CBSE Multiple Choice Type Questions for 12th Class Maths PDF formatted study resources are available for free download. These Grade 12 Maths CBSE MCQ Mock Test helps you learn & practice the concepts in a fun learning way.
Here are the chapterwise CBSE MCQ Quiz Test Questions for Class 12th Maths in pdf format that helps you access & download so that you can practice online/offline easily.
Application Of Derivatives Quiz Question | Answer |
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The curve for which the ratio of the length of the segment by any tangent on the $$Y-$$axis to the length of the radius vector is constant $$(K)$$, is | $$(y+\sqrt {x^2 +y^2})x^{k-1}=c$$ |
The points on the curve $$9 y^{2} = x^{3}$$, where the normal to the curve makes equal intercepts with the axes are ........... | $$\left ( 4, \dfrac{-8}{3} \right )$$ |
The angle between the tangents at ant point P and the line joining P to the original, where P is a point on the curve in $$(x^{2}+y^{2})=c \tan ^{-1}\dfrac{y}{x},c$$ is a constnt, is | independent of x |
The slope of the tangent to the curve at a point $$(x,y) $$ on it is proportional to $$(x-2).$$ If the slope of the tangent to the curve at $$(10,-9)$$ on it is $$-3$$. The equation of the curves is . | $$y=\dfrac{-3}{16}(x-2)^2+3$$ |
The tangent at the point $$(2, -2)$$ to the curve, $$x^2y^2-2x=4(1-y)$$ does not pass through the point. | $$(-2, -7)$$ |
If the tangent to the conic, $$y - 6 = x^2$$ at (2, 10) touches the circle, $$x^2 + y^2 + 8x - 2y = k$$ (for some fixed k) at a point $$(\alpha, \beta)$$; then $$(\alpha, \beta)$$ is; | $$\displaystyle \left( -\frac{8}{17}, \frac{2}{17} \right)$$ |
Let b be a nonzero real number. Suppose $$f : R \rightarrow R$$ is a differentiable function such that $$f(0) = 1$$. If the derivative f' of f satisfies the equation $$f'(x) = \dfrac{f(x)}{b^2 + x^2}$$ for all $$x \in R$$, then which of the following statements is/are TRUE? |
$$f\left( x \right) f\left( -x \right) =1$$ for all $$x\in R$$ |
What is the $$x$$-coordinate of the point on the curve $$f(x) = \sqrt {x}(7x - 6)$$, where the tangent is parallel to $$x$$-axis? | $$\dfrac {2}{7}$$ |
Consider the following statements in respect of the function $$f(x) = x^{3} - 1, \quad x\epsilon [-1, 1]$$ I. $$f(x)$$ is increasing in $$[-1, 1]$$ II. $$f'(x)$$ has no root in $$(-1, 1)$$. Which of the statements given above is/ are correct? |
Only I |
If $$\dfrac{x^2}{f(4a)}=\dfrac{y^2}{f(a^2-5)}$$ respresents and ellipse with major axis as y-axis and $$f$$ is a decreasing function, then | $$a \in (-1, 5)$$ |
Application Of Integrals Quiz Question | Answer |
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Area of the region bounded by the curve $$( y - x ) ^ { 2 } = x ^ { 3 }$$ and the line $$x = 1$$ is | $$\frac {4} {3}$$ |
