Explanation
As nuclear density is constant, therefore, mass ∝ volume i.e m ∝ V.
Isotones contain the same number of neutrons i.e. (A – Z) must be same. For 34Se74 (A – Z) = 74 – 34 = 40 For 31Ga71, (A – Z) = 71 – 31 = 40 Choice (a) is correct.
Fission of nuclei is possible, because at high mass numbers, binding energy per nucleon decreases with mass number.
T.E. = 3.4 eV Let K.E. = x ∴ P.E. = -2x As T.E. = K.E + P.E. Therefore, - 3.4 = x – 2x = -x x = 3.4 eV
In nuclear reactions, number of fundamental particles is not conserved.
During fusion, binding energy of daughter nucleus is always greater than the total binding energy of parent nucleus. The difference of binding energies is released i.e.
Q = E2 - 2E1
Helium atom has 2 electrons. When one electron is removed, the remaining atom is hydrogen like atom, whose energy in first orbit is
E1 = - (2)2 (13.6eV) = -54.4 eV.
Therefore, to remove the second electron from the atom, an additional energy of 54.4 eV is required. Hence, total energy required to remove both the electrons = 24.6 + 54.4 = 79.0 eV.
According to conservation of momentum
Balmer series lies in the visible region.
In the spectral series of the hydrogen atom, Lyman series is in the ultraviolet region, Balmer series is in the visible region, Paschen, Brackett and Pfund are in the infrared region of the electromagnetic spectrum.
The absorption lines are obtained when the electron jumps from ground state (n = 1) to the higher energy states. Thus only, 2 and 3 lines will he obtained
In hydrogen atom, the lowest orbit (n = 1) corresponds to minimum energy (– 13.6 eV)
When an electron jumps from the orbit of lower energy (n = 1) to the orbit of higher energy (n = 3), energy is absorbed.
Energy required to ionise helium atom = 24.6 eV
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