JEE Questions for Physics Current Electricity I Quiz 4 - MCQExams.com

A certain current on passing through a galvanometer produces a deflection of 100 divisions. When a shunt of one ohm is connected, the deflection reduces to 1 division. The galvanometer resistance is
  • 100Ω
  • 99Ω
  • 10Ω
  • 9.9Ω
To convert a Moving Coil Galvanometer (MCG) into a voltmeter
  • a high resistance R is connected in parallel with MCG
  • a low resistance r is connected in parallel with MCG
  • a low resistance r is connected in series with MCG
  • a high resistance R is connected in series with MCG
In a potentiometer, the null point is received at 7th wire. If now we have to change the null point at 9th wire, what should we do?
  • Attach resistance in series with battery
  • Increase resistance in main circuit
  • Decrease resistance in main circuit
  • Decrease applied emf
A galvanometer coil has a resistance of 15 Ω and gives full scale deflection for a current of 4 mA. To convert it to an ammeter of range 0 to 6 A
  • 10 mΩ resistance is to be connected in parallel to the galvanometer
  • 10 mΩ resistance is to be connected in series with the galvanometer
  • 0.1 Ω resistance is to be connected in parallel to the galvanometer
  • 0.1 Ω resistance is to be connected in series with the galvanometer
A resistance of 2 Ω is connected across one gap of a meter bridge (the length of the wire is 100 cm) and an unknown resistance, greater than 2 Ω, is connected across the other gap. When these resistances are interchanged, the balance point shifts by 20 cm. Neglecting any corrections, the unknown resistance is
  • 3Ω
  • 4Ω
  • 5Ω
  • 6Ω
To decrease the range of an ammeter, its resistance need to be increased. An ammeter has resistance R0 and range I. Which of the following resistance can be connected in series with it to decreases its range to I/n ?

  • Physics-Current Electricity I-64625.png
  • 2)
    Physics-Current Electricity I-64626.png

  • Physics-Current Electricity I-64627.png
  • None of these
An ammeter reads upto 1A. Its internal resistance is 0.81Ω. To increase the range to 10 A the value of the required shunt is
  • 0.03Ω
  • 0.3Ω
  • 0.9Ω
  • 0.09Ω
In the Wheatstone's network given, P =10Ω , Q = 20 Ω, R =15Ω, S = 30Ω, the current passing through the battery (of negligible internal resistance) is
Physics-Current Electricity I-64630.png
  • 0.36 A
  • zero
  • 0.18 A
  • 0.72 A
A potentiometer wire, 10 m long, has a resistance of 40Ω. It is connected in series with a resistance box and a 2V storage cell. If the potential gradient along the wire is (0.1 mVcm-1 ), the resistance unplugged in the box is
  • 260 Ω
  • 760 Ω
  • 960 Ω
  • 1060 Ω
  • 1160 Ω
A galvanometer of resistance 20Ω shows a deflection of 10 divisions when a current of 1 mA is passed through it. If a shunt of 4 Ω is connected and there are 50 divisions on the scale, the range of the galvanometer is
  • 1 A
  • 3 A
  • 10 mA
  • 30 A
  • 30 mA