Area bounded by the curves $$y=\log _{ e }{ x } \quad$$ and $$y={ \left( \log _{ e }{ x } \right) }^{ 2 }$$ is ? |
$$e-2$$ |
Area enclosed by the curve $$y = f ( x )$$ defined parametrical as $$x = \frac { 1 - t ^ { 2 } } { 1 + t ^ { 2 } } , y = \frac { 2 t } { 1 + t ^ { 2 } }$$ | $$\pi$$ sq. units |
The area (in sq units) of the region bounded by the curve $$y=\sqrt { x } $$ and the lines $$y=0,y=x-2$$, is | $$\frac { 10 }{ 3 } $$ |
The area bounded by the curve y=$${ x }^{ 3 },$$ x-axis and two ordinates x=1 to x=2 equal to | 15/4 sq.unit |
Area enclosed by the graph of the function $$y=l{ n }^{ 2 }x-1$$ lying in the $${ 4 }^{ th }$$ quadrant is | $$\frac { 4 }{ e } $$ |
Area bounded by the curves $$y = \sin x ,$$ tangent drawn to it at $$x = 0$$ and the line $$x = \frac { \pi } { 2 }$$ is equal to | $$\frac { \pi ^ { 2 } - 2 } { 2 }$$ sq.units |
Area bounded by curves $$ x=\sqrt{y-1} $$ and y=x+1 is - |
$$ \frac{1}{6} s q \cdot u n i t $$ |
The area of the region bounded by the curves $$y = x^2$$ and $$y = |x|$$ is | $$\dfrac{1}{3}$$ |
The area enclosed by the line y = x + 1, X- axis and the lines x = -3 and x = 3 is | 10 |
Continuity And Differentiability Quiz Question | Answer |
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Let $$f\left( x \right)=x\left| x \right| ,g\left( x \right)=sinx$$ and $$h\left( x \right) =\left( gof \right) \left( x \right) .$$ Then | $$h'\left( x \right) $$ is not differentiable at x=0 |
If $$f(x)=0$$ for $$x<0$$ and $$f(x)$$ is differentiable at $$x=0$$, then for $$x\ge 0, f(x)$$ may be | $$-x^{3/2}$$ |
$$\frac { d }{ dx } (\sin ^{ -1 }{ \{ \frac { \sqrt { 1+x } +\sqrt { 1-x } }{ 2 } \} } )=$$ | $$\frac { -1 }{ 2\sqrt { 1-{ x }^{ 2 } } } $$ |
If $$\mathrm{f}(\mathrm{x})$$ is a differentiable function and $$\mathrm{g}(\mathrm{x})$$ is a double differentiable function such that $$|\mathrm{f}(\mathrm{x})|\leq 1$$ and $$\mathrm{f}'(\mathrm{x})=\mathrm{g}(\mathrm{x})$$. If $$\mathrm{f}^{2}(0)+\mathrm{g}^{2}(0)=9$$such that there exists some $$\mathrm{c}\in(-3, 3)$$ such that $$\mathrm{g}(\mathrm{c}).\ \mathrm{g}''(\mathrm{c})<0$$, True or false |
True |
Let $$f : R \rightarrow R$$ and $$g : R \rightarrow R$$ be functions satisfying $$f(x + y) = f(x) + f(y) + f(x)f(y)$$ and $$f(x) = xg(x)$$ for all $$x, y \in R$$. If $$\underset{x \rightarrow 0}{\lim} g(x) = 1$$, then which of the following statements is/are TRUE? | The derivative $${ f }^{ \prime }\left( 0 \right) $$ is equal to $$1$$ |
For the curve $$x = t^2 - 1, y = t^2 - t$$, tangent is parallel to $$x$$ - axis where, |
$$t=\dfrac{1}{2}$$ |
Let F(x) = $$\left( f\left( x \right) \right) ^{ 2 }+\left( f\left( x \right) \right) ^{ 2 },F\left( 0 \right) -6$$ where f(x) is a differential function such that $$\left| f\left( x \right) \right| \le 1\forall x\notin \left[ -1,1 \right] $$ then choose the correct statement (s) | For some $$c\in \left( -1,1 \right) $$, $$F'\left( c \right) \ge 6,F"\left( c \right) \le 0$$ |
