JEE Questions for Chemistry Solutions Quiz 6 - MCQExams.com

Choose the correct statement.
When concentration of a salt solution is increased
  • Boiling point increases while vapour pressure decreases.
  • Boiling point decreases while vapour pressure increases.
  • Freezing point decreases while vapour pressure increases.
  • Freezing point increases while vapour pressure decreases.
The relative lowering of vapour pressure of a dilute aqueous solution containing non-volatile solute is 0.0125. The molality of the solution is about
  • 0.70
  • 0.50
  • 0.90
  • 0.80
The empirical formula of a non-electrolyte is CH2O. A solution containing 6 g of the compound exerts the same osmotic pressure as that of 0.05 M glucose solution at the same temperature. The molecular formula of the compound is
  • C2H4O2
  • C3H6O3
  • C5H10O5
  • C4H8O4
Colligative properties of a solution depends upon
  • nature of both solvent and solute
  • nature of solute only
  • number of solvent particles
  • the number of solute particles
At a constant temperature, which of the following aqueous solutions will have the maximum vapour pressure ?
( Mol. wt. NaCl = 58.5 , H2SO4 = 98.0 g ∙ mol-1 )
  • 1 molal NaCl (aq)
  • 1 molar NaCl (aq)
  • 1 molal H2SO4 (aq)
  • 1 molar H2SO4 (aq)
Which of the following would exert maximum osmotic pressure ?
  • Decinormal aluminium sulphate
  • Decinormal barium chloride
  • Decinormal sodium chloride
  • A solution obtained by mixing equal volumes of (and (and filtering
What is the freezing point of a solution containing 8.1 g HBr in 100 g water assuming the acid to be 90% ionised ? (Kf for wt. = 1.86 K mol-1)
  • 0.85°C
  • -3.53°C
  • 0°C
  • -0.35°C
In countries nearer to polar region, the roads are sprinkled with CaCl2 . This is
  • to minimise the wear and tear of the roads
  • to minimise the snow fall
  • to minimise pollution
  • to minimise the accumulation of dust on the road
The difference between the boiling point and freezing point of an aqueous solution containing sucrose (mol. wt. = 342 g mol-1) in 100 g of water is 105.0°C. If Kf and Kb of water are 1.86 and 0.51 K kg mol-1 respectively, the weight of sucrose in the solution is about
  • 34.2 g
  • 342 g
  • 7.2 g
  • 72 g
  • 68.4 g
If 0.1 M solutions of each electrolyte are taken and if all electrolytes are completely dissociated, then whose boiling point will be highest ?
  • Glucose
  • KCl
  • BaCl2
  • K4 [Fe(CN)6]
The vapour pressure of water at 20°C is 17.5 mm Hg. If 18 g of glucose (C6H12O6 ) is added to 178.2 g of water at 20°C, the vapour pressure of the resulting solution will be
  • 17.675 mmHg
  • 15.750 mmHg
  • 16.500 mmHg
  • 17.325 mmHg
When 25 g of a non-volatile solute is dissolved in 100 g of water, the vapour pressure is lowered by 2.25 × 10-1 mm. If the vapour pressure of water at 20°C is 17.5 mm, what is the molecular weight of the solute ?
  • 206
  • 302
  • 350
  • 276
Solutions A, B, C and D are respectively 0.1 M glucose, 0.05 M NaCl, 0.05 M BaCl2 and 0.1 M AlCl3 . Which one of the following pairs is isotonic ?
  • A and B
  • B and C
  • A and D
  • A and C
Which of the following solutions will have highest boiling point ?
  • 0.1 M FeCl3
  • 0.1 M BaCl2
  • 0.1 M NaCl
  • 0.1 M urea (NH2 CONH2 )
Which of the following can be measured by the Ostwald-Walker dynamic method ?
  • Relative lowering of vapour pressure
  • Lowering of vapour pressure
  • Vapour pressure of the solvent
  • All of the above
The freezing point of water is depressed by 0.37°C in a 0.01 mol NaCl solution. The freezing point of 0.02 molal solution of urea is depressed by
  • 0.37°C
  • 0.74°C
  • 0.185°C
  • 0°C
On adding 1 g arsenic to 80 g benzene, the freezing point of benzene is lowered by 0.19°C. The formula of arsenic is
( Kf = 5.08 K kg mol-1 )
  • As
  • As2
  • As3
  • As4
The osmotic pressure (at 27°C) of an aqueous solution (200 mL) containing 6 g of a protein is 2 × 10-3 atm. If R = 0.080 L atm mol-1 K -1, the molecular weight of protein is
  • 7.2 × 105
  • 3.6 × 105
  • 1.8 × 105
  • 1.0 × 105
A solution containing 4 g of polyvinyl chloride polymer in one litre of dioxane was found to have an osmotic pressure of 4.1×10-4atm at 27°C. The approximate molecular weight of the polymer is
  • 1.5 × 103
  • 2.4 × 105
  • 1.0 × 104
  • 2 × 1012
A solution of sucrose (molar mass = 342 g/mol) is prepared by dissolving 68.4 g of it per litre of solution, what is its osmotic pressure
(R = 0.082 L atm K-1 mol-1) at 273 K ?
  • 3.92 atm
  • 4.48 atm
  • 5.92 atm
  • 29.4 atm
In a 0.2 molal aqueous solution of a weak acid HX, the degree of ionisation is 0.3. Taking Kf for water as 1.85, the freezing point of the solution will be nearest to
  • - 0.481°C
  • - 0.360° C
  • -0.260° C
  • + 0.480° C
At temperature 327°C and concentration C osmotic pressure of a solution is p, the same solutions at concentration C /2 and a temperature 427°C shows osmotic pressure 2 atm, value of p will be

