Explanation
Effective molar concentration = i×M
Therefore ,
A(glucose) = 1×0.1 = 0.1 M
B(NaCl) = 2 × 0.05 = 0.1 M
C(BaCl2) = 3 × 0.05 = 0.15 M
D(AlCl3) = 4 × 0.1 = 0.4 M
Hence A and B are isotonic with each other.
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