JEE Questions for Physics Current Electricity I Quiz 5 - MCQExams.com

In the circuit (figure) the current is to be measured. The ammeter shown is a galvanometer with a resistance RG = 60.00Ω converted to an ammeter by a shunt resistance rs = 0.2Ω. The value of the current is
Physics-Current Electricity I-64704.png
  • 0.79 A
  • 0.29 A
  • 0.99 A
  • 0.8 A
Four resistence of 10 Ω, 60Ω, 100 Ω and 200Ω, respectively taken in order are used to form a Wheatstone's bridge. A 15 V battery is connected to the ends of a 200Ω resistance, the current through it will be
  • 7.5 × 10-5 A
  • 7.5 × 10-4 A
  • 7.5 × 10-3 A
  • 7.5 × 10-2 A
When a resistor of 11Ω is connected in series with an electric cell. The current flowing in it is 0.5 A. Instead when a resistor of 5Ω is connected to the same electric cell is series, the current increases by 0.4 A. The internal resistance of the cell is
  • 1.5Ω
  • 2Ω
  • 2.5Ω
  • 3.5Ω
In the following circuit reading of voltmeter V is
Physics-Current Electricity I-64708.png
  • 12 V
  • 8 V
  • 20 V
  • 16 V
Four cells, each of emf E and internal resistance r, are connected in series across an external resistance R. By mistake one of the cells is connected in reverse. Then, the current in the external circuit is

  • Physics-Current Electricity I-64710.png
  • 2)
    Physics-Current Electricity I-64711.png

  • Physics-Current Electricity I-64712.png

  • Physics-Current Electricity I-64713.png
A circuit consists of three batteries of emf E1 =1V, E2 = 2 V and E3 = 3 V and internal resistances 1 Ω, 2 Ω and 1 Ω respectively which are connected in parallel as shown in the figure. The potential difference between points P and Q is
Physics-Current Electricity I-64715.png
  • 1.0 V
  • 2.0 V
  • 2.2 V
  • 3.0 V
Two identical cells whether connected in parallel or in series gives the same current, when connected to an external resistance 1.5 Ω. Find the value of internal resistance of each cell
  • 1 Ω
  • 0.5 Ω
  • zero
  • 1.5 Ω
For the resistance network shown in the figure, choose the correct option(s).
Physics-Current Electricity I-64718.png
  • The current through PQ is zero
  • I1 = 3A
  • The potential as S is less than that at Q
  • I2 = 2A
In the circuit shown, the galvanometer G of resistance 60 Ω is shunted by a resistance r = 0.02 Ω. The current through R is nearly 1 A. The value of resistance R is (in ohms) is nearly
Physics-Current Electricity I-64720.png
  • 50 Ω
  • 100 Ω
  • 200 Ω
  • 400 Ω

Physics-Current Electricity I-64722.png
  • I, II and III
  • II and III
  • Only II
  • Only I
The maximum power dissipated in an external resistance R, when connected to a cell of emf E and internal resistance r, will be

  • Physics-Current Electricity I-64724.png
  • 2)
    Physics-Current Electricity I-64725.png

  • Physics-Current Electricity I-64726.png

  • Physics-Current Electricity I-64727.png
For the circuit shown in figure the potential difference between A and B will be (in volt)
Physics-Current Electricity I-64729.png
  • 2
  • 1.5
  • 1.0
  • zero
In the circuit given here, the points A, B and C are 70 V, 0V, 10 V respectively. Then,
Physics-Current Electricity I-64731.png
  • the point D will be at a potential of 60 V
  • the point D will be at a potential of 20 V
  • currents in the paths AD, DB and DC are in the ratio of 1 : 2 : 3
  • currents in the paths AD, DB and DC are in the ratio of 3 : 2 : 1
Two similar accumulators each of emf E and internal resistance rare connected as shown in the following figure. Then, the potential difference between x and y is
Physics-Current Electricity I-64733.png
  • 2E
  • E
  • zero
  • None of these
Calculate the value E for given circuit, when value of 2 A current is either flowing in clockwise or anti-clockwise direction.
Physics-Current Electricity I-64735.png
  • 32 V, 8 V
  • 38 V, 2 V
  • 32 V, 2 V
  • 30 V, 8 V
In the figure shown below, the terminal voltage across E2 is
Physics-Current Electricity I-64737.png
  • 12 V
  • 12.66 V
  • 11.34 V
  • 11.66 V
  • 12.33 V
Twelve wires of each of resistance 6Ω are connected to form a cube as shown in the figure. The current enters at a corner A and leaves at the diagonally opposite corner G. The joint resistance across the corners A and G are
Physics-Current Electricity I-64739.png
  • 12 Ω
  • 6 Ω
  • 3 Ω
  • 5 Ω
In the electric circuit shown each cell has an emf of 2 V and internal resistance of 1Ω. The external resistance is 2Ω. The value of the current I is (in ampere)
Physics-Current Electricity I-64741.png
  • 2
  • 1.25
  • 0.4
  • 1.2
The currents it and i2 through the resistors R1 (= 10Ω) and R2 (= 30 Ω) in the circuit diagram with E1 = 3 V, E2 = 3 V and E3 = 2 V are respectively
Physics-Current Electricity I-64743.png
  • 0.2 A, 0.1 A
  • 0.4 A, 0.2 A
  • 0.1 A, 0.2 A
  • 0.2 A, 0.4 A
A battery consists of a variable number (n) of identical cells, each having an internal resistance r connected in series. The terminals of the battery are short-circuited. A graph of current versus the number of cells will be as shown in figure.

