Explanation
MgCO3 and CaCO3 are water insoluble. CaSO4 dissolves in water adding Ca2+ ions which are responsible for producing hardness in water. Hence saturation of ordinary water with CaSO4 produces hard water.
Hydrogen peroxide is manufactured by electrolysis of 50 % sulphuric acid followed by vacuum distillation. The distillate is 30 % hydrogen [peroxide. The first product of electrolysis is peroxy disulphuric acid which is obtained by the electrolytic oxidation of sulphuric acid.
2H2SO4 → 2H+ + 2HSO4-
2HSO4- → H2S2O8 + 2e- ( at anode)
Peroxy- disulphuric acid H2S2O8 reacts with water during distillation to form hydrogen peroxide.
H2S2O8 (aq) + 2H2O (l) → 2H2SO4 (aq) + H2O2 (aq)
2H+ + 2e- → H2 (g) (at cathode)
Hence X is H2SO4 and Y is H2S2O8. Therefore the number of peroxy bonds present in X and Y are zero and 1 respectively.
20 volume of H2O2 = 1mL of H2O2 gives 20 mL of oxygen on decomposition
∴ For 5000cm3 of O2 required = 5000/20 = 250 cm3
(a) Heavy water is used as a moderator in nuclear reactors.
(b) Heavy water is more associated than ordinary water.
(c) Heavy water is more effective solvent than ordinary water.
Which of the above statements are correct?
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