \frac { 3{ x }^{ 3 } }{ 3x } -\frac { 15{ x }^{ 2 } }{ 3x } +\frac { 21x }{ 3x }$

$\displaystyle ={ x }^{ 2 }-5x+7$

Factorise :

$\displaystyle 40{ m }^{ 2 }n+50mn$

0%
$\displaystyle 10mn(4mn+5n)$
0%
$\displaystyle 10mn(2m+5)$
0%
$\displaystyle 10mn(2m+10)$
0%
$\displaystyle 10mn(4m+5)$

Explanation

$\displaystyle 40{ m }^{ 2 }n+50mn=\left( 2\times 5\times 2\times 2\times m\times m\times n \right) +\left( 2\times 5\times 5\times m\times n \right)$

$\displaystyle =10mn\left( 4m+5 \right)$

Simplify:

$\displaystyle \left( 16{ x }^{ 3 }{ y }^{ 2 }{ z }^{ 2 }+16{ x }^{ 2 }{ y }^{ 2 }{ z }^{ 3 }+16{ x }^{ 2 }{ y }^{ 3 }{ z }^{ 2 } \right) \div 8xyz$

0%
$\displaystyle 2\left( { x }^{ 2 }yz+xy{ z }^{ 2 }+x{ y }^{ 2 }z-xyz \right)$
0%
$\displaystyle \left( { x }^{ 2 }yz+xy{ z }^{ 2 }+x{ y }^{ 2 }z \right)$
0%
$\displaystyle 2{ x }^{ 2 }yz+2xy{ z }^{ 2 }+2x{ y }^{ 2 }z$
0%
$\displaystyle 2{ x }^{ 2 }{ y }^{ 2 }z+2x{ y }^{ 2 }{ z }^{ 2 }+2{ x }^{ 2 }y{ z }^{ 2 }-xyz$

Explanation

Given,

$\displaystyle \left( 16{ x }^{ 3 }{ y }^{ 2 }{ z }^{ 2 }+16{ x }^{ 2 }{ y }^{ 2 }{ z }^{ 3 }+16{ x }^{ 2 }{ y }^{ 3 }{ z }^{ 2 } \right) \div 8xyz$

$\displaystyle =\frac { 16{ x }^{ 3 }{ y }^{ 2 }{ z }^{ 2 }+16{ x }^{ 2 }{ y }^{ 2 }{ z }^{ 3 }+16{ x }^{ 2 }{ y }^{ 3 }{ z }^{ 2 } }{ 8xyz }$

$\displaystyle =\frac { 8xyz\left( 2{ x }^{ 2 }yz+2xy{ z }^{ 2 }+2x{ y }^{ 2 }z \right) }{ 8xyz }$

$\displaystyle =2{ x }^{ 2 }yz+2xy{ z }^{ 2 }+2x{ y }^{ 2 }z$

Factorisation of the expression

$\displaystyle 6p-24q$ results in :

0%
$\displaystyle 6(p-4q)$
0%
$\displaystyle 6(p-q)$
0%
$\displaystyle 6(1-4q)$
0%
$\displaystyle 3(2-12q)$

Explanation

$\displaystyle 6p-24q=\left( 6\times p \right) -\left( 24\times q \right)$

$=\left( 6\times p \right) -\left( 6\times 4\times q \right)$

$=6\left( p-4q \right)$

Which of the following statement is correct?

0%
$\displaystyle \left( { x }^{ 2 }-2xy \right) \div x=\left( x-2 y \right)$
0%
$\displaystyle \left( { x }^{ 2 }-2xy \right) \div x=\left( x-2 \right)$
0%
$\displaystyle \left( { x }^{ 2 }-2xy \right) \div x=\left( 2x-2y \right)$
0%
$\displaystyle \left( { x }^{ 2 }-2xy \right) \div x=\left( x-y \right)$

Explanation

$\displaystyle \left( { x }^{ 2 }-2xy \right) \div x$

$=\dfrac { { x }^{ 2 }-2xy }{ x } =\dfrac { x\left( x-2y \right) }{ x }$

$=\left( x-2y \right)$

$\displaystyle \therefore \left( { x }^{ 2 }-2xy \right) \div x=\left( x-2y \right)$ is a correct statement.

The value of

$(\displaystyle 9{ x }^{ 2 }+18x+27) \div 9$ is equal to

0%
$\displaystyle x+2$
0%
$\displaystyle { x }^{ 2 }+2x+2$
0%
$\displaystyle { x }^{ 2 }+2x+3$
0%
$\displaystyle { x }^{ 2 }+2x+1$

Explanation

$(\displaystyle 9{ x }^{ 2 }+18x+27) \div 9 =\frac { 9{ x }^{ 2 }+18x+27 }{ 9 }$

$\displaystyle =\frac { 9\left( { x }^{ 2 }+2x+3 \right) }{ 9 }$

$\displaystyle = { x }^{ 2 }+2x+3$

Which of the following is incorrect?

