Explanation
The mutual inductance of two coils is maximum, when there is minimum leakage of magnetic flux. In situation (i), magnetic flux linked with one coil threads fully through the other coil. Therefore, mutual inductance is
maximum.
Here, L and C are in parallel. When frequency of power supply is equal to the resonant frequency of the circuit, resonance occurs. In the parallel resonance circuit, current becomes zero. Therefore, ammeter A3 reads
zero amperes.
When switch S is closed, current in coil P increases in clockwise direction. Induced current in Q must oppose this increase, as per Lenz’s law. Therefore, induced current in Q i.e. IQ1 must be anticlockwise.
When switch S is opened, current in coil P decrease, Induced current in Q opposes this decrease, as per Lenz’s law. Therefore, induced current in Q is IQ2 must be clockwise,
Mutual inductance of the pair of coils depends on relative position and orientation of the two coils. This is in addition to other factors not given in the alternatives .
Polarity of e.m.f will be opposite in the two cases while the magnet enters the coil and while the magnet leaves the coil. As polarity is changing only in option (b), therefore, (b) must be the correct option.
The phase difference between the alternating current and alternating e.m.f. in RL circuit lies between 0 and π/2.
Since the magnetic field uniform, hence there is no change in the magnetic flux linked with cylindrical wire and hence no current will be induced on the surface of cylindrical wire.
As N pole of magnet approaches the coil from left, induced e.m.f is such that north pole develops on left end. Induced e.m.f is zero when the entire magnet moves within the coil. As N pole of magnet leaves the coil from right end, induced e.m.f is such that south pole developes on right end of the coil.
As S pole of magnet reenters the coil from right, induced e.m.f is such that S pole developes on right end. Induced e.m.f. is zero when the entire magnet moves within the coil. As S pole of magnet leaves the coil from left end, induced e.m.f is such that north pole developes on left end of the coil. Therefore the time variation of the magnitude of e.m.f generated across the coil during one cycle is represented correctly in Fig (d)
As coil A is moved closer to B, field due to A intercepting B is increasing. Induced current in B must oppose this increase. Hence the current in B must be anticlockwise.
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