If $$f(x)={ sin }^{ -1 }\left[ \dfrac { 2x }{ 1+{ x }^{ 2 } } \right] $$,then $$f(x)$$ is differentiable on | R-{-1,1} |
$$\displaystyle \frac{d}{dx}(\tan ^{-1}x)$$ | $$ \displaystyle \frac{1}{1+x^{2}}.$$ |
If $$\displaystyle x+y=x^{y}$$ then $$\displaystyle \frac{dy}{dx}\ equals-$$ | $$\displaystyle \frac{yx^{y-1}-1}{1-x^{y}\log x}$$ |
Determinants Quiz Question | Answer |
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If A is a singular matrix, then adj A is | singular |
If $$A = \left( \begin{array} { l l } { 1 } & { 2 } \\ { 3 } & { 5 } \end{array} \right), $$ then the value of the determinant $$\left| A ^ { 2009 } - 5 A ^ { 2008 } \right|$$ is | $$- 6$$ |
If $$A=\begin{bmatrix} -4 & -1 \\ 3 & 1 \end{bmatrix}$$ then the determinant of the matrix $$\left( {A}^{2016}-2{A}^{2015}-{A}^{2014} \right) $$ is | $$-2016$$ |
If $$A=A=\left[ \begin{matrix} a & 0 & 0 \\ 0 & a & 0 \\ 0 & 0 & a \end{matrix} \right]$$,then $$\left| A \right| \left| AdjA \right|$$ is equal to | $${a}^{9}$$ |
If $$A$$ is a square matrix $$(adj \,A)' - (adj \,A')$$ | $$2A$$ |
If adj B = A, |P| = |Q| = 1, then adj $$\left( { Q }^{ -1 }{ BP }^{ -1 } \right) $$ is | PAQ |
There are $$12$$ points in a plane. The number of the straight lines joining any two of them when $$3$$ of them are collinear is. | $$64$$ |
If $$A$$ is singular matrix, then $$A.(adj\,A)$$ is | $$singular$$ |
If $$A$$ is $$4\times 4$$ matrix and if $$\left| \left| A \right| adj\left( \left| A \right| A \right) \right| ={ \left| A \right| }^{ n }$$, then $$n$$ is | $$11$$ |
If $$A=\begin{bmatrix} 5a & -b \\ 3 & 2 \end{bmatrix}$$ and $$A(adj\, A)=A{A}^{T}$$ then $$5a+3b$$ is equal to | $$5$$ |
Differential Equations Quiz Question | Answer |
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The solution of $$\dfrac{dy}{dx}=2^{x-y}$$ is: | $$2^{x}-2^{y}=c$$ |
The solution of $$(x^{2}+x)\frac{dy}{dx}=1+2x$$ is: | $$e^{y}=c(x^{2}+x)$$ |
$$\displaystyle e^{x-y}dx+e^{^{y-x}}dy=0$$ Solve the differential equations. |
$$\displaystyle e^{2x}+e^{2y}=-k$$ |
The solution to the differential equation $$y\ln y \, +\, xy'\, =\, 0\,$$ where$$\, y(1)\, =\, e$$, is: | $$x(\ln y)\, =\, 1$$ |
$$x^{\frac{b-c}{bc}} . x^{\frac{c-a}{ca}} . x^{\frac{a-b}{ac}}=$$ |
1 |
The solution of $$x^{2} \cfrac{dy}{dx}=2$$ is |
$$y=-\cfrac{2}{x}+c$$ |
Which of the following differential equation is linear ? | $$(1+x)\dfrac{dy}{dx}-xy=1$$ |
Degree of $$\dfrac{d^{3}y}{dx^{3}}+2\left ( \dfrac{dy}{dx} \right )^{4}+\dfrac{dy}{dx}=\cos x $$ is | $$1$$ |
The solution of $$\dfrac{dy}{dx}=e^{logx}$$ is: | $$2y=x^{2}+c$$ |
Check whether the function is homogenous or not. If yes then find the degree of the function $$g(x)=4-x^2$$. |
