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JEE Questions for Maths Inverse Trigonometric Functions Quiz 1 - MCQExams.com
JEE
Maths
Inverse Trigonometric Functions
Quiz 1
The greatest and least values of (sin
-1
χ )
2
+ (cos
-1
χ)
2
are respectively
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0%
0%
2)
0%
0%
The value of sin (2 sin
-1
0.is
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0%
0.48
0%
sin 1.2o
0%
sin 1.6o
0%
0.96
If χ > 0, y > 0, z > 0, χy + yz + zχ < 1 and tan
-1
χ + tan
-1
y + tan
-1
z = π, then χ + y + z is equal to
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0%
0
0%
χyz
0%
3χyz
0%
√(χyz)
If we consider only the principle values of the inverse trigonometric functions then the value of
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0%
0%
2)
0%
0%
tan
-1
(√- cot
-1
(-√is equal to
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0%
0
0%
2√3
0%
-(π/2)
0%
π
The number of value(s) of χ, in which tan
-1
(1/χ) = π tan
-1
χ, 0 < χ < 1
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0%
not defined
0%
√3
0%
± 1
0%
0
The value of sin (2 tan
-1
χ), |χ| ≤ 1 is
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0%
1/χ
0%
χ
0%
1/χ2
0%
2χ/ (1 + χ2)
The number of real solutions of
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0%
zero
0%
one
0%
two
0%
infinite
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0%
0%
2)
0%
0%
0%
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0%
1/2
0%
1
0%
–1/2
0%
-1
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0%
π/2 - θ
0%
θ - (π/4)
0%
2θ - (π/2)
0%
π/4 - θ
If sin
-1
1/3 + sin
-1
2/3 = sin
-1
χ, then the value of χ is
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0%
0
0%
2)
0%
0%
π/2
cot
-1
(2.1
2
) + cot
-1
(2.2
2
) + cot
-1
(2.3
2
) + ... upto ∞ is equal to
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0%
π/4
0%
π/3
0%
π/2
0%
π/5
If χ takes negative permissible value, then sin
-1
χ is equal to
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0%
0%
2)
0%
0%
The value of x for which sin (cot
–1
(1+ x)) = cos (tan
–1
x) is
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0%
1/2
0%
1
0%
0
0%
–1/2
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0%
0%
2)
0%
0%
0%
The value of cos (2 cos
-1
0.is
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0%
0.48
0%
0.96
0%
0.6
0%
None of these
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0%
0%
2)
0%
0%
If (tan
-1
χ)
2
+ (cot
-1
χ )
2
= 5π
2
/8 , then χ is equal to
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0%
0
0%
2
0%
1
0%
- 1
0%
2√2
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0%
π/4
0%
- (π/4)
0%
π/2
0%
- (π/2)
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0%
0%
2)
0%
0%
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0%
π/6
0%
π/4
0%
π/3
0%
π/2
The solution of tan
-1
2θ + tan
-1
3θ = π/4 is
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0%
1/√3
0%
1/3
0%
1/6
0%
1/√6
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0%
0%
2)
0%
0%
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0%
0%
2)
0%
0%
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0%
π/2
0%
π/4
0%
π
0%
3π/4
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0%
3π/10
0%
5π/10
0%
7π/10
0%
9π/10
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0%
√5/3
0%
2√5/3
0%
4√5/9
0%
2√5/9
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0%
0%
2)
0%
0%
none
If 2 tan
-1
(cos χ) = tan
-1
(2 cosec χ ), then the value of χ is
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0%
3π/4
0%
π/4
0%
π/3
0%
None of these
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