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CBSE Questions for Class 8 Maths Linear Equations In One Variable Quiz 7 - MCQExams.com
CBSE
Class 8 Maths
Linear Equations In One Variable
Quiz 7
A daily wage worker was paid Rs.
1700
during a period of
30
days. During his period he was absent for
4
days and was fined Rs.
15
per day for absence. He was paid the full salary only for
18
days as he came late on the other days. Those who came late were given only half the salary for that day. What was the total salary paid per month to a worker who came on time every day and was never absent?
Report Question
0%
Rs.
2400
0%
Rs.
3000
0%
Rs.
2700
0%
Rs.
2250
Explanation
Let the salary of the worker per day be Rs.
x
.
Then,
18
×
x
+
8
×
x
2
−
4
×
15
=
1700
⇒
18
x
+
4
x
−
60
=
1700
⇒
22
x
=
1760
→
x
=
1760
22
=
80
∴
Total salary of a worker who came everyday on time for
30
days
=
30
×
Rs.
80
=
Rs.
2400
.
A grandfather is ten times older than his grand daughter. He is also
54
years older than her. Find their present ages.
Report Question
0%
The present age of granddaughter is
6
years and that of grandfather is
60
years.
0%
The present age of granddaughter is
8
years and that of grandfather is
80
years.
0%
The present age of granddaughter is
7
years and that of grandfather is
70
years.
0%
The present age of granddaughter is
9
years and that of grandfather is
90
years.
Explanation
Let the present age of granddaughter be
x
years.
So, the present age of grandfather is
10
x
years.
According to the given condition, we have
10
x
−
x
=
54
⇒
9
x
=
54
⇒
x
=
6
.... On dividing
9
from both the sides
Hence, the present age of granddaughter is
6
years and that of grandfather is
60
years.
If
26
−
(
7
m
−
9
)
=
−
2
m
, then
m
=
Report Question
0%
9
17
0%
35
9
0%
7
0%
9
Explanation
Given,
26
−
(
7
m
−
9
)
=
−
2
m
⇒
26
−
7
m
+
9
=
−
2
m
⇒
35
=
5
m
Divide
5
on both the sides, we get
35
5
=
5
m
5
∴
m
=
7
Solve
x
−
2
3
+
3
x
−
5
5
=
5
x
−
7
6
−
1
10
Report Question
0%
x
=
4
0%
x
=
8
0%
x
=
5
0%
x
=
12
Explanation
Given,
x
−
2
3
+
3
x
−
5
5
=
5
x
−
7
6
−
1
10
Multiplying both sides of the given equation by
30
....(LCM of
3
,
5
,
6
and
10
), we get
10
(
x
−
2
)
+
6
(
3
x
−
5
)
=
5
(
5
x
−
7
)
−
3
×
1
10
x
−
20
+
18
x
−
30
=
25
x
−
35
−
3
28
x
−
50
=
25
x
−
38
Transposing the terms, we get
28
x
−
25
x
=
50
−
38
3
x
=
12
Dividing both sides by
3
, we get
x
=
4
The ages of Rahul and Haroon are in the ratio
5
:
7
. Four years later, the sum of their ages will be
56
years. What are their present ages?
Report Question
0%
Rahul's age
=
10
years and Haroon's age
=
17
years
0%
Rahul's age
=
25
years and Haroon's age
=
42
years
0%
Rahul's age
=
28
years and Haroon's age
=
50
years
0%
Rahul's age
=
20
years and Haroon's age
=
28
years
Explanation
Let the common ratio between Rahul's age and Haroon's age be
x
.
Therefore, age of Rahul and Haroon will be
5
x
and
7
x
years respectively.
After
4
years, their ages will be
(
5
x
+
4
)
and
(
7
x
+
4
)
rexpectively.
According to the given condition, we have
5
x
+
4
+
7
x
+
4
=
56
⇒
12
x
+
8
=
56
⇒
x
=
4
Therefore, present age of rahul is
5
x
=
5
×
4
=
20
years and present age of Haroon is
7
x
=
7
×
4
=
28
years.
3 years ago, the average age of a family of 5 members was 17 years. A baby having been born, the average age of the family is same today. The present age of the baby is
Report Question
0%
3 years
0%
2 years
0%
1
1
2
years
0%
1 years
Explanation
Total age of the family three years ago = 17 x 5 = 85 years.
