Explanation
$$(2t-7)+(\dfrac{3t-3}{2})=3\\(\dfrac{4t-14+3t-3}{2})=3\\7t-17=6\\\therefore 7t=6+17\\t=(\dfrac{23}{7})\\then x+2=(\dfrac{23}{7})\\\therefore x=(\dfrac{23}{7})-2\\=(\dfrac{23-14}{7})\\=(\dfrac{9}{7})$$
Find the two consecutive odd numbers whose sum is 76.
Given that,
The sum of two numbers is $$72$$.
One of the numbers is double that of the other.
To find out,
The numbers.
Let one of the numbers be $$x$$.
Hence, the other number will be $$2x$$.
The sum of the two numbers is $$72$$.
Hence, $$x+2x=72$$
$$3x=72\\$$
$$x=\dfrac{72}{3}$$
$$=24$$
Hence, $$2x=2\times 24$$
$$=48$$
Hence, the numbers are $$24$$ and $$48$$.
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