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JEE Questions for Chemistry Solutions Quiz 14 - MCQExams.com
JEE
Chemistry
Solutions
Quiz 14
Boiling point of an aqueous solution of 0.05m FeCl
3
is 100.087
o
C; then, what will be the value of Van’t Hoff factor i ? (K
b
= 0.513
o
C – kg - mole
-1
)
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0%
4
0%
3.4
0%
2.5
0%
2.8
Difference of boiling point and freezing point of an aqueous solution of glucose is 104
o
C at 1 bar pressure; then what will be the molality of the solution ? (K
b
= 0.513
o
and K+” = 1.86
o
C – kg - mole
-1
)
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0%
2.373 m
0%
1.05 m
0%
2.151 m
0%
1.68 m
Difference of boiling point and freezing point of 0.2 m acetic acid prepared in benzene is 75.7
o
C; then, state the value of Van’t Hoff factor i ? (For benzene, K
b
= 2.65
o
C – kg – mol
–1
, K
f
= 5.12
o
C – kg – mol
– 1
, T
b
= 80
o
C, T
f
= 5.5
o
C)
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0%
1.44
0%
0.64
0%
0.83
0%
0.77
Difference in boiling point and freezing point of 10 kg aqueous solution of urea is 100.2372
o
C; then what quantity of urea dissolved in the solution ? (Kb = 0.513
o
and K+” = 1.86
o
C – kg - mole
-1
)
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0%
59.64
0%
38.946
0%
51.65
0%
40.5
500 ml solution of HCl is prepared by dissolving 14.6 gm HCl in water. What will be the molarity of HCl in the solution ? (Molecular weight of HCl = 36.5 gm/mole )
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0%
0.4M
0%
0.3M
0%
0.8M
0%
0.3M
What would be the molality of the solution prepared by dissolving 60 gm NaOH in 1.5 kg water ? (Molecules weight of NaOH = 40 gm/mole)
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0%
0.5M
0%
1.0M
0%
0.8M
0%
0.4M
What would be the molarity of 3.0 N H
2
SO
4
solution ?
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0%
6M
0%
1.5M
0%
3M
0%
1M
What quantity of NaOH is needed to prepare 1.2 m, 800 ml NaOH solution ?
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0%
3.84
0%
60
0%
42
0%
38.4
What would be the molarity and normality of solution prepared by dissolving 19.6 gm H
2
SO
4
in dissolved water to prepare 800 ml solution ? (Molecular weight of H
2
SO
4
is 98 gm/mole)
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0%
0.5 M, 0.25 N
0%
0.25 M, 0.125 N
0%
0,25 M, 0.5 N
0%
0.125 M, 0.25 N
What amount of H
2
SO
4
required to prepare 2 litre of 0.5 N H
2
SO
4
solution ? (Molecular weight of H
2
SO
4
is 98 gm/mole)
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0%
98 gm
0%
24.5 gm
0%
49 gm
0%
73.5 gm
What will be the concentration of solution prepared by dissolving 50 gm glucose in 200 gm water ?
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0%
25 % w/w
0%
20 % w/w
0%
35 % w/w
0%
15 % w/w
What quantity of urea required to prepare 20 % w/w solution having weight 150 gm ?
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0%
20 gm
0%
40 gm
0%
10 gm
0%
30 gm
What will be the mole-fraction of ethanol in solution, prepared by dissolving 9.2 gm ethanol in 900 gm water ? (Molecular weight of water and ethanol are 18 and 48 gm/mole respectively)
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0%
0.04
0%
0.004
0%
0.4
0%
0.0004
What will be the mole-fraction of water and NaOH respectively, when 260 gm NaOH dissolved in 1.8 kg water ? (M.W of water NaOH = 18440)
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0%
0.96, 0.4
0%
0.0962, 0.38
0%
0.0962, .038
0%
0.962, 0.0038
What would be the mole-fraction of solute in an aqueous solution of a substances heaving strength 4.5 m ?