Let the present age of the child be x years.
Present total age of the family = 85 + 5 x 3 + x = (100 + x) years.
Given
100
+
x
6
=
17
⇒
100
+
x
=
102
⇒
x
=
2
years
Solve the linear equation:
3
(
t
−
3
)
=
5
(
2
t
+
1
)
Report Question
0%
t
=
−
2
0%
t
=
1
0%
t
=
6
0%
t
=
−
9
Explanation
We have,
3
(
t
−
3
)
=
5
(
2
t
+
1
)
⇒
3
t
−
9
=
10
t
+
5
⇒
3
t
−
10
t
=
5
+
9
[Transposing 10t to LHS and -9 to RHS]
⇒
−
7
t
=
14
⇒
7
t
7
=
−
14
7
⇒
t
=
−
2
The organisers of an essay competition decide that a winner in the competition gets a prize of Rs.
100
and a participant who does not win gets a prize of Rs.
25
. The total prize money distributed is Rs.
3000
. Find the number of winners, if the total number of participants is
63
.
Report Question
0%
14
0%
16
0%
19
0%
12
Explanation
Let x be the number of the winners. So, the number of participants who does not win
(
63
−
x
)
.
Prize money given to
x
winners = Rs.
(
100
×
x
)
=
Rs.
100
x
and prize money given to
(
63
−
x
)
participants = Rs.
25
(
63
−
x
)
Given, total prize money distributed = Rs.
3000
∴
100
x
+
25
(
63
−
x
)
=
3000
⇒
4
x
+
(
63
−
x
)
=
120
...[On dividing both sides by 25]
⇒
3
x
+
63
=
120
⇒
3
x
=
120
−
63
...[Transposing 63 to RHS]
⇒
3
x
−
57
⇒
x
=
57
3
=
19
∴
The number of winners is
19
.
If a scooterist drives at the rate of
25
km/h
he reaches his destination
7
min
late and if he drives at the rate of
30
km/h
he reaches his destination
5
min
earlier. How far is his destination?
Report Question
0%
20
km
0%
25
km
0%
30
km
0%
32
km
Explanation
Let the distance be
x
km
far.
From the given information we can conclude that the difference between the time taken at the given two speeds is
12
min
.
Now, by using the relation between distance, time, and speed,
x
25
−
x
30
=
12
60
6
x
−
5
x
150
=
1
5
x
=
150
5
=
30
km
Hence, the desired destination is
30
km
far.
A grand father is ten times older than his grand daughter. He is also
54
years older than her. Find their present ages.
Report Question
0%
The present age of granddaughter is
5
years and that of grandfather is
50
years.
0%
The present age of granddaughter is
4
years and that of grandfather is
40
years.
0%
The present age of granddaughter is
7
years and that of grandfather is
70
years.
0%
The present age of granddaughter is
6
years and that of grandfather is
60
years.
Explanation
Let the present age of granddaughter be
x
years.
So, the present age of grandfather is
10
x
years.
According to the given condition, we have
10
x
−
x
=
54
⇒
9
x
=
54
⇒
x
=
6
....[On dividing both sides by
9
]
Hence, the present age of granddaughter is
6
years and that of grandfather is
60
years.
The age of a girl in months is equal to the age of her grandmother in years. If the difference between their ages is
66
years, find their ages.
Report Question
0%
The age of girl is
5
years and that of grandmother is
60
years
0%
The age of girl is
6
years and that of grandmother is
72
years
0%
The age of girl is
7
years and that of grandmother is
84
years
0%
The age of girl is
8
years and that of grandmother is
96
years
Explanation
Let the age of grandmother is
12
x
years.
Then, the age of girl
=
12
x
12
=
x
years
According to the given condition,
12
x
−
x
=
66
⇒
11
x
=
66
⇒
x
=
6
Therefore, the age of girl
=
6
years and that of grandmother
=
12
×
6
=
72
years.
Length of a rectangle is
8
m less than twice its breadth. If the perimeter of the rectangle is
56
m. Find its length and breadth.
