Explanation
It is obvious.
Two sides x – 3y = 0 and 3 x + y = 0 of the given triangle are perpendicular to each other. Therefore its orthocentre is the point of intersection of x – 3y = 0 and 3x + y = 0 i.e., (0,0). Clearly (0,0) satisfies 3x – 4y = 0.
|x| + |y| = 1.
Trick : Cleary, lengths of perpendicular from (0,0) on the given lines are each equal to 2.
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