Physics-Current Electricity I-64634.png
  • 4 , 2
  • 2 , 4
  • Both (and (2)
  • Neither (nor (2)
The resistance of a galvanometer coil is R, then the shunt resistance required to convert it into a ammeter of range 4 times, will be
  • 4R
  • R/3
  • R/4
  • R/5
In a meter bridge experiment, null point is obtained at 20 cm from one end of the wire when resistance X is balanced against another resistance Y. If X < Y, then where will be the new position of the null point from the same end, if one decides to, balance a resistance of 4X against Y ?
  • 50 cm
  • 80 cm
  • 40 cm
  • 70 cm
A moving coil galvanometer of resistance 100 Ω is used as an ammeter using a resistance 0.1Ω. The maximum deflection current in the galvanometer is 100 μA. Find the minimum current in the circuit so that, the ammeter shows maximum deflection
  • 100.1 mA
  • 1000.1 mA
  • 10.01 mA
  • 1.01 mA
A moving coil galvanometer has 150 equal divisions. Its current sensitivity is 10 divisions per milliampere and voltage sensitivity is 2 divisions per millivolt. In order that each division reads 1V, the resistance in Ohm's needed to be connected in series with the coil will be
  • 103
  • 105
  • 99995
  • 9995
A solenoid is at potential difference of 60 V and current flowing through it is 15 ampere, then the resistance of coil will be
  • 4 Ω
  • 8 Ω
  • 0.25 Ω
  • 2 Ω
If an ammeter is to be used in place of a voltmeter, then we must connect with the ammeter a
  • low resistance in parallel
  • high resistance in parallel
  • high resistance in series
  • low resistance is series
The current I and voltage V graphs for a given metallic wire at two different temperatures T1and T2 are shown in the fig. It is concluded that
Physics-Current Electricity I-64640.png
  • T1 > T2
  • T1 < T< sub>2
  • T1 = T2
  • T1 = 2T1
As the switch S is closed in the circuit shown in Fig., current passed through it is
Physics-Current Electricity I-64641.png
  • zero
  • 1A
  • 2 A
  • 1.6 A
Variation of current passing through a conductor as the voltage applied across its ends as varied is shown in the adjoining Fig. If the resistance is determined at the points A, B, C and D, we will find that
Physics-Current Electricity I-64642.png
  • resistance at C and D are equal
  • resistance at B is higher than at A
  • resistance at C is higher than at B
  • none of the above.
A 4 ohm resistance wire is bent through 180o at its mid point and the two halves are twisted together. Then the resistance is
  • 1 Ω
  • 2 Ω
  • 5 Ω
  • 8 Ω
The steady state current in a 2 Ω resistor when the internal resistance of the battery is negligible and the capacitance of the condenser is 0.1 µF is
Physics-Current Electricity I-64645.png
  • 0.6 A
  • 0.9 A
  • 1.5 A
  • 0.3 A
Find the resistance of a circuit between A and B in the Fig. below
Physics-Current Electricity I-64647.png
  • 3 R
  • R/3
  • 3R/2
  • 2R/3
In the circuit shown in Fig. which of the following statement is correct?
Physics-Current Electricity I-64648.png
  • pot. diff. across R is 10 V
  • pot. diff. across the middle resistance is 15 V
  • current through 20 Ω resistance is 1 A
  • resistance R = 16 Ω
In the circuit shown in Fig. the point F is grounded. Which of the following is wrong statement?
Physics-Current Electricity I-64649.png
  • D is at 5 V
  • E is at zero potential
  • The current in the circuit will be 0.5 A
  • The potential at E is same whether or not F is gounded
The current in the fig.
Physics-Current Electricity I-64650.png

  • Physics-Current Electricity I-64651.png
  • 2)
    Physics-Current Electricity I-64652.png

  • Physics-Current Electricity I-64653.png

  • Physics-Current Electricity I-64654.png
Current passing through 1 Ω resistance is zero. Then the emf E is
Physics-Current Electricity I-64655.png
  • 8 V
  • 10 V
  • 6 V
  • 16 V
Two cells with the same e.m.f E and different internal resistances r1 and r2 are connected in series to an external resisance R.A value for R be selected such that the p.d. at the first cell should be zero, when
Physics-Current Electricity I-64656.png

  • Physics-Current Electricity I-64657.png
  • 2)
    Physics-Current Electricity I-64658.png

  • Physics-Current Electricity I-64659.png

  • Physics-Current Electricity I-64660.png

Physics-Current Electricity I-64662.png
  • (i) alone
  • (ii) alone
  • (ii) and (iii)
  • (i), (ii) and (iii)
Two resistances R1 and R2 are joined as shown in fig., to two batteries of e.m.f. E1 and E2. If E2 is short circuited the current through R1 is
Physics-Current Electricity I-64664.png
  • E1/R1
  • E2/R1
  • E2/R2
  • E1/(R1+R2)
The circuit shows (Fig.) the cell is ideal with e.m.f.=15V, each resistance is of 3Ω. The potential difference across the capacitor is
Physics-Current Electricity I-64665.png
  • Zero
  • 9 V
  • 12 V
  • 15 V
In the circuit shown below the readings of the ammeter and voltmeter are
Physics-Current Electricity I-64667.png
  • 6A, 60 V
  • 0.6 A, 6V
  • 6A, 6V

