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JEE Questions for Chemistry Structure Of Atom Quiz 7 - MCQExams.com
JEE
Chemistry
Structure Of Atom
Quiz 7
In two H atoms A and 13 the electrons move around the nucleus in circular orbits of radius r and 4r respectively. The ratio of the times taken by them to complete one revolution is
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0%
1: 4
0%
1: 2
0%
1: 8
0%
2: 1
The energy required to dislodge electron from excited isolated H atom (IE
1
= 13.6eV) is
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= 13.6eV
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> 13.6eV
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< 13.6eVand > 3.4eV
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3.4eV
Velocity of electron in the first orbit of H-atom is compared to that of velocity of light is approximately
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0%
2)
0%
0%
same
How many electrons in Cu atom have (n + ) = 4
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6
0%
7
0%
8
0%
4
In any subshell the maximum number of electrons having same value of spin quantum number is
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0%
l + 2
0%
2l
0%
4l + 2
Explanation
>
How many electrons in K (Z =have n = 4 and ?
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1
0%
2
0%
3
0%
4
Suggest two transitions in hydrogen spectrum for which wave number ratio is 108:7
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2 → 1, 3 → 1
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2 → 1, 4 → 3
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2 → 1, 5 → 4
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2 → 1, 4 → 1
One unpaired electron causes magnetic moment of 1.1 B.M. The magnetic moment of Fe
+2
ion is
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4.4
0%
5.5
0%
2.2
0%
0
Number of waves made by a Bohr electron in one complete revolution in its fourth orbit is
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0%
2
0%
3
0%
4
0%
infinite
Which of the following electronic transitions require that the greatest amount of energy be absorbed by a hydrogen atom?
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n = 1 to n = 2
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n = 2 to n = 4
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n = 3 to n = 6
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n = 0 to n = 1
The radius of first Bohr orbit is , then de-Broglie wavelength of electron in 3rd orbit is nearly
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2πx
0%
6πx
0%
9x
0%
x/3
With increasing principle quantum number, the energy difference between adjacent energy levels in H atom
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decreases
0%
increases
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remains constant
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decreases for low value of Z and increases for higher value of Z
The electrons present in K – shell of the atom will differ in
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principal quantum number
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azimuthal quantum number
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magnetic quantum number
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spin quantum number
The ratio of the ionization energy of H and Be
3+
is..............
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1: 1
0%
1: 3
0%
1 : 9
0%
1: 16
The maximum number of electrons in a subshell for which
l
= 3 is
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0%
14
0%
10
0%
8
0%
4
The number of electrons in the M shell of the element with atomic number 24 is
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0%
24
0%
12
0%
13
0%
8
Sodium chloride imparts a yellow colour to the Bunsen flame. This can be interpreted due to the
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low ionization energy of sodium
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sublimation of metallic sodium to give yellow vapour
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emission of excess energy absorbed as a radiation in the visible region
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photosensitivity of sodium
The exact path of electron 2p – orbital cannot be determined.” The above statement is based upon
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Hund’s Rule
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Bohr’s Rule
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Uncertainty principle
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Aufbau principle
The maximum number of electrons in a subshell is given by the expression
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4l – 2
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4l + 2
0%
2l + 1
0%
2n2
If r is the radius of first orbit, the radius of nth orbit of the H atom will be
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rn2
0%
rn
0%
r/n
0%
r2n2
At 200°C hydrogen molecules have velocity 105 cm sec
–1
. The de-Broglie wavelength in this case is approximately
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2 Å
0%
1000 Å
0%
100 Å
0%
10 Å
The number of electrons in 3d shell for element with atomic number 26 is
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4
0%
6
0%
8
0%
10
In a set of degenerate orbitals the electrons distribute themselves to retain similar spins as far as possible. This statement is attributed to
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Pauli’s exclusion principle
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Aufbau principle
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Hund’s Rule
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Slater rules
If uncertainty in the position of electron is zero, the uncertainty in its momentum would be
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zero
0%
2)
0%
0%
infinite
The radius of second Bohr’s orbit is
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0·053 nm
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0·053/4 nm
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0·053 × 4nm
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0·053 × 20 nm
For which of the following sets of quantum -numbers an electron will have the highest energy ?
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3, 2, 1, 1/2
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4, 2, -1, 1/2
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4, 1, 0, -1/2
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5, 0, 0, 1/2
The uncertainty in the position of an electron (mass 9.1 × 10
–28
g) moving with a velocity of 3.0 x 10
4
cms
–1
accurate up to 0.011% will be
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1·92 cm
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7·68 cm
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0·175 cm
0%
3·84cm
The radius of hydrogen atom in the ground state is 0·53 Å, the radius of
3
Li
2+
in the similar state is
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0%
1·06 Å
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0·265Å
0%
0·17 Å
0%
0·53 Å
Splitting of spectral lines under the influence of magnetic field is called
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0%
Stark effect
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Zeeman effect
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Photoelectric effect
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None of these
The total number of orbitals in a shell with principal quantum number ‘n’ is
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2n
0%
2n2
0%
n2
0%
n + 1
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