JEE Questions for Physics Current Electricity I Quiz 10 - MCQExams.com

In the figure given the value of X resistance will be, when the p.d. between B and D is zero
Physics-Current Electricity I-65153.png
  • 4 ohm
  • 6 ohm
  • 8 ohm
  • 9 ohm
The effective resistance between points A and B is
Physics-Current Electricity I-65155.png
  • 10 Ω
  • 20 Ω
  • 40 Ω
  • None of the above three values
Five resistors of given values are connected together as shown in the figure. The current in the arm BD will be
Physics-Current Electricity I-65157.png
  • Half the current in the arm ABC
  • Zero
  • Twice the current in the arm ABC
  • Four times the current in the arm ABC
In the network shown in the figure, each of the resistance is equal to 2 Ω. The resistance between the points A and B is
Physics-Current Electricity I-65158.png
  • 1 Ω
  • 4 Ω
  • 3 Ω
  • 2 Ω
In the arrangement of resistances shown below, the effective resistance between points A and B is
Physics-Current Electricity I-65160.png
  • 20 Ω
  • 30 Ω
  • 90 Ω
  • 110 Ω
In the circuit given E = 6.0 V, R1 = 100 ohm, R2 = R3 = 50 ohm, R4 = 75 ohm. The equivalent resistance of the circuit , in ohm,is
  • 11.875
  • 26.31
  • 118.75
  • None of these
In the given figure, when galvanometer shows no deflection, the current (in ampere) flowing through 5 Ω resistance will be
Physics-Current Electricity I-65163.png
  • 0.5
  • 0.6
  • 0.9
  • 1.5
Five equal resistances each of value R are connected in a form shown alongside. The equivalent resistance of the network
Physics-Current Electricity I-65165.png
  • Between the points B and D is R
  • Between the points B and D is R/2
  • Between the points A and C is R
  • Between the points A and C is R/2
In the circuit shown below the resistance of the galvanometer is 20 Ω. In which of the following alternatives are the currents arranged strictly in the decreasing order
Physics-Current Electricity I-65167.png
  • i, i1, i2, ig
  • i, i2, i1, ig
  • i, i2, ig, i1
  • i, i1, ig, i2
Potential difference between the points P and Q in the electric circuit shown is
Physics-Current Electricity I-65169.png
  • 4.5 V
  • 1.2 V
  • 2.4 V
  • 2.88 V
The current in a simple series circuit is 5.0 amp. When an additional resistance of 2.0 ohm is inserted, the current drops to 4.0 amp. The original resistance of the circuit in ohm was
  • 1.25
  • 8
  • 10
  • 20
In a typical Wheatstone network, the resistances in cyclic order are A = 10 Ω, B = 5Ω, C = 4 Ω and D = 4 Ω. For the bridge to be balanced
Physics-Current Electricity I-65172.png
  • 10 Ω should be connected in parallel with A
  • 10 Ω should be connected in series with A
  • 5 Ω should be connected in series with B
  • 5 Ω should be connected in parallel with B
Thirteen resistances each of resistance R ohm are connected in the circuit as shown in the figure below. The effective resistance between A and B is
Physics-Current Electricity I-65174.png
  • 2R Ω
  • 2)
    Physics-Current Electricity I-65175.png