  • Chemistry-Solutions-7034.png
  • 2)
    Chemistry-Solutions-7035.png

  • Chemistry-Solutions-7036.png

  • Chemistry-Solutions-7037.png
18 g of glucose ( C6H12O6 ) is added to 178.2 g of water. The vapour pressure of water for this aqueous solution at 100°C is
  • 759.00 Torr
  • 7.60 Torr
  • 76.00 Torr
  • 752.40 Torr
The vapour pressure will be lowest for
  • 0.1 M sugar solution
  • 0.1 M KCl solution
  • 0.1 M Cu(NO3)2 solution
  • 0.1 M AgNO3 solution
Osmotic pressure of 0.4% urea solution is 1.64 atm and that of 3.42% cane sugar is 2.46 atm. When the above two solutions are mixed, the osmotic pressure of the resulting solution is
  • 0.82 atm
  • 2.46 atm
  • 1.64 atm
  • 4.10 atm
Depression in freezing point is 6 K for NaCl solution if Kf for water is 1.86 K/Kg/mol, amount of NaCl dissolved in 1 Kg water is
  • 3.42
  • 1.62
  • 3.24
  • 1.71
If a solution containing 0.072 g atom of sulphur in 100 g of a solvent ( Kf = 7.0 ) gave a freezing point depression of 0.84°C , the molecular formula of sulphur in the solution is
  • S6
  • S7
  • S8
  • S9
Equimolar solution in the same solvent have
  • different boiling and different freezing points
  • same boiling and same freezing points
  • same freezing point but different boiling point
  • same boiling point but different freezing point
The molar freezing point constant for water is 1.86°C/mol. If 342 g of cane sugar ( C12 H22 O11) is dissolved in 1000 g of water , the solution will freeze at
  • -1.86°C
  • 1.86°C
  • -3.92°C
  • 2.42°C
Dry air is passed through a solution containing 10 g of a solute in 90 g of water and then through pure water. The loss in weight of solution is 2.5 g and that of pure solvent is 0.05 g. Calculate the molecular weight of the solute.
  • 50
  • 180
  • 102
  • 25
  • 51
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