Explanation
Here both the equations are perpendicular to each other. So, under the given condition it is clear that angle is 90o.
x2 + xy – 12y2 = 0
⇒ x2 + 4xy – 3xy – 12y2 = 0
⇒ (x + 4y) (x – 3y) = 0
Therefore separate equations for the lines are
x + 4y = 0 and x – 3y = 0
From options, proceed as to find the equation represented by them a(b – c) x – c (a – b) y = 0 and x – y = 0
We have to check for each equation separately. Option (d) cannot be because it is a circle.Considering option (a) Δ ≠ 0, option (b) Δ ≠ 0 and for option (c) Δ = 0
Equation of lines are (px + qy)(py – qx) = 0
Hence , one lines is px + qy = 0
The equation of lines represented by the equation 3x2 – 8xy + 5y2 = 0 are 3x – 5y = 0 and x – y = 0.Therefore, equation of lines passing through (1, 2) and perpendicular to given lines are x + y – 3 = 0 and 5x + 3y – 11 = 0.
f (x, y) = 0 gives us an equation Δ = 0 gives us a pair of straight lines, h2 = ab gives angle between them equal to zero. Hence equation represents two parallel lines.
It is obvious.
The joint equation of the given lines is (x + y – 1) (x – y – 4) = 0
In this case coefficient of x2 and y2 are interchanged and sign of h is changed.
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