0%
$\displaystyle \left( 8{ x }^{ 2 }-8{ y }^{ 2 } \right) \div 8={ x }^{ 2 }-{ y }^{ 2 }$
0%
$\displaystyle \left( 8{ x }^{ 2 }{ y }^{ 2 }-16xy \right) \div 8xy=\left( xy-2 \right)$
0%
$\displaystyle \left( { a }^{ 2 }bc+a{ b }^{ 2 }c+ab{ c }^{ 2 } \right) \div abc=\left( a+b+c \right)$
0%
$\displaystyle \left( { a }^{ 2 }bc+a{ b }^{ 2 }c+ab{ c }^{ 2 }+abc \right) \div abc=\left( a+b+c \right)$

Explanation

$\displaystyle \left( { a }^{ 2 }bc+a{ b }^{ 2 }c+ab{ c }^{ 2 }+abc \right) \div abc=\frac { { a }^{ 2 }bc+a{ b }^{ 2 }c+ab{ c }^{ 2 }+abc }{ abc }$

$\displaystyle =\frac { abc\left( a+b+c+1 \right) }{ abc } =a+b+c+1$

$\displaystyle \therefore \left( { a }^{ 2 }bc+a{ b }^{ 2 }c+ab{ c }^{ 2 }+abc \right) \div abc$ is an incorrect statement.

Which of the following statements is correct?

0%
$\displaystyle \left( 7{ x }^{ 2 }-7 \right) \div 7={ x }^{ 2 }-7$
0%
$\displaystyle \left( 5{ x }^{ 2 }+10 \right) \div 5={ x }^{ 2 }+10$
0%
$\displaystyle \left( 4{ x }^{ 2 }+12 \right) \div 2={ x }^{ 2 }+6$
0%
$\displaystyle \left( 6{ x }^{ 2 }+12 \right) \div 6={ x }^{ 2 }+2$

Explanation

$\displaystyle \left( 6{ x }^{ 2 }+12 \right) \div 6=\frac { 6{ x }^{ 2 }+12 }{ 6 }$

$=\dfrac { 6\left( { x }^{ 2 }+2 \right) }{ 6 } ={ x }^{ 2 }+2$

$\displaystyle \therefore \left( 6{ x }^{ 2 }+12 \right) \div 6$ is a correct statement.

Factorise:

$\displaystyle -6{ a }^{ 2 }+6cb-6ca$

0%
$\displaystyle -6\left( { a }^{ 2 }+cb-ca \right)$
0%
$\displaystyle 6\left( { a }^{ 2 }-cb+ca \right)$
0%
$\displaystyle 6\left( { a }^{ 2 }+cb+ca \right)$
0%
$\displaystyle -6\left( { a }^{ 2 }-cb+ca \right)$

Explanation

$-6{ a }^{ 2 }+6cb-6ca=\left( -6\times a\times a \right) +\left( 6\times c\times b \right) -\left( 6\times c\times a \right)$

$\displaystyle =-6( { a }^{ 2 }-cb+ca)$

Factorise:

$\displaystyle 13{ x }^{ 2 }y-65x{ y }^{ 2 }$

0%
$\displaystyle xy(x-y)$
0%
$\displaystyle 65xy(x-y)$
0%
$\displaystyle 13xy(x-5y)$
0%
$\displaystyle 13xy(x-y)$

Explanation

$\displaystyle 13{ x }^{ 2 }y-65x{ y }^{ 2 }=\left( 13\times x\times x\times y \right) -\left( 13\times y\times x\times y\times y \right) \\$

$\displaystyle =13xy\left( x-5y \right)$

Factorise:

$\displaystyle 5xy+15y$

0%
$\displaystyle 5y(x+1)$
0%
$\displaystyle 5y(x+3)$
0%
$\displaystyle 5y(x+y)$
0%
$\displaystyle 5y(x+5)$

Explanation

$\displaystyle 5xy+15y=\left( 5\times x\times y \right) +\left( 5\times 3\times y \right)$

$\displaystyle =5y\left( x+3 \right)$

Factorisation of the expression :

$\displaystyle -2{ x }^{ 2 }{ y }^{ 3 }+6{ x }^{ 3 }{ y }^{ 2 }-8{ x }^{ 2 }{ y }^{ 2 }$ results in :

0%
$\displaystyle -2{ x }^{ 2 }{ y }^{ 2 }\left( -y-3x-4 \right)$
0%
$-\displaystyle 2{ x }^{ 2 }{ y }^{ 2 }\left( y-3x+4 \right)$
0%
$\displaystyle 2{ x }^{ 2 }{ y }^{ 2 }\left( 3x+y-4 \right)$
0%
$\displaystyle 2{ x }^{ 2 }{ y }^{ 2 }\left( 3x-y+4 \right)$

Explanation

$\displaystyle -2{ x }^{ 2 }{ y }^{ 3 }+6{ x }^{ 3 }{ y }^{ 2 }-8{ x }^{ 2 }{ y }^{ 2 }$

$\displaystyle =\left[ (-2)\times { x }^{ 2 }\times { y }^{ 2 }\times y \right] +\left[ (-2) \times (-3)\times { x }^{ 2 }\times x\times { y }^{ 2 } \right] +\left[(-2) \times 4 \times { x }^{ 2 }\times { y }^{ 2 }\right]$

$\displaystyle =-2{ x }^{ 2 }{ y }^{ 2 }\left( y-3x+4 \right)$

$\displaystyle =-2{ x }^{ 2 }{ y }^{ 2 }\left( y-3x-4 \right)$

CBSE Questions for Class 8 Maths Factorisation Quiz 4 - MCQExams.com

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Practice Class 8 Maths Quiz Questions and Answers

CBSE Questions for Class 8 Maths Factorisation Quiz 4 - MCQExams.com

0:0:1

Practice Class 8 Maths Quiz Questions and Answers

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