  • Physics-Current Electricity I-64745.png
  • 2)
    Physics-Current Electricity I-64746.png

  • Physics-Current Electricity I-64747.png

  • Physics-Current Electricity I-64748.png
A current of 6 A enters one corner P of an equilateral triangle PQR having 3 wires of resistances 2Ω each and leaves by the corner R. Then, the currents I1 and I2 are
Physics-Current Electricity I-64750.png
  • 2A, 4A
  • 4 A, 2 A
  • 1 A, 2 A
  • 2 A, 3 A
The Kirchhoff's first law (∑i=and second law (∑iR = ∑E)
where the symbols have their usual meanings, are respectively based on
  • conservation of charge, conservation of momentum
  • conservation of energy, conservation of charge
  • conservation of momentum, conservation of charge
  • conservation of charge, conservation of energy
A cell of constant emf first connected to a resistance R1 and then connected to a resistance R2. If power delivered in both cases is same then the internal resistance of the cell is

  • Physics-Current Electricity I-64752.png
  • 2)
    Physics-Current Electricity I-64753.png

  • Physics-Current Electricity I-64754.png

  • Physics-Current Electricity I-64755.png
12 cells, each having emf E volts are connected in series and kept in a closed box. Some of these cells are wrongly connected with positive and negative terminals reversed. This 12 cells battery is connected in series with an ammeter, an external resistance R ohm and a 2 cell battery (two cells of the same type used earlier, connected perfectly in series).
The current in the circuit when the 12 cell battery and 2 cell battery aid each other is 3A and is 2A when they oppose each other. Then, the number of cells in 12 cell battery that are connected wrongly is
  • 4
  • 3
  • 2
  • 1
If the potential difference across the internal resistance r1 is equal to the emf E of the battery, then
Physics-Current Electricity I-64758.png
  • R = r1 + r2
  • 2)
    Physics-Current Electricity I-64759.png
  • R = r1 - r2

  • Physics-Current Electricity I-64760.png
The magnitude of I in ampere is
Physics-Current Electricity I-64762.png
  • 0.1
  • 0.3
  • 0.6
  • None of these
Two cells having emf 4 V, 2 V and internal resistances 1Ω, 1 Ω are connected as shown in the figure below. Current ' through 6Ω resistance is
Physics-Current Electricity I-64764.png

  • Physics-Current Electricity I-64765.png
  • 2)
    Physics-Current Electricity I-64766.png
  • 1 A

  • Physics-Current Electricity I-64767.png
A group of N cells whose emf varies directly with the internal resistance as per the equation EN =1.5 rN are connected as shown in the figure. The current I in the circuit is
Physics-Current Electricity I-64769.png
  • 5.1 A
  • 0.51 A
  • 1.5 A
  • 0.15 A
This equation has Statement I and Statement II of the four choices given after the statements, choose the one that best describes the two statements.
Statement I Higher the range, greater is the resistance of ammeter.
Statement II To increase the range of ammeter, additional shunt needs to be used across it.
  • Statement I is true, Statement II is true and Statement II is the correct explanation of Statement I
  • Statement I is true, Statement II is true, but Statement II is not the correct explanation of Statement I
  • Statement I is true, Statement II is false
  • Statement I is false, Statement II is true
A meter bridge is set up as shown in figure, to determine an unknown resistance X using a standard 10 Ω resistor. The galvanometer shows null point when tapping key is at 52 cm mark. The end-corrections are 1 cm and 2 cm respectively for the ends A and B. The determined value of X is
Physics-Current Electricity I-64771.png
  • 10.2Ω
  • 10.6Ω
  • 10.8Ω
  • 11.1Ω
In a potentiometer experiment, when three cells A, B and C are connected in series the balancing length is found to be 740 cm. If A and B are connected in series balancing length is 440 cm and for B and C connected in series that is 540 cm. Then, the emf of EA,EBand EC are respectively (in volts)
  • 1, 1.2 and 1.5
  • 1, 2 and 3
  • 1.5, 2 and 3
  • 1.5, 2.5 and 3.5
  • 1.2, 1.5 and 3.5
When a resistance of 100 Ω is connected in series with a galvanometer of resistance R, its range is V. To double its range, a resistance of 1000 Ω is connected in series. Find R.
  • 700Ω
  • 800Ω
  • 900Ω
  • 100Ω
A 2V battery, a 990 Ω resistor and a potentiometer of 2 m length, all are connected in series of the resistance of potentiometer wire is 10 Ω, then the potential gradient of the potentiometer wire is
  • 0.05 Vm-1
  • 0.5 Vm-1
  • 0.01 Vm-1
  • 0.1 Vm-1
The resistance of a galvanometer is 50 Ω and it shows full scale deflection for a current of 1 mA. To convert it into a voltmeter to measure 1 V and as well as 10 V (refer circuit diagram) the resistance R1 and R2 respectively are
Physics-Current Electricity I-64776.png
  • 950 Ω and 9150 Ω
  • 900 Ω and 9950 Ω
  • 900 Ω and 9900 Ω
  • 950 Ω and 9900 Ω
  • 950 Ω and 9950 Ω
Which statement is true?
I. Kirchhoff s law is equally applicable to both AC and DC.
II. Semiconductors have a positive temperature coefficient of resistance.
III. Meter bridge is greater sensitive when the resistance of all the four arms of the bridge are of the same order.
IV. The emf of a cell depends upon the size and area of electrodes.
  • I and IV
  • II and IV
  • III and IV
  • None of these
A meter bridge is used to determine the resistance of an unknown wire by measuring the balance point length l. If the wire is replaced by another wire of same material but with double the length and half the thickness, the balancing point is expected to be