Report Question
0%
Length
=
1
6m and breadth
=
12
m
0%
Length
=
13
m and breadth
=
15
m
0%
Length
=
14
m and breadth
=
17
m
0%
Length
=
18
m and breadth
=
21
m
Explanation
Let the breadth of the rectangle be
x
m. Then,
length of the rectangle
=
(
2
x
−
8
)
m
Given, perimeter
=
56
m
⟹
2
(
2
x
−
8
+
x
)
=
56
⟹
2
(
3
x
−
8
)
=
56
⟹
6
x
−
16
=
56
⟹
6
x
=
56
+
16
[
T
r
a
n
s
p
o
s
i
n
g
−
16
t
o
R
H
S
]
⟹
6
x
=
72
⟹
x
=
12
Therefore, breadth of the rectangle
=
12
m and length of the rectangle
=
2
×
12
−
8
=
16
m
70
coins of
10
paise and
50
paise are mixed in a purse. If the total value of the money in the purse is Rs.
19
, find the number of each type of coins in the purse.
Report Question
0%
Number of
10
paise coins are
60
Number of
50
paise coins are
20
0%
Number of
10
paise coins are
20
Number of
50
paise coins are
40
0%
Number of
10
paise coins are
40
Number of
50
paise coins are
30
0%
Number of
10
paise coins are
30
Number of
50
paise coins are
50
Explanation
Suppose the number of
10
paise coins
=
x
∴
the number of
50
paise coins
=
70
−
x
Now, value of
10
paise coins
=
Rs.
x
10
and value of
50
paise coins
=
Rs.
70
−
x
2
Total value of coins
=
x
10
+
70
−
x
2
∴
x
10
+
70
−
x
2
=
19
Multiplying both sides by
10
, (LCM of
10
,
2
=
10
), we get
x
+
5
(
70
−
x
)
=
19
×
10
x
+
350
−
5
x
=
190
−
4
x
=
−
160
−
4
x
−
4
=
−
160
−
4
∴
x
=
40
∴
number of
10
paise coins
=
40
Number of
50
paise coins
=
70
−
40
=
30
.
When
19
is subtracted from the product of
p
and
4
, the result is
17
.
Then, the value of
p
is
Report Question
0%
−
1
9
0%
1
9
0%
−
9
0%
9
Explanation
According to the question,
4
p
−
19
=
17
Adding
19
to both sides we get,
⟹
4
p
=
17
+
19
⟹
4
p
=
36
⟹
p
=
36
4
...
(Divide by
4
on both sides)
∴
p
=
9
So, option D is correct.
One of the two digits of a two digit number is three times the other digit. If you interchange the digits of this two digit number and add the resulting number to the original number, you get
88
. What is the original number?
Report Question
0%
88
0%
26
0%
62
0%
68
Explanation
Let the digit in units place be
x
.
Then, digit in ten's place
=
3
x
So, original number
=
10
(
3
x
)
+
x
=
31
x
On interchanging the digits, new number
=
10
x
+
3
x
=
13
x
According to the given condition,
31
x
+
13
x
=
88
⇒
44
x
=
88
⇒
x
=
2
So, the original number is
31
x
or
31
×
2
=
62
.
On the other hand, if we consider the digit in ten's place as
x
, then the digit in the unit's place will be
3
x
.
So, original number
=
10
(
x
)
+
3
x
=
13
x
On interchanging the digits, new number
=
10
(
3
x
)
+
x
=
31
x
According to the given condition,
13
x
+
31
x
=
88
⇒
44
x
=
88
⇒
x
=
2
So, the original number is
13
x
or
13
×
2
=
26
.
Here, both answers are correct, as
26
+
62
=
88
.
The difference between a number and two third of itself is
13
. Find the number.
Report Question
0%
31
0%
35
0%
39
0%
33
Explanation
Let the number be
x
.
According to the given condition,
x
−
2
3
x
=
13
⇒
3
x
−
2
x
3
=
13
....(By taking L.C.M.)
⇒
x
3
=
13
Multiply both sides by
3
3
×
x
3
=
13
×
3
⇒
x
=
39
Hence, the number is
39
.
The distance between two towns is
300
km. Car
A
and Car
B
starts simultaneously from these towns and move towards each other. The speed of Car
A
is more than that of Car
B
by
7
km/h. If the distance between the cars after two hours is
34
km. Find the speed of both cars.