Not homogenous |
Integrals Quiz Question | Answer |
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$$\int { { e }^{ x^{ 3 } }+{ x }^{ 2-1 }(3{ x }^{ 4 }+{ 2x }^{ 3 }+{ 2x }^{ 2 }\quad x=h(x)+c } $$ then the value of $$h(1)h(-1)$$. | 1 |
$$\displaystyle \int \frac { 1 - x ^ { 2 } } { \left( 1 + x ^ { 2 } \right) \sqrt { 1 + x ^ { 4 } } } d x$$ is equal to |
$$\frac { 1 } { \sqrt { 2 } } \sin ^ { - 1 } \left\{ \frac { \sqrt { 2 } x } { x ^ { 2 } + 1 } \right\} + c$$ |
Let $$ 1 _ { n } = \int _ { 0 } ^ { \frac { 1 } { 2 } } \frac { 1 } { \sqrt { 1 - x ^ { n } } } d x $$ where $$ n > 2 , $$ then |
$$ I _ { n } < \frac { \pi } { 6 } $$ |
If $${ I }_{ m }=\overset { e }{ \underset { 1 }{ \int } } (lnx)^{ m }dx,$$ where $$m\epsilon N,$$then $${ I }_{ 10 }+10{ I }_{ 9 }$$ is equal to- | e |
If for every integer n, $$\int _{ n }^{ n+1 }{ f(x)dx={ n }^{ 2 } } $$, then the value of $$\int _{ -2 }^{ 4 }{ f(x)dx } $$ is - | 16 |
$$\int _{ 0 }^{ 4036 }{ \dfrac { { 2 }^{ x } }{ { 2 }^{ x }+{ 1 }^{ 4036-x } } } dx=............$$ | 4035 |
If $${ I }_{ 1 }=\int _{ x }^{ 1 }{ \cfrac { 1 }{ 1+{ t }^{ 2 } } } dt$$ and $${ I }_{ 2 }=\int _{ 1 }^{ 1/x }{ \cfrac { 1 }{ 1+{ t }^{ 2 } } } dt$$ for x > 0, then | $${ I }_{ 1 }={ I }_{ 2 }$$ |
$$\frac { 1 }{ \pi } \int _{ -2 }^{ 2 }{ \frac { 1 }{ 4+{ x }^{ 2 } } dx= } $$ | $$\frac { 1 }{ 4 } $$ |
$$\displaystyle \int_{-1}^{1}\dfrac{x^4}{1+e^{x^7}}dx$$ is | $$1/5$$ |
Evaluate: $$\int { \sqrt { \dfrac { x }{ 4-{ x }^{ 3 } } } } dx$$ | $$2\sin ^{ -1 }{ \left( \dfrac { { x }^{ \dfrac { 3 }{ 2 } } }{ 2 } \right) +c } $$ |
Inverse Trigonometric Functions Quiz Question | Answer |
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$$if\quad x>0\quad then\quad { tanh }^{ -1 }\left( \frac { { x }^{ 2 }-1 }{ { x }^{ 2 }+1 } \right) $$ | $${ log }_{ e }x$$ |
If $$\cos^{-1}x-\cos^{-1}(\dfrac {y}{2})=\alpha$$ $$ax^{2}-4xy\cos \alpha +y^{2}=$$ | $$4\sin^{2}\alpha$$ |
$${\cot}^{-1}\left(\sqrt{\cos\alpha}\right) -{\tan}^{-1}\left(\sqrt{\cos\alpha}\right) =x$$, then $$\sin x$$ is equal to | $$\displaystyle {\tan}^{2}\frac{\alpha}{2}$$ |
$${ cos }^{ -1 }(\frac { x }{ 3 } )+{ cos }^{ -1 }(\frac { y }{ 2 } )=(\frac { \theta }{ 2 } )$$ , then the value of $${ 4x }^{ 2 }$$-12xy cos$$(\frac { \theta }{ 2 } )$$+$${ 9y }^{ 2 }$$ is equal to | $$18(1-cos\theta )$$ |
$$\cos ^{ -1 }{ \left\{ \dfrac { 1 }{ 2 } { x }^{ 2 }+\sqrt { { 1-x }^{ 2 } } .\sqrt { 1\dfrac { { x }^{ 2 } }{ 4 } } \right\} } =\cos ^{ -1 }{ \dfrac { x }{ 2 } } -\cos ^{ -1 }{ x } $$ holds for | $$0\le x\le 1$$ |
$$tan^{-1}y=tan^{-1}x+tan^{-1}(\frac{2x}{1-x^{2}})$$ where $$|x| < \frac{1}{\sqrt{3}}$$. Then a value of y is: | $$\dfrac{3x-x^{3}}{1-3x^{2}}$$ |
$$4\tan ^{ -1 }{ \frac { 1 }{ 5 } } -\tan ^{ -1 }{ \frac { 1 }{ 70 } } +\tan ^{ -1 }{ \frac { 1 }{ 99 } } =$$ | $$\pi $$ |
