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CBSE Questions for Class 8 Maths Introduction To Graphs Quiz 3 - MCQExams.com
CBSE
Class 8 Maths
Introduction To Graphs
Quiz 3
If the total number of candidates appeared in 1996 and 1997 together was 47400, then the total number of candidates qualified in these two years together was?
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0%
34700
0%
32100
0%
31500
0%
Data inadequate
Explanation
The total number of candidates qualified in 1996 and 1997 together, cannot be determined until we know at least, the number of candidates appeared in any one of the two years 1996 or 1997 or the percentage of candidates qualified to appeared in 1996 and 1997 together.
Hence, the data is inadequate.
If the expenditure of Company $$Y$$ in $$1997$$ was $$Rs. 220$$ crores, what was its income in $$1997$$ ?
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0%
$$Rs. 312$$ crores
0%
$$Rs. 297$$ crores
0%
$$Rs. 283$$ crores
0%
$$Rs. 275$$ crores
Explanation
Profit percent of Company $$Y$$ in $$1997 = 35.$$
Let the income of Company $$Y$$ in $$1997$$ be $$Rs.
x$$
crores.
Then, $$\displaystyle 35=\frac { x-220 }{ 220 } \times 100\Rightarrow x=297$$
$$\displaystyle \therefore $$
Income of Company $$Y$$ in $$1997 = Rs. 297$$ crores.
In which of the following years, the difference between the productions of Companies X and Y was the maximum among the given years ?
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0%
1997
0%
1998
0%
1999
0%
2000
Explanation
The difference between the productions of Companies X and Y in various years are:
For 1997 (139000 - 119000) = 20000.
For 1998 (120000 - 99000) = 21000.
For 1999 (141000 - 100000) = 41000.
For 2000 (128000 - 78000) = 50000.
For 2001 (120000 - 107000) = 13000.
For 2002 (159000 - 148000) = 11000.
Clearly, maximum difference was in 2000.
The difference between the percentage of candidates qualified to appeared was maximum in which of the following pairs of years?
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0%
1994 and 1995
0%
1997 and 1998
0%
1998 and 1999
0%
1999 and 2000
Explanation
The differences between the percentages of candidates qualified to appeared for the give pairs of years are:
For 1994 and 1995 = 50 - 30 = 20.
For 1998 and 1999 = 80 - 80 = 0.
For 1994 and 1997 = 50 - 30 = 20.
For 1997 and 1998 = 80 - 50 = 30.
For 1999 and 2000 = 80 - 60 = 20.
Thus, the maximum difference is between the years 1997 and 1998.
What is the difference between the number of vehicles manufactured by Company Y in 2000 and 2001 ?
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0%
50000
0%
42000
0%
33000
0%
21000
Explanation
No. of vehicles manufactured by company Y in $$2000 = 128000$$
No. of vehicles manufactured by company Y in $$2001 = 107000$$
Required difference = (128000 - 107000) = 21000.
In which periodical exams there is a fall in percentage of marks as compared to the previous periodical exams ?
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0%
None
0%
June, 01
0%
Oct, 01
0%
Feb, 02
Explanation
As is clear from the graph, the total marks obtained in periodical exams, go on increasing. Since, the maximum marks for all the periodical exams are the same; it implies that the percentage of marks also goes on increasing.
Thus, in none of the periodical exams, there is a fall in percentage of marks compared to the previous exam.
If the profit in 1999 was Rs. 4 crores, what was the profit in 2000?
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0%
Rs. 4.2 crores
0%
Rs. 6.6 crores
0%
Rs. 6.8 crores
0%
Cannot be determined
Explanation
From the line-graph we obtain information about the percentage profit only. To find the profit in 2000 we must have the data for the income or expenditure in 2000.
Therefore, the profit for 2000 cannot be determined.
In which year is the expenditure minimum?
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0%
$$2000$$
0%
$$1997$$
0%
$$1996$$
0%
Cannot be determined
Explanation
The line graph gives the comparison of percent profit for different years but the comparison of the expenditures is not possible without more data.
Therefore, the year with minimum expenditure cannot be determined.
In how many of the given years were the exports more than the imports ?
