Explanation
$$ 5.6\dfrac{(x+3)}{0.7}=24 $$
$$ 5.6x+16.8=16.8 $$
$$ x=0 $$
We have,
$$\sqrt{1+\dfrac{x}{289}}=1\dfrac{1}{17}$$
$$\sqrt{\dfrac{289+x}{289}}=\dfrac{18}{17}$$
On squaring both sides, we get
$$ {{\left( \sqrt{\dfrac{289+x}{289}} \right)}^{2}}={{\left( \dfrac{18}{17} \right)}^{2}} $$
$$ \dfrac{289+x}{289}=\dfrac{324}{289} $$
$$ 289+x=324 $$
$$ x=324-289 $$
$$ x=35 $$
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