Explanation
NH3 undergoes H- bonding and hence has the highest b.p. Among the remaining hydrides i.e., PH3, AsH3 and SbH3 and BiH3, the b.p. increases as the size of the element increases and hence the magnitude of the van der Waal’s forces of attraction increases. Thus, PH3 has the lowest b.p.
Linear combination of two hybridized orbitals leads to the formation of sigma bond .
B.O. in N2 = (10 – 4)/2=3 B.O. in N2+ = (9 – 4)/ 2 =2.5 B.O. in O2 = (10 – 6)/2 =2.0 B.O. in O2+= (10 - 5)/2 = 2.5 N2+ contains one unpaired electron and hence is paramagnetic. Therefore option (d) is wrong . All other statements are correct.
Please disable the adBlock and continue. Thank you.