  • Physics-Current Electricity I-64668.png
In the circuit, shown in Fig. If the potential at B, VB = 0, then potential at A and D are
Physics-Current Electricity I-64670.png
  • VA = – 1.5 V, VD = + 2 V
  • VA = + 1.5 V, VD = + 0.5V
  • VA= + 1.5 V, VD = + 2V
  • VA = + 1.5 V, VD = – 0.5 V
If the ammeter in the given circuit reads 2A, the resistance R is
Physics-Current Electricity I-64672.png
  • 1 Ω
  • 2 Ω
  • 3 Ω
  • 4 Ω
A 6 volt battery is connected to the terminals of a three metre long wire of uniform thickness and resistance of 100 ohm. The difference of potential between two points on the wire separated by a distance of 50 cm will be
  • 2 volt
  • 3 volt
  • 1 volt
  • 15 volt
Resistances n, each of r ohm, when connected in parallel give an equivalent resistance of R ohm. If these resistances were connected in series, the combination would have a resistance in ohm, equal to
  • n2 R
  • R/n2
  • R/n
  • n/R
In the circuit Fig. E = 6.0 V, R1 = 100 Ω, R2 = R3 50Ω, R4 = 75Ω. The equivalent resistance of the circuit in ohm, is
Physics-Current Electricity I-64675.png
  • 11.875
  • 26.31
  • 118.75
  • none of these
A uniform wire of resistance 36 ohm is bent in the form of a circle. The effective resistance across the points A and B is
Physics-Current Electricity I-64677.png
  • 5Ω
  • 6 Ω
  • 7.2 Ω
  • 30 Ω
In, the given circuit R1 = 20 Ω, R2 = 40 Ω, R3 = 60 Ω, R4 = 180 Ω, C = 5µF and E = 6 volt. The switch S has been closed for a long time. What is the charge on the capacitor ?
Physics-Current Electricity I-64679.png
  • zero
  • 2.5 µC
  • 5 µC
  • 10 µC
A part of circuit shown in Fig. the potential difference across A and B is
Physics-Current Electricity I-64681.png
  • 7 V
  • 11 V
  • 14 V
  • 15 V
Voltmeter has a resistance of 20 kΩ. When it is connected in series with a resistance R across a 230 V supply, it reads 200 V. what is the value of R ?
  • 2 k Ω
  • 3 k Ω
  • 4 k Ω
  • 1 k Ω
The charge flowing in a conductor varies with time as Q= at – bt2, then the current
  • reaches a maximum and then decreases
  • falls to zero after t = a/ 2b
  • changes at the rate of (-2b)
  • will remain constant
Two cells of unequal emfs E1 and E2 and internal resistances r1 and r2 are joined as shown in fig. VP and VQ are the potential at P and Q respectively.
Physics-Current Electricity I-64685.png
  • The potential difference across both the cells will be equal
  • one cell will continuously supply energy to the other
  • the potential difference across one cell will be greater than its emf.

  • Physics-Current Electricity I-64686.png
The colours of the rings on a resistor are brown, yellow, green and gold as seen from the left to the right. The value of the resistance is
  • (1.4 ± 0.MΩ
  • (2.4 ± 0.MΩ
  • (3.4 ± 0.MΩ
  • (1.4 ± 0.MΩ
Two metallic rings A and B, identical in shape and size but having different resistivities ρA and ρB , are kept on top of two identical solenoids as shown in the figure. When current1 is switched on in both the solenoids in identical manner, the rings A and B jump to the heights hAand hB , respectively, with hA> hB .
The possible relation(s) between their resistivities and their masses mAand mB is (are)
Physics-Current Electricity I-64688.png
  • ρA > ρB and mA = mB
  • ρA < ρB and mA = mB
  • ρA > ρB and mA > mB
  • ρA< ρB and mA = mB
If the free electron density ben and relaxation time be T, the electrical conductivity of a conductor may be expressed as

  • Physics-Current Electricity I-64690.png
  • 2)
    Physics-Current Electricity I-64691.png

  • Physics-Current Electricity I-64692.png

  • Physics-Current Electricity I-64693.png
The plot represents the flow of current through a wire at three different times.
The ratio of charges flowing through the wire at different times is
Physics-Current Electricity I-64695.png
  • 2 : 1 : 2
  • 1 : 3 : 3
  • 2 : 3 : 4
  • 2 : 3 : 3
Which of the following set up can be used to verify the Ohm's law?

  • Physics-Current Electricity I-64696.png
  • 2)
    Physics-Current Electricity I-64697.png

  • Physics-Current Electricity I-64698.png

  • Physics-Current Electricity I-64699.png
In the given figure, the steady state current in the circuit is
Physics-Current Electricity I-64700.png
  • zero
  • 0.6 A
  • 0.9 A
  • 1.5 A
The current I drawn from the 5 V source will be
Physics-Current Electricity I-64702.png
  • 0.33 A
  • 0.5 A
  • 0.67 A
  • 0.17 A
0:0:1


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