Explanation
1 F deposits 1 g eq.
Q = C × t = 0.6 ×(7 × 60) = 252 C,= 252/96500F‒ =2.6 × 10-3 F.
One mole of electrons ( i.e, 1 F) will deposit 1 g eq.
Q = 12× 60 × 60 = 43200C Ni2++2e‒ → Ni, Theoretically 2× 96500C will deposit Ni = 58.7 g. Hence 43200C will deposit Ni = 13.137 g. As current efficiency is 60 %. mass actually deposited = 60/100 × 13.137 = 7.88g
A salt bridge is a laboratory device used to connect the oxidation and reduction half-cells of a galvanic cell (voltaic cell), a type of electrochemical cell. It maintains electrical neutrality within the internal circuit, preventing the cell from rapidly running its reaction to equilibrium. If no salt bridge were present, the solution in one half cell would accumulate negative charge and the solution in the other half cell would accumulate positive charge as the reaction proceeded, quickly preventing further reaction, and hence production of electricity. And it does not participate chemically in the cell reaction
EMF for (a) is positive.(c) and (d) involve only oxidation or reduction and are impossible.
One g eq. is deposited by 1 F i.e. charge on 1 mole of electrons.
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