JEE Questions for Chemistry Aldehydes Ketones And Carboxylic Acids Quiz 10 - MCQExams.com


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  • reaction of benzene and acetyl chloride in the presence of AlCl3
  • reaction of acetonitrile with phenyl magnesium bromide in ether followed by hydrolysis
  • treatment of acetyl chloride with dibenzyl cadmium
  • addition of water to phenyl acetylene in the presence of mercuric sulphate and dilute sulphuric acid.
The best reagent to convert pent-3-en-2-ol into pent-3-en-2-one is
  • pyridinium chlorochromate
  • chromic anhydride in glacial acetic acid
  • acidic dichromate
  • acidic permanganate
An ester (A) with molecular formula C9H10O2 was treated with excess of CH3 MgBr and the complex so formed was treated with H2 SO4 to give an olefin (B) . Ozonolysis of (B) gave a ketone with molecular formula C8H8O which shows positive iodoform test. The structure of (A) is
  • C6H5COOC2H5
  • C6H5COOC6H5
  • C6H5COOCH3
  • p-H3CO—C6H4—COCH3
A nitrogen containing organic compound gave an oily liquid on heating with bromine and potassium hydroxide solution. On shaking the product with acetic anhydride, an antipyretic drug was obtained. The reactions indicate that the starting compound is
  • aniline
  • benzamide
  • acetamide
  • nitrobenzene

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  • (CH3)3 C — O — C2 H5
  • C2H5OC2H5

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With reference to the scheme given, which of the given statement (s) about T, U ,V and W is (are) correct?
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  • T is soluble in hot aqueous NaOH
  • U is optically active
  • Molecular formula of W is C10H18O4
  • V gives effervescence on treatment with aqueous NaHCO3
  • All (1), (and (4)
Which of the following represents the correct order of the activity in the given compounds?
  • CH3COOH > BrCH2COOH > ClCH2COOH > FCH2COOH
  • FCH2COOH > CH3 COOH > BrCH2COOH > ClCH2COOH
  • BrCH2COOH > ClCH2COOH > FCH2COOH > CH3COOH
  • FCH2COOH > ClCH2COOH > BrCH2COOH > CH3COOH
Carboxylic acids readily dissolve in aqueous sodium bicarbonate, liberating carbon dioxide. Which one of the following is correct?
  • Free carboxylic acid and its conjugate base are of comparable stability
  • The free carboxylic acid is more stable than its conjugate base
  • The conjugate base of the carboxylic acid is more stable than the free carboxylic acid
  • The conjugate acid of the carboxylic acid is more stable than the free carboxylic acid
An organic compounds with the molecular formula C8H8O forms 2, 4-DNP derivative, reduces Tollen's reagent and undergoes Cannizaro reaction. On vigorous oxidation, it gives 1, 2-benzenedicarboxylic acid. The organic compound is
  • 2-ethylbenzaldehyde
  • 2-methylbenzaldehyde
  • acetophenone
  • 3-methylbenzaldehyde
  • phenylacetaldehyde
After completion of the reactions (I and II), the organic compound(s) in the reaction mixtures is (are)
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  • Reaction I P and Reaction II P
  • Reaction 1U, acetone and Reaction II Q, acetone
  • Reaction I T, U acetone and Reaction II P
  • Reaction I R acetone and reaction II S acetone
In the given transformation, which of the following is the most appropriate reagent ?
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  • Zn —Hg / HCl
  • Na, Liq. NH3
  • NaBH4
An organic compound 'A' burns with a sooty flame. It is neagtive towards Tollen's reagent test and positive for Brady's reagent test. The compound 'A' is
  • Acetophenone
  • Acetone
  • Salicylic acid
  • Bezaldehyde
An organic compound X is oxidised by using acidified K2 Cr2 O7. The product obtained reacts with phenyl hydrazine but does not answer silver mirror test. The possible structure of X is
  • CH3CH2OH
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  • (CH3)2 CHOH
  • CH3 CHO

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A and B in the following reaction are
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The reduction of benzoyl chloride with Pd and BaSO4 produces
  • Benzyl chloride
  • Benzaldehyde
  • Benzoic acid
  • None of above
Compound (A )(molecular formula C3H8O) is treated with acidified potassium dichromate to form a product B (molecular formula C3H6O). 'B ' forms a shining silver mirror on warming with ammoniacal silver nitrate. `B ' when treated with an aqueous solution of H2NCONHNH2 ∙ HCl and sodium acetate gives a product ' C '. Identify the structure of `C '.
  • CH3CH2 CH = NNHCONH2
  • (CH3)2 C = NNHCONH2
  • (CH3)2 C = NCONHNH2
  • CH3CH2CH = NCONHNH2
Which of the product is formed when acetone is reacted with barium hydroxide solution?

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One mole of an organic compound requires 0.5 mole of oxygen to produce an acid. The compound may be
  • alcohol
  • ether
  • Ketone
  • aldehyde
Aldehydes can be oxidised by
  • Tollen’s reagent
  • Fehling solution
  • Benedict solution
  • All

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  • C6H5CH3
  • C6H5CH2Cl
  • C6H5CHO
  • C6H5COOH
A compound A has molecular formula C2Cl3OH. It reduces Fehling’s solution and on oxidation gives a monocarboxylic acid B. A is obtained by the action of Cl2 on ethyl alcohol.A is
  • Chloral
  • Chloroform
  • Chloromethane
  • Chloroacetic acid
Identify X in the sequence
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  • CH3 — CH2 — CH2OH
  • CH3 —CHOH — CH3
  • CH3 — O —CH2 — CH3
  • CH3 — CH2 — CHO
Benzaldehyde can be prepared by oxidation of toluene by
  • Acidic KMnO4
  • K2Cr2O7
  • CrO2Cl2
  • All
Tollen’s reagent is
  • Ammonical cuprous chloride
  • Ammonical cuprous oxide
  • Ammonical silver bromide
  • Ammonical silver nitrate
When vapours of isopropyl alcohol are passed over heated copper, the major product obtained is
  • Propane
  • Propylene
  • Acetaldehyde
  • Acetone
Benzaldehyde, when heated with conc. KOH solution, gives
  • C6H5CH2OH
  • C6H5COOH
  • C6H5COONa
  • a mixture of C6H5COONa and C6H5CH2OH
Benzene reacts with CH3COCl in the presence of AlCl3 to give.
  • C6H5COCl
  • C6H5Cl
  • C6H5CH3
  • C6H5COCH3
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