  • Physics-Current Electricity I-65176.png
  • RΩ
An unknown resistance R1 is connected in series with a resistance of 10 Ω. This combinations is connected to one gap of a metre bridge while a resistance R2 is connected in the other gap. The balance point is at 50 cm. Now, when the 10 Ω resistance is removed the balance point shifts to 40 cm. The value of R1 is (in ohm)
  • 40
  • 20
  • 60
  • 10
A wire has a resistance of 6 Ω It is cut into two parts and both half values are connected in parallel. The new resistance is
  • 12Ω
  • 1.5Ω
  • 3Ω
  • 6Ω
Six equal resistances are connected between points P, Q and R as shown in the figure. Then, the net resistance will be maximum between
Physics-Current Electricity I-65180.png
  • P and Q
  • Q and R
  • P and R
  • Any two points
The total current supplied to the circuit by the battery is
Physics-Current Electricity I-65182.png
  • 1 A
  • 2 A
  • 4 A
  • 6 A
An electric current is passed through a circuit containing two wires of the same material, connected in parallel. If the lengths and radii of the wires are in the ratio of 4/3 and 2/3, then the ratio of the currents passing through the wire will be
  • 3
  • 1/3
  • 8/9
  • 2
If a rod has resistance 4 Ω and if rod is turned as half circle, then the resistance along diameter
  • 1.56 Ω
  • 2.44 Ω
  • 4 Ω
  • 2 Ω
A parallel combination of two resistors of 1 Ω each, is connected in series with a 1.5 Ω resistor. The total combination is connected across a 10 V battery. The current flowing in the circuit is
  • 5 A
  • 20 A
  • 0.2 A
  • 0.4 A
In the circuit shown, the current through 8 ohm is same before and after connecting E. The value of E is
Physics-Current Electricity I-65187.png
  • 12 V
  • 6 V
  • 4 V
  • 2 V
In the adjoining circuit, the battery E1 has an e.m.f. of 12 volt and zero internal resistance while the battery E has an e.m.f. of 2 volt. If the galvanometer G reads zero, then the value of the resistance X in ohm is
Physics-Current Electricity I-65189.png
  • 10
  • 100
  • 500
  • 200
A battery of e.m.f E produces currents I1 and I2 when external resistances R1 and R2 internal resistance of the battery is

  • Physics-Current Electricity I-65191.png
  • 2)
    Physics-Current Electricity I-65192.png

