Explanation
Packing fraction of CCP = 74%
Hence free space = (100-74)% = 26%
Packing fraction of bcc = 68%
Free space = (100-68)% = 32%
The number of tetrahedral voids in CCP = 2N.
Imagine if the no. of atoms in y elements in CCP = 100
Then, tetrahedral void in CCP = 2×100 = 200
If element X occupy 2/3rd of tetrahedral void
Then no. of atoms in x element = 2/3 × 200 = 400/3
Then the ratio of X and Y will be
X: Y = 400/3: 100
⇒ X/Y = 400/ (3×100) = 400/300 = 4/3
Hence the formula of the compound will be X4Y3.
The given compound MPXq, has CCP.
Hence contribution of M-atom from each edge = ¼
∴ no. of M atom = (1/4×4)+1
(from edge) (from body centre)
1 + 1 = 2
No. of X atom = (1/8 × 8) + 1/2 ×6(from face centre)
(from corners)
1 + 3 = 4.
∴ Empirical formula = M2X4 = (MX2)2 or MX2
BaCl2 is a crystalline solid and will show anisotropy.
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