$$\cos ^{ -1 }{ \left( \cos { \dfrac { 7\pi }{ 6 } } \right) } $$ is equal to | $$\dfrac {5\pi}{6}$$ |
The value of $$\sin ^{ -1 }{ (\cos { (\cos ^{ -1 }{ (\cos { x } ) } +\sin ^{ -1 }{ (\sin { x } ) } ) } ) } ,\quad where\quad x\in (\frac { \pi }{ 2 } ,\pi )$$, is equal to | $$-\frac { \pi }{ 2 } $$ |
The value of $$\sin^{-1}(\sin 3)+\cos^{-1}(\cos 7)-\tan^{-1}(\tan 5)$$ is | $$\pi-1$$ |
Linear Programming Quiz Question | Answer |
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Solution of LPP to minimize z = 2x + 3y, such that $$x \geq 0, y \geq 0, 1 \leq x + 2y \leq 10 $$ is | $$x = 0, y = \dfrac{1}{2}$$ |
The point which provides the solution to the linear programming problem : Max P= 2x+3y subject to constraints :$$x\geq 0, y\geq 0,2x+2y\leq 9,2x+y\leq 7,x+2y\leq 8,$$ is | (1,3.5) |
Feasible region is the set of points which satisfy | all the given constraints |
If the corner points of the feasible solution are (0, 10), (2, 2) and (4, 0), then the point of minimum z = 3x + 2y is | (2, 2) |
Minimise $$Z=\sum _{ j=1 }^{ n }{ \sum _{ i=1 }^{ m }{ { c }_{ ij }.{ x }_{ ij } } } $$ Subject to $$\sum _{ i=1 }^{ m }{ { x }_{ ij } } ={ b }_{ j },j=1,2,......n$$ $$\sum _{ j=1 }^{ n }{ { x }_{ ij } } ={ b }_{ j },j=1,2,......,m$$ is a LPP with number of constraints |
$$m+n$$ |
The solution of the set of constraints of a linear programming problem is a convex (open or closed) is called ______ region. | feasible |
Solving an integer programming problem by rounding off answers obtained by solving it as a linear programming problem (using simplex), we find that | The value of the objective function for a maximization problem will likely be less than that for the simplex solution. |
If a = b then ax = ........... | bx |
The bar graph shows the grades obtained by a group of pupils in a test. If grade C is the passing mark, how many pupils passed the test? |
30 |
An iso-profit line represents | An infinite number of solutions all of which yield the same profit |
Matrices Quiz Question | Answer |
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If $$\displaystyle A=\left[ \begin{matrix} 3 & 1 \\ -1 & 2 \end{matrix} \right] $$ and $$\displaystyle I=\left[ \begin{matrix} 1 & 0 \\ 0 & 1 \end{matrix} \right] $$, then the correct statement is: | $$\displaystyle { A }^{ 2 }-5A+7I=O$$ |
If AB = AC then | B need not be equal to C |
If $$\mathrm{A}^{2}=\mathrm{A},\ \mathrm{B}^{2}=\mathrm{B},\ \mathrm{A}\mathrm{B}=\mathrm{B}\mathrm{A}=O$$ (Null Matrix), then $$(\mathrm{A}+\mathrm{B})^{2}=$$ |
$$\mathrm{A}+\mathrm{B}$$ |
$$I$$ $$A=\left[\begin{array}{ll} 0 & 1\\ 1 & 0 \end{array}\right]$$, $$A^{4}=$$ ($$I$$ is an identity matrix.) |
$$I$$ |
