Explanation
Since A ⊆ A. Relation ‘⊆’ is reflexive.
Since A ⊆ B, B ⊆ C ⇒A ⊆ C
Relation ‘⊆’ is transitive.
But A ⊆ B, ⇒B ⊆ A, Relation is not symmetric
Let A = {1,2,3} and R = {(1,1), (1,2)},
S = {(2, 2), (2, 3)} be transitive relations on A.
Then R U S = {(1, 1); (1,2); (2,2), (2,3)}
Obviously R U S is not transitive. Since (1, 2) ϵ R U S and (2, 3) ϵ R U S but (1, 3) ∉
R U S
Hence 2m = 2n + 112 is given ⇒ 2n(2m–n – 1) = 24 × 7 ⇒ n = 4 and 2m–n – 1 = 7 ⇒ n = 4 and 2m–4 = 8 ⇒ n = 4 and m = 7
X U {3, 4} – {3, 4} = {1, 2, 5, 6} is the smallest set
R = {(2, 2), (3, 5), (4, 10), (5, 17), (6, 25)}
(1, 2) ∈ R but (1, 2) ∉ (a) or (2) or (3)
f is not defined for –4 ≤ x ≤ 3 and g is not defined for x2 – 16 ≤ 0 i.e. f and g are not defined on [–4, 3]
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