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JEE Questions for Maths Properties Of Triangle Quiz 2 - MCQExams.com
JEE
Maths
Properties Of Triangle
Quiz 2
The area of the ∆ ABC, in which a = 1, b = 2, ∠C = 60
o
, is
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0%
4 sq units
0%
1/2 sq units
0%
√3/2 sq units
0%
√3 sq units
In a ∆ABC, b = √3, c = 1 and ∠A = 30
o
, then the largest angle of the triangle is
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0%
60o
0%
135o
0%
90o
0%
120o
The angles of a triangle are in the ratio 3 : 5 : 10. Then, the ratio of the smallest side to the greatest side is
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0%
1 : sin 10o
0%
1 : 2 sin 10o
0%
1 : cos 10o
0%
1 : 2 cos 10o
If sin A : sin B : sin C = 3 : 4 : 5, then cos A : cos B is equal to
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0%
4 : 3
0%
5 : 3
0%
3 : 4
0%
3 : 5
If two angles of a triangle are 45
o
and tan
-1
(2), then the third angle is
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0%
60o
0%
75o
0%
tan-1 3
0%
90o
If ∆ = a
2
- (b - c)
2
, where ∆ is the area of ∆ABC, then tan A is equal to
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0%
15/16
0%
8/17
0%
8/15
0%
1/2
0%
11/15
If in a ∆ABC, a = 5, b = 4, A = π/2 + B, then C
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0%
is tan-1 (1/2)
0%
is tan-1 (9/40)
0%
cannot be evaluated
0%
is tan-1 (1/9)
0%
is 2 tan-1 (1/40)
In a ∆ABC, a (cos
2
B + cos
2
C ) + cos A (c cos C + b cos B) is equal to
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0%
a
0%
b
0%
c
0%
a + b + c
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0%
a
0%
b
0%
c
0%
0
Two sides of a triangle are given by the roots of the equations
x
2
- 5
x
+ 6 = 0 and the angle between the sides is π/3. Then, the perimeter of the triangle is
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0%
5 + √2
0%
5 + √3
0%
5 + √5
0%
5 + √7
If a, b and c are the sides of a triangle such that a
4
+ b
4
+ c
4
= 2c
2
(a
2
+ b
2
), then the angles opposite to the side c is
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0%
45o or 90o
0%
30o or 135o
0%
45o or 135o
0%
60o or 120o
If in a ∆ABC, r
1
= 2r
2
= 3 and r
2
= 6, then a equals
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0%
4
0%
1
0%
2
0%
3
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0%
right angled
0%
isosceles
0%
equilateral
0%
None of these
In a ∆ABC, if a = 3, b = 4, c = 5, then the distance between iis incentre and circumcentre is
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0%
1/2
0%
√3/2
0%
3/2
0%
5/2
0%
√5/2
In an equilateral triangle of side 2√3 cm, the circumradius e is
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0%
1 cm
0%
√3 cm
0%
2 cm
0%
2√3 cm
0%
4 cm
In ∆ABC, ∠A = π/2, b = 4, c = 3, then the value of R/r is
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0%
5/2
0%
7/2
0%
9/2
0%
35/24
In ∆ABC with usual notation, observe the two statements given below I . rr
1
r
2
r
3
= ∆
2
II. r
1
r
2
+ r
2
r
3
+ r
3
r
1
= s
2
Which of the following is correct?
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0%
Both I and II are correct
0%
I and II are incorrecty
0%
I is incorrect, II is correct
0%
I is correct, II is correct
In a triangle, if r
1
+ r
3
= k cos
2
B/2, then k is equal to
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0%
R
0%
2R
0%
3R
0%
4R
If PQR be a triangle of area ∆ with a = 2, b = 7/2 and c = 5/2, where a, b and c are the lengths of the sides of the triangle opposite to the angles at P, Q and R, respectively.
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0%
3/4∆
0%
45/4∆
0%
(3/4∆)2
0%
(45/4∆)5
Let p, q and r be the sides opposite to the angles P ,Q,R respectively in a ∆ PQR. If r
2
sin P sin Q = pq, then the triangle is
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0%
equilateral
0%
acute angled but not equilateral
0%
obtuse angled
0%
right angled
Let ABC be a triangle such that ∠ACB = π/6 and let a, b and 6 c denote the lengths of the sides opposite to A, B and C respectively. The value(s) of
x
for which a =
x
2
+
x
+ 1, b =
x
2
- 1 and c = 2
x
+ 1 is (are )
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0%
-(2 + √3)
0%
1 + √3
0%
2 + √3
0%
4√3
If angles A, B and C are in AP, then (a + c)/b is equal to
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0%
0%
2)
0%
0%
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0%
a2 + b2 - c2
0%
C2 + a2 - b2
0%
b2 - a2 - c2
0%
c2 - a2 - b2
The sides BC, CA and AB of a ∆A BC are of lengths a, b and c, respectively. If D is the mid-point of BC and AD is perpendicular to AC, then the value of cos A cos C is
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0%
0%
2)
0%
0%
If one side of a triangle is double the other and the angles opposite to these sides differ by 60°, then the triangle is
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0%
obtuse angled
0%
acute angled
0%
isosceles
0%
right angled
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0%
0%
2)
0%
0%
0%
In a ∆ABC , if ∠ A = 60° , a = 5, b = 4, then c is a root of the equation
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0%
c2 - 5c - 9 = 0
0%
c2 - 4c - 9 = 0
0%
c2 - 10c + 25
0%
c2 - 5c - 41 = 0
0%
c2 - 4c - 41 = 0
In ∆ABC, a = 2, b = 3, and sin A = 2/3 , then B is equal to
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0%
30o
0%
60o
0%
90o
0%
120o
In a ∆ABC, if sin A sin B = ab/ c
2
, then the triangle is
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0%
equilateral
0%
isosceles
0%
right angled
0%
obtuse angled
If a = 2√2 , b = 6, A = 45
o
, then
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0%
no triangle is possible
0%
one triangle is possible
0%
two triangles are possible
0%
either no triangle or two triangles are possible
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