lf $$\mathrm{A}= \left[\begin{array}{lll} o & c & -b\\ -c & o & a\\ b & -a & o \end{array}\right]\mathrm{a}\mathrm{n}\mathrm{d}$$ $$ \mathrm{B}=\left[\begin{array}{lll} a^{2} & ab & ac\\ ab & b^{2} & bc\\ ac & bc & c^{2} \end{array}\right],$$ then $$\mathrm{A}\mathrm{B}=$$ |
$$\mathrm{O}$$ |
lIf $$\mathrm{A} =\left[\begin{array}{ll} a & 0\\ a & 0 \end{array}\right],\ \mathrm{B}=\left[\begin{array}{ll} 0 & 0\\ b & b \end{array}\right],$$ then $$\mathrm{A}\mathrm{B}=$$ |
$$O$$ |
If $$A=\left[\begin{array}{lll} 1 & -2 & 3\\ -4 & 2 & 5 \end{array}\right]$$ and $$B=\left[\begin{array}{ll} 2 & 3\\ 4 & 5\\ 2 & 1 \end{array}\right],$$ then |
$$\mathrm{A}\mathrm{B},\ \mathrm{B}\mathrm{A}$$ exist and are not equal |
$$A=\left[\begin{array}{lll} 0 & 1 & -2\\1 & 0 & 3\\2 &-3 & 0 \end{array}\right]$$ then $$\mathrm{A}+\mathrm{A}^{\mathrm{T}}=$$ |
$$\left[\begin{array}{lll} 0 & 2 & 0\\ 2 & 0 & 0\\ 0 & 0 & 0 \end{array}\right]$$ |
$$\left[\begin{array}{ll} x & 0\\ 0 & y \end{array}\right]\left[\begin{array}{ll} a & b\\ c & d \end{array}\right]=$$ |
$$\left[\begin{array}{ll} ax & b_{X}\\ yc & dy \end{array}\right]$$ |
If $$\mathrm{A}=\left[\begin{array}{lll} 1 & -3 & -4\\ -1 & 3 & 4\\ 1 & -3 & -4 \end{array}\right]$$, then $$\mathrm{A}^{2}=$$ |
Null matrix |
Probability Quiz Question | Answer |
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Three number are chosen at random without replacement from {1,2,3,...8}. The probability that their minimum is 3, given that their maximum is 6 is | $$\frac{3}{28}$$ |
Difference between sample space and subset of sample space is considered as | complementary events. |
If A and B are two events in a sample space S such that $$P\left ( A \right )\neq 0$$, then $$P\left ( \frac{B}{A} \right )= $$ | $$\frac{P\left ( A\cap B \right )}{P\left ( A \right )}$$ |
Let A and E be any two events with positive probabilities : Statement - 1 : $$P \left (\displaystyle \frac{E}{A} \right) \geq P \left (\displaystyle \frac{A}{E} \right ) P(E)$$ Statement - 2 : $$P \left (\displaystyle \frac{A}{E}\right ) \geq P(A\cap E)$$ |
Both the statement are true |
If $$\mathrm{C}$$ and $$\mathrm{D}$$ are two events such that $$\mathrm{C}\subset \mathrm{D}$$ and $$\mathrm{P}(\mathrm{D})\neq 0$$, then the correct statement among the following is |
$$P\left(\dfrac{C}{D}\right) \geq \mathrm{P}(\mathrm{C})$$ |
If $$A$$ and $$B$$ are any two events such that $$P(A) = \dfrac {2}{5}$$ and $$P(A\cap B) = \dfrac {3}{20}$$, then the conditional probability, $$P(A|(A'\cup B'))$$, where A' denotes the complement of $$A$$, is equal to: | $$\dfrac {5}{17}$$ |
It is given that the events A and $$B$$ are such that $$P(A)=\displaystyle \frac{1}{4},\ P(A|B)=\displaystyle \frac{1}{2}$$ and $$P(B|A)=\displaystyle \frac{2}{3}$$. Then $$P(B)$$ is |
$$\displaystyle \frac{1}{3}$$ |
Assertion is False, Reason is True | |