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0%
1
0%
2
0%
3
0%
4
Explanation
The exports are more than the imports imply that the ratio of value of imports to exports is less than 1.
Now, this ratio is less than 1 in years 1995, 1996, 1997 and 2000.
Thus, there are four such years.
The number of students spent more than $$5$$ hours in watching TV , is _____ .
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0%
$$32$$
0%
$$8$$
0%
$$6$$
0%
$$14$$
Explanation
Hours of TV Watched
Number of Students
1-2
4
2-3
8
3-4
22
4-5
32
5-6
8
6-7
6
As clearly seen from the Graph and Corresponding Table,
Number of Students who spent more than $$5$$ Hours in watching T.V $$=$$ Number of Students lying in Category $$5$$-$$6$$ and $$6$$-$$7$$ $$=$$ $$8 + 6 = 14$$
________ lies on X-axis.
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0%
$$(5, 5)$$
0%
$$(0, 5)$$
0%
$$(0, -5)$$
0%
$$(5, 0)$$
Explanation
The point which lies an x-axis has its y-co-ordinate zero,
$$\therefore (5, 0)$$ lies on x-axis.
The cartesian system is named in honour of the Mathematician _____.
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0%
Leibnitz
0%
Euclid
0%
Laplace
0%
Rene Descartes
Explanation
The Cartesian coordinate system named in honor
of the French philosopher and mathematician
René Descartes
(1596—
1650).
A graph that displays data that changes continuously over periods of time is
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0%
Bar graph
0%
pie chart
0%
Histogram
0%
Line graph
Explanation
The correct answer is option (d). Line graph is a way to compare and represent the data. It displays the relation among two varying quantities.
State whether the following statements are True or False ?
A point lies on y - axis at a distance of $$2$$ units from the x- axis. Then its coordinate are $$\left(2,0\right)$$.
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0%
True
0%
False
Explanation
Any point which lies on the y - axis of the form $$\left(0,y \right)$$. Its coordinate are $$\left(2,0\right)$$. Hence, the given statement is False.
The coordinates of the origin are $$(0, 0)$$.
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0%
True
0%
False
Explanation
$$\textbf{Step 1:Find the co-ordinates of origin}$$
$$\text{Origin denoted by O is the centre of the co-ordinate system}$$
$$\text{Origin lies on the intersection of the x-axis and y-axis}$$
$$\therefore \text{At origin,x=0 and y=0}$$
$$\Rightarrow O=(0,0)$$.
$$\textbf{Therefore It is true that Co-ordinates of origin are(0,0)}$$
The point at which the two coordinate axes meet is called the
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0%
abscissa
0%
ordinate
0%
origin
0%
quadrant
Explanation
The points at which the two coordinate axes meets is called the origin.
Hence, $$\left(C\right)$$ is the correct answer.
To get an interest of Rs $$280$$ per year, how much money should be deposited?
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0%
$$2500$$
0%
$$3000$$
0%
$$3500$$
0%
$$400$$
Explanation
From the above graph, we can notice that, to get an interest of $$280$$ rupees per year, the money to be deposited is $$3500$$ rupees (approximately).
Use the graph to find the interest on Rs $$2500$$ for a year.
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0%
$$Rs. 100$$
0%
$$Rs.200$$
0%
$$Rs.300$$
0%
$$Rs.400$$
Explanation
From the above graph, we can observe that simple interest on $$Rs. 2500$$ rupees is $$Rs. 200$$ rupees which is marked as black point in the graph.
3 weeks
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0%
$$7cm$$
0%
$$8cm$$
0%
$$9cm$$
0%
$$10cm$$
Explanation
In the given graph, The dotted line represents the growth of the Plant $$A$$.
From the graph, we can observe that after $$3$$ weeks Plant $$A$$ has grown $$9\space cm$$
2 weeks
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0%
$$7cm$$
0%
$$8cm$$
0%
$$9cm$$
0%
$$10cm$$
Explanation
In the given graph, The dotted line represents the growth of the Plant $$A$$.
From the graph, we can observe that after $$2$$ weeks Plant $$A$$ has grown $$7\space cm$$
During which periods did the patient's temperature showed an upward trend?
