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CBSE Questions for Class 8 Maths Factorisation Quiz 6 - MCQExams.com
CBSE
Class 8 Maths
Factorisation
Quiz 6
State whether the statement is true (T) or false (F).
Factorized form of $$p^{2} + 30p + 216$$ is $$(p + 18) (p - 12)$$.
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True
0%
False
Explanation
Factorizingthe given expression by splitting the middle term,
$$p^{2} + 30p + 216$$
$$= p^{2} + 18p + 12p + 216$$
$$= p (p + 18) + 12 (p + 18)$$
$$ = (p + 12) (p + 18)$$
Clearly, $$(p + 12)(p + 18) \neq (p + 18)(p- 12)$$
Hence, the fiven statement is false.
Choose the correct answer
$$4a + 12b $$ is equal to
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$$4a$$
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$$12b$$
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$$4(a + 3b) $$
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$$3a$$
Which among the options is one of the factors of $$x^2+\frac{x}{6}-\frac{1}{6}$$
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3x + 1
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2x + 1
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$$x-\frac{1}{5}$$
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$$x-\frac{1}{2}$$
The value of $$(3x^{3} +9x^{2} + 27x) \div 3x$$ is
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$$ x^{2} +9 + 27x$$
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$$ 3x^{3} +3x^{2} + 27x$$
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$$3x^{3} +9x^{2} + 9$$
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$$x^{2} +3x +9$$
Explanation
$$\begin{aligned}{}\left( {3{x^3} + 9{x^2} + 27x} \right) \div 3x& = \frac{{3{x^3} + 9{x^2} + 27x}}{{3x}}\\ &= \frac{{3{x^3}}}{{3x}} + \frac{{9{x^2}}}{{3x}} + \frac{{27x}}{{3x}}\\ &= {x^2} + 3x + 9\end{aligned}$$
Hence, option $$D$$ is the correct answer.
The value of $$(2x^{2} + 4) \div 2$$ is
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$$ 2x^{2} +2 $$
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$$ x^{2}+2$$
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$$x^{2} +4$$
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$$ 2x^{2} +4$$
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