Explanation
Amorphous solids do not undergo clean cleavage
Solid CO2 is a molecular crystal
Covalent crystals have highest melting points because of network structure.
Isomorphous is not a crystal system.
The arrangement of first two layers in hcp and ccp is exactly same.
ccp = fcc
No. of tetrahedral voids =2. × No.of spheres in the packing.
r = 0.225R
The space occupied in hcp and ccp arrangement is 74%
fcc = ccp has a co-ord. no =12
As CsCl has co-ord. no = 8, the radius ratio lies in the range 0.732-1.000.
For isoelectronic ions, greater the nuclear charge, smaller is the ionic radius.
F‒ and O2‒ are isoelectronic but nuclear charge of F‒ > O2‒. Hence ionic radius of F‒ < O2‒. So the order is F‒ < O2‒ < S2‒ < Br‒.
Tetrahedral voids are vacant. All the octahedral voids are occupied by Na+ ions.
Co-ord.no of Cs+ and Cl- ions in CsCl is 8: 8
In ZnS,co -ord. no. of Zn2+ and S2- ions is 4 : 4.
AgBr has NaCl type structure
The given structure is of zinc blende
Fe0.9S is non-stoichiometric( ratio is not 1:1)
Bragg’s law is nλ = 2d sin θ.
Mg2 SiO4 is an orthosilicate
Schottky defect is due to missing of equal number of cations and anions.
In Schottky defect, equal no. of cations and anions are missing.
Due to small difference in size of Na+ and Cl- ions and high co-ordination number, NaCl has Schottky defects.
fcc (= ccp) has maximum space occupied and hence largest packing fraction
In order of strength van der waals < dipole-dipole < hydrogen bond < covalent
Please disable the adBlock and continue. Thank you.