Explanation
3000 yrs= Two half lives.
Amount left = 1/4 th = 0.25g
The 1st pair is isotopes, the 2nd is isobars.
α − rays,, being heavy particles are easily stopped by air.
Same number of nucleons means same mass number. Different number of protons means different atomic numbers. Hence they are isobars.
Mass defect= 34. 96903 – 34 .96885 = 0.00018 amu
Energy released = 931.5 × 0.00018MeV
= 0.167 Me V.
He atom has 2 p + 2 n. Hence
∆m = (2 × 1.0078 + 2 × 1.0087) – 4.0026 = 0.0304 amu.
∴ Energy released = 0.0304 × 931.5MeV = 28.3MeV
Binding energy per nucleon 28.3/4 = 7 MeV (approx)
Decay by emission β− – result in decrease of n/p ratio for nuclides with Z< 82.
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