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CBSE Questions for Class 8 Maths Squares And Square Roots Quiz 9 - MCQExams.com
CBSE
Class 8 Maths
Squares And Square Roots
Quiz 9
Write the correct answer from the given four options.
196 is the square of
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11
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12
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14
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16
Explanation
$$196$$ can be written as $$196 = 2 \times 2 \times 7 \times 7 = (2 \times 7)^2 = (14)^2 $$
Hence, C will be correct answer.
Write the correct answer from the given four options.
If m is the square of a natural number n, then n is
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The square of m
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Greater than m
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Equal to m
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$$\sqrt{m}$$
Explanation
Natural number = n
Square of n = $$(n)^2$$
Now, $$(n)^2 = m$$
$$n = \sqrt{m}$$
Write the correct answer from the given four options.
Which among $$43^2, 67^2, 52^2, 59^2$$ would end with digit 1?
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$$43^2$$
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$$67^2$$
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$$52^2$$
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$$59^2$$
Explanation
Unit digit of 59 = 9
Square of $$9 \times 9 = 81$$
A number ending in 9 will have the units place of its square as ____.
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3
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9
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1
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6
Explanation
If any number ends in $$9$$ then unit place of its square will be $$1$$ because
$$ 9 \times 9 = 81$$
Hence, C will be correct.
Write the correct answer from the given four options.
The value of $$\sqrt{248 + \sqrt{52 + \sqrt{144}}}$$ is
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14
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12
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16
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13
Explanation
$$\because \sqrt{144} = 12$$
$$\therefore \sqrt{248 + \sqrt{52+12}} = \sqrt{248 + \sqrt{64}}$$
$$\because \sqrt{64} = 8$$
$$\therefore \sqrt{248+8} = \sqrt{256} = 16$$
Which of the following will have $$4$$ at the units place?
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$$(14)^2$$
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$$(62)^2$$
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$$(27)^2$$
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$$(35)^2$$
Explanation
Unit digit of $$62 $$ is $$2$$ and the s
quare of $$2$$ is $$ 4$$.
State true or false:
Square root of a number x is denoted by $$\sqrt{x}$$.
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True
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False
Explanation
$$a^2=x$$
$$\therefore a=\sqrt{x}$$
State whether the statements are true (T) or false (F).
The square root of 1521 is 31.
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True
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False
Explanation
Square of 31 = $$(31)^2 = 31 \times 31 = 961$$
Some questions and their alternative answer are given. Select the correct alternative . Out of the following which is the pythagorean triplet?
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$$(1, 5 , 10 )$$
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$$( 3 , 4 , 5 )$$
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$$( 2, 2, 2)$$
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$$(5, 5, 2)$$
Explanation
(A) In the triplet ( 1, 5, 10 )
$$1^{2}=1,5^{2}=25,10^{2}=100 \ and \ 1+25 =26\neq 100$$
The square of largest number is not equal to the sum of the square of the other two numbers.
$$\therefore (1, 5, 10)$$ is not pythagorean triplet.
In the triplet (3 , 4 , 5)
$$3^{2}= 9 , 4^{2} = 16 , 5^{2} =25 \ and \ 9 + 16 = 25$$
The square of the largest number is not equal to the sum of the square of the other two numbers.
$$\therefore (2,2,2)$$ is not a pythgorean triplet.
In the triplet (5,5,2)
$$2^{2}=4,5^{2}=25,5^{2}=25 \ and \ 4 +25 = 29\neq 25$$
The square of the largest number is not equal to the sum of the square of the other two numbers.
$$\therefore (5,5,12)$$ is not a pythagprean triplet
Hence, the correct option is $$(3,4,5)$$
Choose the correct option:
The number of perfect squares from $$1$$ to $$500$$ is
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$$1$$
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$$16$$
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$$22$$
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$$25$$
Choose the correct option:
The last digit of a perfect square number can never be ___.
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$$1$$
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$$3$$
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$$5$$
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$$9$$
Explanation
As we know that, all the perfect square number ends with $$1,4,5,6,9$$ and $$0$$
So, the last digit of a perfect square can never be $$3.$$
Hence, $$Op-B$$ is correct.
Some question and their alternative answer are given. Select the correct alternative . Out of the dates given below which date constitutes a pythagorean triplet ?
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$$15/08/17$$
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$$16/08/16$$
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$$3/5/17$$
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$$4/9/15$$
Explanation
(A) In the triplet $$15 / 08 / 17$$
$$15^{2}=225,8^{2}=64,17^{2}=289 \ and \ 225+64=289$$ The square of the largest number is equal to the sum of the sum of square of the two numbers.
$$\therefore 15/08/17$$ is a pythsgorean triplet
(B) In the triplet $$16/08/16$$
$$ 16^{2}=256,8^{2}=64,16^{2}=256 \ and \ 256+64=320\neq 256$$
The square of the largest number is not equal to the sum of the squares of the other two numbers.
$$\therefore 16/08/16 $$ is not a pythagorean triplet
(C)In the triplet $$3/5/17$$
$$3^{2}=9,5^{2}= 25, 17^{2} = 289 \ and \ 9 + 25 = 34\neq 289$$
The square of the largest number is not equal to the sum of the squares of the other two numbers
$$\therefore 3/5/17$$ is not a pythagorean triplet
(D)In the triplet $$4/9/15$$
$$4^{2}=16,9^{2}=81,15^{2}=225 \ and \ 16+81=97\neq 225$$
The square of the largest number is not equal to the sum of the square of the other two numbers
$$\therefore 4/9/15$$ is not a pythagorea triplet.
Hence, the correct option is $$15/08/17$$
Out of the following which is a Pythagorean triplet?
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$$(5, 12, 14)$$
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$$(3, 4, 2)$$
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$$(8, 15, 17)$$
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$$(5, 5, 2)$$
The square root of 350 lies between which pair of numbers?
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18 and 19
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35 and 36
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3.5 and 3.6
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7 and 8
If $$\frac{18\times 72\times x}{48\times 315} = \sqrt{81}$$, then $$x = \underline{ }$$
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115
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150
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15
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105
Find the square root: $$\sqrt { 4562 }$$
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66.52
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67.52
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66.53
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67.54
$$n-$$ similar balls each of weight $$w$$ when weighed in pairs, the sum of the weights of all the possible pairs is $$120$$ and then they are weighed in triplets, the sum of the weights comes out to be $$480$$ for all possible triplets. Then $$n4$ is equal to
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$$5$$
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$$10$$
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$$15$$
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$$20$$
The square root of $$49+20\sqrt{6}$$ is
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$$3+3\sqrt{5}$$
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$$5+3\sqrt{6}$$
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$$5+2\sqrt{6}$$
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$$2+5\sqrt{6}$$
What is the square root of $$110.25$$?
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$$10.5$$
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$$11.5$$
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$$9.05$$
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None of these
Which of the following is the square root of $$7-4\sqrt { 3 } $$
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$$2-\sqrt { 3 } $$
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$$5-\sqrt { 3 } $$
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$$2-\sqrt { 5 } $$
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none of these
Which of the following is not perfect square number.
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89722
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298116
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225
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6400
Write the correct answer from the given four options.
If one member of a Pythagorean triplet is 2m, then the other two members are
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$$m, m^2 + 1$$
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$$m^2 + 1, m^2 - 1$$
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$$m^2, m^2 - 1$$
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$$m^2, m + 1$$
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