Explanation
Given, yz + zx + xy = 12 (constant) The value of (yz) (zx) (xy) is greatest when yz = zx = xy = K (say) ∴ 3K = 12 ⇒ K = 4 ∴ greatest value of (yz) (zx) (xy) = (4) (4) (4) = 64 ∴ greatest value of xyz = 8
Given x + y + z = 9 = constant K Here m = –1 and n = 3 Hence the least value of x–1 + y–1 + z–1 = 31–(–1).9–1 = 9/9 =1
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