Explanation
V.D = 11.2, Mol. wt. = 22.4.
Hence 22.4 g = 22.4 L ∴ 11.2 g = 11.2L
Mass of 1 L steam = 1000 × 0006 = 0.6 g = mass of liquid water Volume of water = 0.6 cc (Qd = 1 g cm-3). Same volume will be occupied by water molecules in steam
No. of collisions of one molecule/unit time = X
No. of collisions of N molecules/unit time = NX
As in one collision, two molecules are involved, collision frequency = NX/2.
At a particular temp. the fraction of molecules possessing a particular speed remains constant. As the total no. of molecules is doubled, to keep the fraction same, no. of molecules possessing speed in the same range is also doubled.
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