  • Physics-Current Electricity I-64778.png
  • 2)
    Physics-Current Electricity I-64779.png

  • Physics-Current Electricity I-64780.png

  • Physics-Current Electricity I-64781.png
A cell can be balanced against 110 cm and 100 cm of potentiometer wire, respectively with and without being short circuited through a resistance of 10 Ω. Its internal resistance is
  • 1.0Ω
  • 0.5Ω
  • 2.0Ω
  • zero
A galvanometer of resistance 50 Ω is connected to a battery of 3V along with a resistance of 2950Ω in series. A full scale deflection of 30 divisions is obtained in the galvanometer. In order to reduce this deflection to 20 divisions, the resistance in series should be
  • 5050Ω
  • 5550Ω
  • 6050Ω
  • 4450Ω
In the circuit shown, if the 10Ω resistance is replaced by 20 Ω then what is the amount of current drawn from the battery?
Physics-Current Electricity I-64785.png
  • 2.5 A
  • 3 A
  • 3.5 A
  • 4 A
The resistance of an ammeter is 13 Ω and its scale is graduated for a current upto 100 A. After an additional shunt has been connected to this ammeter it becomes possible to measure currents upto 750 A by this meter. The value of shunt resistance is
  • 20Ω
  • 2Ω
  • 0.2Ω
  • 2kΩ
The relation between voltage sensitivity (σv ) and current sensitivity (σi) of a moving coil galvanometer is (resistance of galvanometer is G).

  • Physics-Current Electricity I-64787.png
  • 2)
    Physics-Current Electricity I-64788.png

  • Physics-Current Electricity I-64789.png

  • Physics-Current Electricity I-64790.png
The length of a wire of a potentiometer is 100 cm, and the emf of its stand and cell is E volt. It is employed to measure the emf of a battery whose internal resistance is 0.5 Ω. If the balance point is obtained at l = 30 cm from the positive end, the emf of the battery is

  • Physics-Current Electricity I-64792.png
  • 2)
    Physics-Current Electricity I-64793.png

  • Physics-Current Electricity I-64794.png

  • Physics-Current Electricity I-64795.png
The current passing through the ideal ammeter in the circuit given below is
Physics-Current Electricity I-64797.png
  • 1.25 A
  • 1 A
  • 0.75 A
  • 0.5 A
For the post office box arrangement to determine the value of unknown resistance, the unknown resistance should be connected between
Physics-Current Electricity I-64799.png
  • B and C
  • C and D
  • A and D
  • B1 and C1
In the circuit, the galvanometer G shows zero deflection. If the batteries A and B have negligible internal resistance, the value of the resistor R will be
Physics-Current Electricity I-64800.png
  • 200Ω
  • 100Ω
  • 500Ω
  • 1000Ω
In a meter bridge experiment, the ratio of the left gap resistance to right gap resistance is 2 : 3, the balance point from left is
  • 60 cm
  • 50 cm
  • 40 cm
  • 20 cm
When a metal conductor connected to the left gap of a meter bridge is heated, the balancing point
  • shifts towards right
  • shifts towards left
  • remains unchanged
  • remains at zero
The maximum current that can be measured by a galvanometer of resistance 40 Ω is 10 mA. It is converted into a voltmeter that can read upto 50 V. The resistance to be connected in series with the galvanometer (in ohm) is
  • 2010
  • 4050
  • 5040
  • 4960
An unknown resistance R1 is connected in series with a resistance of 10 Ω. This combination is connected to one gap of meter bridge while a resistance R2 is connected in the other gap. The balance point is at 50 cm. Now, when the 10 Ω resistance is removed the balance point shifts to 40 cm. The value of R1 (in ohm) is
  • 20
  • 10
  • 60
  • 40
In the given circuit, the voltmeter records 5 V. The resistance of the voltmeter in ohm is
Physics-Current Electricity I-64805.png
  • 200
  • 100
  • 10
  • 50
0:0:1


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