Report Question
0%
Speed of car
B
is
63
km/h and speed of car
A
is
70
km/h
0%
Speed of car
B
is
70
km/h and speed of car
A
is
75
km/h
0%
Speed of car
B
is
50
km/h and speed of car
A
is
65
km/h
0%
Speed of car
B
is
72
km/h and speed of car
A
is
80
km/h
Explanation
Let the speed of car
B
be
x
km/h.
Then, speed of car
A
=
(
x
+
7
)
km/h
Now, distance covered by car
B
in
2
hours
=
2
x
km and
Distance covered by car
A
in
2
hours
=
2
(
x
+
7
)
km
Given,
distance between the cars after two hours is
34
km and distance between both the towns is
300
km.
So, distance covered by both the cars in two hours moving in opposite direction
=
300
−
34
=
266
km
⇒
2
(
x
+
7
)
+
2
x
=
266
⇒
2
x
+
14
+
2
x
=
266
⇒
4
x
=
252
⇒
x
=
63
km/h
Therefore, speed of car
B
=
63
km/h and speed of car
A
=
63
+
7
=
70
km/h.
The digit in the units place of a
2
digit number is
4
times the digit in the tens place. The number obtained by reversing the digits exceeds the given number by
54
. Find the given number.
Report Question
0%
28
0%
32
0%
15
0%
25
Explanation
Let one's digit be
4
x
. Then, ten's digit
=
x
.
Number
=
10
x
+
4
x
=
14
x
....(1)
Number obtained by reversing the digits
=
40
x
+
x
=
41
x
According to the given condition,
41
x
−
14
x
=
54
27
x
=
54
x
=
2
Putting the value of
x
in (1) , we get
Number
=
14
×
2
=
28
Hence,
28
is the required number.
The difference of two numbers is
72
and the quotient obtained by dividing the one by the other is
3
. Find the numbers.
Report Question
0%
60
and
132
0%
42
and
114
0%
36
and
108
0%
30
and
102
Explanation
Let one number be
x
.
According to given condition, second number
=
3
x
Given, difference of two numbers
=
72
⇒
3
x
−
x
=
72
⇒
2
x
=
72
⇒
x
=
36
So, one number
=
36
and other number
=
3
×
36
=
108
The sum of three consecutive odd numbers is
63
. Find them.
Report Question
0%
19
,
21
,
23
0%
21
,
23
,
29
0%
19
,
21
,
27
0%
21
,
23
,
32
Explanation
Let the three consecutive odd numbers be
(
2
x
+
1
)
,
(
2
x
+
3
)
and
(
2
x
+
5
)
.
According to the given condition, we have
(
2
x
+
1
)
+
(
2
x
+
3
)
+
(
2
x
+
5
)
=
63
6
x
+
9
=
63
6
x
=
54
...[By transposing
9
to RHS]
x
=
9
So, three consecutive odd numbers are
(
2
×
9
+
1
)
,
(
2
×
9
+
3
)
and
(
2
×
9
+
5
)
i.e.,
19
,
21
and
23
.
Nineteen boys turn out for baseball. Of these 11 are wearing baseball shirts and 14 are wearing baseball pants. There are no boys without one or the other. The number of boys wearing full uniforms is ________.
Report Question
0%
3
0%
5
0%
6
0%
8
Explanation
Let the no. of boys wearing full uniform
be x
∴
∴
No. of boys wearing baseball shirts only
=
11
−
x
=11−x
and No. of boys wearing baseball pants only
=
14
−
x
=14−x
∴
11
−
x
+
14
−
x
+
x
=
19
∴11−x+14−x+x=19
or,
−
x
=
19
−
11
−
14
=
−
6
⟹
x
=
6
Sixteen years ago, Tanya's grandfather was
8
times older to her.
8
years from now h
e would be
3
times for her age. Eight years ago. what was the ratio of Tanya's age to that of her grandfather?
Report Question
0%
1
:
2
0%
1
:
5
0%
3
:
8
0%
None of these
Explanation
Let, Tanya age
16
years ago
=
x
Grandfather's age
16
years ago
=
8
x
.