One of the two boxes, box $$I$$ and box $$II$$, was selected at random and balls are drawn randomly out of this box. The ball was found to be red.If the probability that this red ball was drawn from box $$II$$ is $$\dfrac{1}{3}$$, then the correct option options with the possible values of $$n_1,n_2,n_3$$ and $$n_4$$ is (are) |
$$n_1 = 3, n_2=6,n_3=10,n_4=50$$ |
A fair die is rolled repeatedly until a six is obtained. Let X denote the number of rolls required. The conditional probability that $$X \geq 6$$ given $$X > 3$$ equals |
$$\displaystyle \frac{25}{36}$$ |
Relations And Functions Quiz Question | Answer |
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If $$f:N\rightarrow N,f(x)=x+3$$, then $$\quad { f }^{ -1 }(x)=.....$$ | does not exist |
If $$f(x)=8x^3$$ and $$g(x)=x^{1/3}$$ then $$(g o f)(x)=?$$ | $$2x$$ |
Which of the following functions are one-one? |
$$h:R\rightarrow R$$ given by $$ h(x)={ x }^{ 3 }+4$$ for all $$\quad x\in R$$ |
A mapping function $$f:X\rightarrow Y$$ is one-one, if |
$$f({ x }_{ 1 })=f({ x }_{ 2 })\Rightarrow { x }_{ 1 }={ x }_{ 2 }$$ for all $${ x }_{ 1 },{ x }_{ 2 }\in X$$ |
Let $$R$$ be a relation from a set $$A$$ to a set $$B$$,then |
$$\displaystyle R\subseteq A\times B$$ |
Number of one-one functions from A to B where $$n(A)=4, n(B)=5$$. | $$120$$ |
Find the value of $$\displaystyle \left( g\circ f \right) \left( 6 \right) $$ if $$\displaystyle g\left( x \right) ={ x }^{ 2 }+\frac { 5 }{ 2 } $$ and $$\displaystyle f\left( x \right) =\frac { x }{ 4 } -1$$. |
2.75 |
The first component of all ordered pairs is called | Domain |
Find the correct expression for $$\displaystyle f\left( g\left( x \right) \right) $$ given that $$\displaystyle f\left( x \right) =4x+1$$ and $$\displaystyle g\left( x \right) ={ x }^{ 2 }-2$$ | $$\displaystyle 4{ x }^{ 2 }-7$$ |
The second component of all ordered pairs of a relation is | Range |
Three Dimensional Geometry Quiz Question | Answer |
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The equation of a plane passing through the points $$A(a, 0, 0), B(0, b, 0)$$ and $$C(0, 0, c)$$ is given by? | $$\dfrac{x}{a}+\dfrac{y}{b}+\dfrac{z}{c}=1$$ |
The direction consines of the line drawn from $$P\left ( -5,3,1 \right )\,to\,Q\left ( 1,5,-2 \right )$$ is | $$\left ( \dfrac {6}{7},\dfrac {2}{7},-\dfrac {3}{7} \right )$$ |
If a straight line makes an angle of $$60^\circ$$ with each of the X and Y axes, the angle which it makes with the Z axis is | $$\dfrac {3\pi}{4}$$ |
The points $$(p+1, 1), (2p+1, 3)$$ and $$(2p+2,2p)$$ are collinear if | $$p=-\dfrac{1}{2}$$ |
In a plane there are 10 points, no three are in same straight line except 4 points which are collinear, then the number of straight lines are | 45 |
The st lines whose direction cosines satisfy: $$al+bm+cn=0$$ and $$fmn+gnl+hlm=0$$ are perpendicular if: |