  • Physics-Current Electricity I-65193.png

  • Physics-Current Electricity I-65194.png
By a cell a current of 0.9 A flows through 2 ohm resistor and 0.3 A through 7 ohm resistor. The internal resistance of the cell is
  • 0.5 Ω
  • 1.0 Ω
  • 1.2 Ω
  • 2.0 Ω
Two cells, each of e.m.f. E and internal resistance r are connected in parallel between the resistance R. The maximum energy given to the resistor will be, only when
  • R = r/2
  • R = r
  • R = 2r
  • R = 0
Kirchhoff s second law is based on the law of conservation of
  • Charge
  • Energy
  • Momentum
  • Sum of mass and energy
The potential difference across the terminals of a battery is 50 V when 11A current is drawn and 60 V when 1A current is drawn. The e.m.f. and the internal resistance of the battery are
  • 62 V, 2 Ω
  • 63 V, 1 Ω
  • 61 V, 1 Ω
  • 64 V, 2 Ω
In the circuit shown, A and V are ideal ammeter and voltmeter respectively. Reading of the voltmeter will be
Physics-Current Electricity I-65199.png
  • 2 V
  • 1 V
  • 0.5 V
  • Zero
A 5 V battery with internal resistance 2 Ω and a 2 V battery with internal resistance 1 Ω are connected to a 10 Ωresistor as shown in the figure. The current in the 10 SI resistor is
Physics-Current Electricity I-65200.png
  • 0.03 A P1 to P2
  • 0.03 A P2 to P1
  • 0.27 A P1 to P2
  • 0.27 A P2 to P1
A primary cell has an e.m.f. of 1.5 volt, when short-circuited it gives a current of 3 ampere. The internal resistance of the cell is
  • 4.5 ohm
  • 2 ohm
  • 0.5 ohm
  • 1/4.5 Ω
A new flashlight cell of e.m.f. 1.5 volt gives a current of 15 amp, when connected directly to an ammeter of resistance 0.04 Ω. The internal resistance of cell is
  • 0.04 Ω
  • 0.06 Ω
  • 0.10 Ω
  • 10 Ω
Calculate the value of E, for given circuit, when value of 2 amp current is either flowing in clockwise or anticlockwise direction
Physics-Current Electricity I-65204.png
  • 3 V, 28 Volt
  • 38 V, 2 Volt
  • 3 V, 30 Volt
  • 3 V, 2.8 Volt
Three identical resistances A, B and C are connected as shown in fig.
The heat produced will be maximum
Physics-Current Electricity I-65206.png
  • In B
  • In B and C
  • In A
  • Same for A, B and C
To get the maximum current from a parallel combination of n identical cells each of internal resistance r and external resistance R, when
  • R >> r
  • R << r
  • R = r
  • None of these
The internal resistances of two cells shown are 0.1 Ω and 0.3 Ω. If R = 0.2 Ω, the potential difference across the cell
Physics-Current Electricity I-65209.png
  • B will be zero
  • A will be zero
  • A and B will be 2V
  • A will be > 2V and B will be < 2V
A torch battery consists of two cells of 1.45 volt and an internal resistance 0.15 Ω. If each cell sends current through the filament of the lamps having resistance 1.5 ohm, the value of current will be
  • 16.11 amp
  • 1.611 amp
  • 0.1611 amp
  • 2.6 amp
The electromotive force of a primary cell is 2 volt. When it is short-circuited it gives a current of 4 ampere. Its internal resistance in ohm is
  • 0.5
  • 5.0
  • 2.0
  • 8.0
The figure shows a network of currents. The magnitude of currents is shown here. The current i will be
Physics-Current Electricity I-65213.png
  • 3 A
  • 13 A
  • 23 A
  • –3 A
A battery of e.m.f. E and internal resistance r is connected to a variable resistor R as shown here. Which one of the following is true?
Physics-Current Electricity I-65214.png
  • Potential difference across the terminals of the battery is maximum when R = r
  • Power delivered to the resistor is maximum when R = r
  • Current in the circuit is maximum when R = r
  • Current in the circuit is maximum when R >>r
Two cells having the internal resistance 0.2 Ω. and 0.4 Ω are connected in parallel. The voltage across thebattery terminal is 1.5 Volt. The e.m.f. of first cell is 1.2 Volt. The e.m.f. of the second cell is
  • 2.7 Volt
  • 2.1 Volt
  • 3 Volt
  • 4.2 Volt
A current of 6 A enters one corner P of an equilateral triangle PQR having 3 wires of resistances 2 Ω each and leaves by the corner R. Then, the current I1 and I2 are
Physics-Current Electricity I-65216.png
  • 2 A, 4 A
  • 4 A, 2 A
  • 1 A, 2 A
  • 2 A, 3 A
A current of two ampere is flowing through a cell of e.m.f. 5 volt and internal resistance 0.5 ohm from negative to positive electrode. If the potential of negative electrode is 10 V, the potential of positive electrode will be
  • 5 V
  • 14 V
  • 15 V
  • 16 V
100 cells each of e.m.f. 5 V and internal resistance 1 ohm are to be arranged so as to produce maximum current in a 25 ohm resistance. Each row is to contain equal number of cells. The number of rows should be
  • 2
  • 4
  • 5
  • 10
If six identical cells each having an e.m.f. of 6V are connected in parallel, the e.m.f. of the combination is
  • 1 V
  • 36 V

  • Physics-Current Electricity I-65220.png
  • 6 V
Consider the circuit shown in the figure. The current I3is equal to
Physics-Current Electricity I-65222.png
  • 5 amp
  • 3 amp
  • –3 amp
  • –5/6 amp
If VAB = 4V in the given figure, then resistance X will be
Physics-Current Electricity I-65224.png
  • 5Ω
  • 10Ω
  • 15Ω
  • 20Ω
Two resistances R1 and R2are joined as shown in the figure to two batteries of e.m.f. E1 and E2. If E2is short-circuited, the current through R1 is
Physics-Current Electricity I-65226.png
  • E1 /R1
  • E2/R1
  • E2/R2
  • E1 / (R2 + R1)
A storage battery has e.m.f. 15 volt and internal resistance 0.05 ohm. Its terminal voltage when it is delivering 10 ampere is
  • 30 volt
  • 1.00 volt
  • 14.5 volt
  • 15.5 volt
The number of dry cells, each of e.m.f. 1.5 volt and internal resistance 0.5 ohm that must be joined in series with a resistance of 20 ohm so as to send a current of 0.6 ampere through the circuit is
  • 2
  • 8
  • 10
  • 12
E.m.f is most closely related to
  • Mechanical force
  • Potential difference
  • Electric field
  • Magnetic field
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