8
years from now,
3
(
x
+
16
+
8
)
=
8
x
+
16
+
8
3
x
+
48
+
24
=
8
x
+
24
⇒
3
x
−
8
x
=
24
−
72
⇒
−
5
x
=
−
48
⇒
x
=
48
5
Also given,
8
years ago, ratio was
x
+
8
8
x
+
8
⇒
48
5
+
8
8
×
48
5
+
8
⇒
88
5
424
5
⇒
88
424
⇒
11
53
The ratio of Tanya's age to that of her grandfather is
11
:
53
.
A labourer was engaged for
30
days on the condition that he will be paid Rs.
35
for each day he works and will be fined Rs.
10
for each day he is absent. He earned Rs.
735
in total. Find how many days did he work?
Report Question
0%
21
0%
22
0%
25
0%
23
Explanation
Let the number of days he worked be x. Then
x
×
35
−
10
(
30
−
x
)
=
735
or
35
x
−
300
+
10
x
=
735
or
45
x
=
735
+
300
or
x
=
1035
45
=
23
∴
x
=
23
d
a
y
s
A piece of string is
80
cm long. It is cut into three pieces. The longest piece is
3
times as long as the middle sized piece and the shortest piece is
46
cm shorter than the longest piece. Find the length of the shortest piece.
Report Question
0%
14
cm
0%
10
cm
0%
8
cm
0%
18
cm
Explanation
Let the length of middle piece
=
x
Then length of longest piece
=
3
x
Then length of shortest piece
=
3
x
−
46
Thus,
x
+
3
x
+
3
x
−
46
=
80
⇒
7
x
=
126
⇒
x
=
18
Hence, shortest piece
=
18
×
3
−
46
=
54
−
46
=
8
cm
The sum of one half, one third and one fourth of a number exceed the number itself by
12
. The number is
Report Question
0%
72
0%
144
0%
180
0%
244
Explanation
Let the number be
x
⇒
[
x
2
+
x
3
+
x
4
]
−
x
=
12
⇒
6
x
+
4
x
+
3
x
−
12
x
12
=
12
⇒
x
=
144
The perimeter of an isosceles triangle is
3
9
4
cm. The base of an isosceles triangle is
3
2
cm. What is the length of either of the remaining equal sides?
Report Question
0%
15
4
cm
0%
15
8
cm
0%
8
15
cm
0%
4
15
cm
Explanation
Perimeter =
3
9
4
=
21
4
cm
Property of an isosceles triangle = two sides are equal
Perimeter of triangle = Sum of three sides
∴
21
4
=
a
+
a
+
3
2
⟹
2
a
=
21
4
−
3
2
⟹
2
a
=
21
−
6
4
∴
a
=
15
8
The sum of three consecutive multiples of
9
is
135
, then the multiples are
Report Question
0%
36
,
45
,
54
0%
45
,
54
,
63
0%
27
,
36
,
45
0%
None of the above.
Explanation
If
p
is a multiple of
9
, then next two multiples are
p
+
9
and
p
+
18
According to the question:
⟹
p
+
(
p
+
9
)
+
(
p
+
18
)
=
135
⟹
3
p
+
27
=
135
⟹
3
p
=
135
−
27
⟹
3
p
=
108
⟹
p
=
36
Thus,
p
=
36
p
+
9
=
45
p
+
18
=
54
Hence the required multiples are
36
,
45
,
54
In a division, a student took
63
as divisor instead of
36
. His answer was
24
. The correct answer is -
Report Question
0%
42
0%
32
0%
48
0%
28
0%
38
Explanation
From the given condition we have,
x
63
=
24
x
=
24
×
63
So, correct answer would be,
24
×
63
36
=
42
In a contest there were
10
problems. Each correct answer is eligible for
5
points while each incorrect answer is penalized with a deduction of
2
points. Venkat answered all the questions but got only
29
points. The number of correct answers of Venkat was
Report Question
0%
5
0%
2
0%
7
0%
4
Explanation
Let the correct answer of Venkat be x. Then
5
x
−
2
(
10
−
x
)
=
29
or
5
x
−
20
+
2
x
=
29
or
7
x
=
49
or
x
=
7
When a number is divided by
4
, the result is
−
9
. The number is
Report Question
0%
36
0%
−
36
0%
1
36
0%
−
1
36
Explanation
Let the required number be
x
According to the question,
x
4
=
−
9
⟹
x
=
−
9
×
4
...(Multiply both sides by
4
)
⟹
x
=
−
36
So, option B is correct.
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