$$\dfrac {f}{a}+\dfrac {g}{b}+\dfrac {h}{c}=0$$ |
The equation of the plane which passes through the x-axis and perpendicular to the line $$\dfrac {(x - 1)}{cos\theta} = \dfrac {(y + 2)}{sin\theta} = \dfrac {(z - 3)}{0}$$ is | $$x\, cos\theta + y\,sin\theta = 0$$ |
If $$l_1$$, $$m_1$$, $$n_1$$ and $$l_2$$, $$m_2$$, $$n_2$$ are the direction cosines of two perpendicular lines, then the direction cosine of the line which is perpendicular to both the lines , will be | ($$m_1$$$$n_2$$ - $$m_2$$$$n_1$$), ($$n_1$$$$l_2$$ - $$n_2$$$$l_1$$), ($$l_1$$$$m_2$$ - $$l_2$$$$m_1$$) |
The point collinder with (1,-2,-3) and (2,0,0) amoung the following is | (0, -4, -6) |
A line with direction ratio 2,7,-5 is drawn to intersect the lines $$\frac { x-y }{ 3 } =\frac { y-7 }{ -1 } =\frac { z+2 }{ 1 } $$ and $$\frac { x+3 }{ -3 } =\frac { y-3 }{ 2 } =\frac { z-6 }{ 4 } $$ at P and Q respectively, then length of PQ is- | $$\sqrt { 78 } $$ |
Vector Algebra Quiz Question | Answer |
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The position vector of A is $$2\vec { i } +3\vec { j } +4\vec { k } $$$$\vec { AB } =5\vec { i } +7\vec { j } +6\vec { k } $$, then the position vector of B is | $$-7\vec { i } -10\vec { j } -10\vec { k } $$ |
Line passing through $$ (3,4,5) $$ and $$ (4,5,6) $$ has direction ratios $$ \ldots $$ | $$ 1,1,1 $$ |
In a parallelogram ABCD, $$|\overrightarrow{AB}| = a, |\overrightarrow{AD}| = b$$ and $$|\overrightarrow{AC}| = c$$, then $$\overrightarrow{DB}.\overrightarrow{AB}$$ has the value | $$\displaystyle \frac{1}{2} (a^2 + b^2 - c^2)$$ |
If $$|\overrightarrow{C}|^2=60$$ and $$\overrightarrow{C} \times (\widehat{i}+2\widehat{j}+5\widehat{k})=\overrightarrow{0}$$, then a value of $$\overrightarrow{C}\cdot (-7 \widehat{i}+2\widehat{j}+3\widehat{k})$$ is : |
$$12\sqrt{2}$$ |
If $$\vec{a} \times \vec{b} = \vec{b} \times \vec{a}$$, then | $$\mathrm{\vec{a}}=k\mathrm{\vec{b}}$$ |
Let $$P,\ Q,\ R$$ and $$S$$ be the points on the plane with position vectors $$-2\hat{i}-\hat{j},\ 4\hat{i},\ 3\hat{i}+3\hat{j}$$ and $$-3\hat{i}+2\hat{j}$$ respectively. The quadrilateral $$PQRS$$ must be a |
parallelogram, which is neither a rhombus nor a rectangle |
Statement -$$1$$ is True, Statement -$$2$$ is False | |
$$ABCD$$ is a parallelogram and $$AC, BD$$ be its diagonals Then $$ \vec{AC} +\vec{BD}$$ is |
$$2\vec{BC} $$ |
The triangle $$ABC$$ is defined by the vertices $$A= (0,7,10)$$ , $$B=(-1,6,6)$$ and $$C=(-4,9,6)$$. Let $$D$$ be the foot of the attitude from $$B$$ to the side $$AC$$ then $$BD$$ is |
$$-\overline{i}+2\overline{j}+2\overline{k}$$ |
The point $$C=(\dfrac{12}{5}, \dfrac{-1}{5},\dfrac{4}{5})$$ divides the line segment $$AB$$ in the ratio $$3:2$$. If $$B=(2,-1,2)$$ then $$A$$ is |
$$(3, 1,-1)$$ |
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