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JEE Questions for Maths Limits Continuity And Differentiability Quiz 5 - MCQExams.com
JEE
Maths
Limits Continuity And Differentiability
Quiz 5
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1
0%
0
0%
e
0%
None of these
For the function, which of the following is correct
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0%
2)
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0%
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does not exist
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infinite
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0
0%
2
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0
0%
1/2
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1
0%
3/2
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10/3
0%
3/10
0%
6/5
0%
5/6
If α and β are the distinct roots a
x
2
+ b
x
+ c = 0, then
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1/2 (α - β)2
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- (α2/(α - β )2
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0
0%
α2/2 (α - β)2
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0
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-1
0%
-2
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1
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0
0%
-1
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1
0%
2
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1/2
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- (1/2)
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0
0%
1
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∞
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1
0%
0
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does not exist
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2
0%
-1
0%
0
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does not exist
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0
0%
-1
0%
1
0%
∞
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l1 < l2 < l3
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l2 < l3 < l1
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l3 < l2 < l1
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l1 < l3 < l2
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1/√2
0%
1/2
0%
1
0%
2
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3
0%
2
0%
-1
0%
4
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1
0%
0
0%
e
0%
e2
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1 and - 2
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1 and 2
0%
-1 and 2
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-1 and -2
For every integer
n
let a
n
and b
n
be real numbers. if function
f
: R → R is given by
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0%
2)
0%
0%
Define F(
x
) as the product of two real functions
f
1
=
x
,
x
ϵ R and
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Statement I is incorrect, Statement II is correct
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Statement I is correct, Statement II is correct; Statement II is correct explanation for Statement I
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Statement I is correct, Statement II is correct; Statement II is not a correct explanation for Statement I
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Statement I is correct, Statement II is incorrect
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p = 5/2 and q = 1/2
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p = 3/2 and q = 1/2
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p = 1/2 and q = 3/2
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p = 1/2 and q = 3/2
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0
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-1
0%
1
0%
e
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a = 1 and b = 1
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a = - 1 and b = -1
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a = - 1 and b = 1
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a = 1 and b = - 1
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a3/2
0%
a1/2
0%
- a1/2
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- a3/2
f
(
x
) =
x
+ |
x
| is continuous for
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0%
2)
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only x > 0
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no value of x
The number of discontinuities of the greatest number integer function
f
(
x
) = [
x
],
x
ϵ (- (7/2),is equal to
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104
0%
100
0%
102
0%
101
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103
if
f
(
x
) = [
x
3
- 3], where [
x
] is the greatest integer function. Then, the number of points in the interval (1,where function is discontinuous is
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4
0%
5
0%
6
0%
7
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2
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1
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-1
0%
0
The function
f
(
x
) is defined as
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-1/3
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1
0%
2/3
0%
1/3
If
f
: R → r is defined by
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-2
0%
-4
0%
-6
0%
-8
The value of
f
(0), so that
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log(1/20
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0
0%
4
0%
-1 + log 2
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f is discontinuous
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f is continuous only, if λ = 0
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f is continuous only, whatever λ may be
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None of these
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∞
0%
1
0%
0
0%
None of these
Explanation
The function is not coninuous .
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4
0%
2
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1
0%
1/4
The function
f
: R -{0} → R is given by
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2
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-1
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0
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1
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for x = 2 only
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for all real values of x such that x ≠ 2
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for all real values of x
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for all integral values ofx only
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π/5
0%
5/π
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1
0%
0
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2
0%
4
0%
3
0%
1
If the derivative of the function
f
(
x
) is everywhere continuous and is given by
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a = 2, b = -3
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a = 3, b = 2
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a = -2, b = -3
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a = -3, b = -2
The value of k which the function
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k = 0
0%
k = 1
0%
k = -1
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None of these
The function
f
(
x
) = (
x
2
-|
x
2
- 3
x
+ 2|+ cos|
x
| is non-differentiable at
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-1
0%
0
0%
1
0%
2
Let R be the set of all real numbers. If
f
: R → r is a function, such that |
f
(
x
)-
f
(
x
)|
2
≤ |
x
- y|
3
, ∀
x
, y ϵ R, then
f
' (
x
) is equal to
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0%
f(x)
0%
1
0%
0
0%
x2
0%
x
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1/4
0%
1/2
0%
3/4
0%
1
0%
0
The function
f
(
x
) = a sin |
x
| + be
|
x
|
is differentiable at
x
= 0, when
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3a + b = 0
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3a - b = 0
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a + b = 0
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a - b = 0
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differentiable both at x = 0 at x = 2
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differentiable at x= 0 but not differentiable at x= 2
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not differentiable at x = 0 but differentiable at x = 0
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differentiable neither at x = 0 nor at x = 2
Consider the function
f
x
= |
x
- 2| + |
x
- 5|,
x
ϵ R Statement I
f
' (= 0 Statement II
f
is continuous in [2, 5], differentiable in (2,and
f
(=
f
(5).
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Statement I is incorrect, Statement II is correct
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Statement I is correct, Statement II is correct; Statement II is correct explanation for Statement I
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Statement I is correct, Statement Ii is correct; Statement II is not a correct explanation for Statement I
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Statement I is correct, Statement Ii is incorrect
A function
f
is defined by
f
(
x
) = 2 + (
x
-1)
2/3
in [0, 2]. Which of the following is not correct ?
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f is continuous is [0, 2]
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f(= f(2)
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f is not derivable in [0, 2]
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Rolle's theorem is true [0, 2]
The number of points of
f
(
x
) = |
x
- 1| + |
x
- 3| + sin
x
,
x
ϵ [0, 4), where
f
(
x
) is not differentiable, is
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0%
0
0%
1
0%
2
0%
3
If
f
: R → R is a function such that
f
(
x
+ y) =
f
(
x
) +
f
(y), ∀
x
, y ϵ R. If
f
(
x
) is differentiable at
x
= 0, then
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f(x) is differentiable only in a finite interval containing zero
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f(x) is continuous, ∀ x ϵ R
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f'(x) is constant, ∀ x ϵ R
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f(x) is differentiable except at finitely many points
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f(x) is continuous at x = - π/2
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f(x) is differentiable at x = 1
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f(x) is differentiable at x = -3/2
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All of the above
If
f
(
x
) = p |sin
x
| + qe
|
x
|
+ r |
x
|
3
and it is differentiable at
x
= 0 then
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p = 0, q = 0 and r = 0
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p + q = 0 and r is any real number
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p + q + r = 0
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-p + q - r = 0
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