If $$\alpha _1, \alpha _2, \alpha _3, \beta_1, \beta_2, \beta_3$$ are the values of $$n$$ for which $$\displaystyle \sum_{r=0}^{n-1} x^{2r}$$ is divisible by $$\displaystyle \sum_{r=0}^{n-1} x^{r}$$, then the triangle having vertices $$(\alpha _1, \beta_1), (\alpha _2, \beta_2)$$ and $$(\alpha _3, \beta_3)$$ can not be

a right angled isosceles triangle

MCQExams

CBSE Questions for Class 8 Maths Introduction To Graphs Quiz 7 - MCQExams.com

A point whose y-coordinate is zero and x-coordinate is

5

$5$ will lies on

The points

(3, - 4)

$(3, -4)$ and

(- 6, 2)

$(-6, 2)$ are the extremities of a diagonal of a parallelogram. If the third vertex is

(- 1, - 3)

$(-1, -3)$ , then the fourth vertex is

If

α_{1}, α_{2}, α_{3}, β_{1}, β_{2}, β_{3}

$\alpha _1, \alpha _2, \alpha _3, \beta_1, \beta_2, \beta_3$ are the values of

n

$n$ for which

\sum_{r = 0}^{n - 1} x^{2 r}

$\displaystyle \sum_{r=0}^{n-1} x^{2r}$ is divisible by

\sum_{r = 0}^{n - 1} x^{r}

$\displaystyle \sum_{r=0}^{n-1} x^{r}$ , then the triangle having vertices

(α_{1}, β_{1}), (α_{2}, β_{2})

$(\alpha _1, \beta_1), (\alpha _2, \beta_2)$ and

(α_{3}, β_{3})

$(\alpha _3, \beta_3)$ can not be

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