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0%
0.75
0%
0.075
0%
0.45
0%
0.045
The density of 98% w/w H
2
SO
4
solution is 1.8 gm/mole then, molarity of the solution is -
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0%
20 M
0%
10 M
0%
18 M
0%
None of these
Molarity and molality of an aqueous solution of H
2
SO
4
are 1.56 (M) and 1.8 (M) respectively; then, water will be the density of the solution ?
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0%
1.835 gm/ml
0%
1.55 gm/ml
0%
1.02 gm/ml
0%
1.725 gm/ml
A solution is prepared from A, B, C and D mole-fraction of A, B and C are 0.1, 0.2 and 0.4 respectively then, mole-fraction of D is -
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0%
0.2
0%
0.1
0%
0.3
0%
0.4
The density of 4 M H
2
SO
4
solution is 1.992 gm/ml then, what will be the molality of the solution ? (Molecular weight of H
2
SO
4
is 98 gm/mole)
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0%
3M
0%
3.5M
0%
1.2M
0%
0.4M
Molarity of 1.2 N aqueous solution of AlCl
3
is -
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0%
3.6m
0%
2.4m
0%
1.2m
0%
0.4m
What will be the molality of the solution prpared using 500 gm of 25 % w/w NaOH and 500 gm of 15 % w/w NaOH solution ? (Molecular weight of NaOH = 40 gm/mole)
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0%
12.74 m
0%
6.25 m
0%
9 m
0%
5 m
What wiil be the molality of solution prepared by taking 25 % w/w NaOH and 15 % w/w NaOH solution ? (Molecular weight of NaOH = 40 gm/mole)
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0%
12.74 m
0%
5.5 m
0%
9 m
0%
4 m
The density of 2.5 M NaOH solution is 1.15 gm/ml; then, which of the following alternative is correct for molarity and molality ?
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0%
M > m
0%
M < m
0%
M = m
0%
can ’t b e predicted
Which of the following is correct for an ideal solution ?
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0%
“H = 0, “V = 0, “S = 0
0%
“H `” 0, “V = 0, “S = 0
0%
“H = 0, “V = 0, “S `” 0
0%
“H = 0, “V `” 0, “S = 0
Boiling point of Aqueous solutions of 0.05 m ABC and 0.02 m X
2
Y
3
are same at 1 bar pressure; then, what will be the values of Van’t Hoff factor (i) for solute in both the solutions ?
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0%
1.04, 5.1
0%
1.9, 4.75
0%
1.2, 3.4
0%
1.5, 3.7
Which of the following substances having concentration of aqueous solution 1% w/w, possesses higher boiling point ? (Molecular weight of Kcl, BaCl
2
, glucose and Al
2
(SO
4
)
3
are 74.5, 208, 342 gm’mole respectively) (Assume that inonic solids dissociates completely in their aqueous solution)
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0%
KCl
0%
BaCl2
0%
glucose
0%
Al2(SO4)3
Molecular weight of biomolecules such as protein can be determined by ______ method.
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0%
osmotic pressure measurement
0%
Depression in freezing point measurement
0%
Elevation in boiling point measurement
0%
Vapour pressure measurement
In the references of the following graph, UR -Oy = __________.
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0%
(SU -VW)QU
0%
VU(VW – QY)
0%
(VW – QY)QU
0%
VW(QV – VU)
What will be the elevation in boiling point of an aqueous solution of 0.5 m NaCl ? ( i = 1.8)
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0%
2.04, 5.1
0%
1.9, 4.57
0%
1.2, 3.4
0%
1.4, 3.7
When 2 gm phenol id dissolve in 100gm benzene; then depression in freezing point is 0.69 K. If its association is dimeric, then calculate its degree of association (X). Molar depression constant for solvent is 5.12 K - kg - mole
-1
.
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0%
0.0734
0%
0.374
0%
0.00734
0%
0.734
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