Explanation
The bulbs are in series, hence they will have the same current through them.
An ideal cell has zero resistance.
When the heating coil is cut into two equal parts and these parts are joined in parallel, the resistance of coil is reduced to one fourth, so power consumed will become 4 times i.e., 400 Js–1
The resistance of 40 W bulb will be more and 60 W bulb will be less.
current capacity of a fuse wire should be slightly greater than the total rated load current.
Watt-hour metre measures electric energy.
As temperature increases resistance of filament also increases.
For maximum joule heat produced in resistor external resistance = Internal resistance
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