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0%
9 a.m. to 10 a.m., 10 a.m. to 11 a.m., 2 p.m. to 3 p.m.
0%
9 a.m. to 10 a.m., 10.30 a.m. to 11.30 a.m., 2 p.m. to 3 p.m.
0%
9 a.m. to 10 a.m., 10 a.m. to 11.30 a.m., 1 p.m. to 2 p.m.
0%
9 a.m. to 10 a.m., 10 a.m. to 11 a.m., 1 p.m. to 2 p.m.
Explanation
Whenever there is an increase in the value of $$y - axis$$ as the time(on $$x - axis$$) passes by, there is an upward trend.
Thus, the patient shows an upward trend between $$9 am - 10 am$$, $$10 am - 11 am$$ and $$2 pm - 3 pm$$
Hence, option A is correct.
When was the patients temperature $$38.5$$ C?
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0%
$$9$$
0%
$$10$$
0%
$$11$$
0%
$$12$$
Explanation
From the given graph, we can observe that the patient temperature $$38.5^0C$$ was at $$12$$ noon
The patients temperature at 1 p.m. is:
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0%
$$37.0$$ C
0%
$$39.5$$ C
0%
$$36.5$$ C
0%
$$36.0$$ C
Explanation
From the given graph, we can observe that at $$1 p.m.$$ the patient temperature is $$36.5^0C$$
How much distance did the car cover during the period 7.30 a.m. to 8 a.m?
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0%
$$20$$ km
0%
$$40$$ km
0%
$$80$$ km
0%
$$100$$ km
Explanation
Using the information provided in the table, we can plot the graph shown above, taking the time on the $$x-axis$$ and the distance (in km) on the $$y-axis$$.
From the above graph, we can observe that at $$7:30\ am$$, the distance traveled is $$100\space km$$ and
at $$8:00\ am$$, the distance traveled is $$120 \space km$$.
Therefore, the distance covered during
the period
$$7:30$$ and $$8:00$$ is $$120-100=20\space km$$
Hence, option A is correct.
Draw a graph for the given information with suitable scales on the axes and answer the following question.
The time when the car had covered a distance of $$100$$ km since its start is:
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0%
$$7:00$$ am
0%
$$7:30$$ am
0%
$$ 8:00$$ am
0%
$$8:30$$ am
Draw a graph for the following:
Side of square (in cm)
$$2$$
$$3$$
$$3.5$$
$$5$$
$$6$$
Perimeter (in cm)
$$8$$
$$12$$
$$14$$
$$20$$
$$24$$
State the typre of graph.
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0%
Linear graph
0%
Bar graph
0%
Pie graph
0%
None of these
Explanation
From the above graph, we observe that the graph is linear graph.
During which week did Plant B grow least?
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0%
1st week
0%
2nd week
0%
3rd week
0%
None of these
Explanation
Growth of plant B during 1st week $$= 1 - 0 = 1.$$
Growth of plant B during 2nd week $$ = 7 - 1 = 6.$$
Growth of plant B during 3rd week $$= 10 - 7 = 3.$$
Plant B grew least in the first week.
What was the maximum forecast temperature during the week?
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0%
$$10$$
0%
$$20$$
0%
$$25$$
0%
$$35$$
How much did Plant B grow from the end of the $$2^{nd}$$ week to the end of the $$3^{rd}$$ week?
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0%
$$2 cm$$
0%
$$3 cm$$
0%
$$4 cm$$
0%
$$5 cm$$
Explanation
In the given graph, The straight line represents the growth of the Plant $$B$$.
From the graph, we can observe that after $$2$$ weeks Plant $$B$$ has grown $$7\space cm$$ and
after $$3$$ weeks Plant $$B$$ has grown $$10\space cm$$
Therefore, from the end of the $$2^{nd}$$ week to the end of the $$3^{rd}$$ week Plant $$B$$ has grown $$10-7=3\space cm$$
2 weeks
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0%
$$7cm$$
0%
$$8cm$$
0%
$$9cm$$
0%
$$10cm$$
Explanation
In the given graph, The straight line represents the growth of the Plant $$B$$.
From the graph, we can observe that after $$2$$ weeks Plant $$B$$ has grown $$7\space cm$$
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