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JEE Questions for Physics Dual Nature Of Radiation And Matter Quiz 1 - MCQExams.com
JEE
Physics
Dual Nature Of Radiation And Matter
Quiz 1
Photoelectric effect was first successfully explained by
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Planck
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Hallwach
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Hertz
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Einstein
An X-ray has a wavelength of 0.010 Å. Its momentum is
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2.126 × 10–23 kg-m/s
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6.626 × 10–22 kg-m/s
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3.456 × 10–25 kg-m/s
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3.313 × 10–22 kg-m/s
The shortest wavelength of X-rays emitted from an X-ray tube depends on the
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Current in the tube
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Voltage applied to the tube
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Nature of gas in the tube
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Atomic number of target material
Momentum of a photon of wavelength λ is
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h/λ
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2)
0%
0%
zero
The wavelength of X-rays is of the order of
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Centimetre
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Micron (10–6m)
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Angstrom (10–10m)
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Metre
Cathode rays enter a magnetic field making oblique angle with the lines of magnetic induction. What will be the nature of the path followed?
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Parabola
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Helix
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Circle
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Straight line
The linear momentum of an electron, initially at rest, accelerated through a potential difference of 100 V is
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9.1 × 10-24
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6.5 × 10-24
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5.4 × 10-24
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1.6 × 10-24
The resistance of a discharge tube is
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zero
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ohmic
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non-ohmic
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infinity
What is the de-Broglie wavelength of the electron accelerated through a potential difference of 100 V?
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12.27 Å
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1.227 Å
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0.1227 Å
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0.001227 Å
Find the de-Broglie wavelength for a 100 g bullet moving at 900 ms
-1
.
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7.4 ×10 -36 m
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7.8 ×10 -37 m
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8.2 ×10 -39 m
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3.7 ×10 -35 m
λ of a particle is 2000 Å and KE is 1 eV. If its KE is 1 MeV then, its λ is
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3 Å
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200 Å
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2 Å
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20 Å
An electron of mass
m
e
and a proton of mass
m
p
are moving with the same speed. The ratio of their de-Broglie wavelength λ
e
/ λ
p
is
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918
0%
1/1836
0%
1836
0%
1
Nuclear radii may be measured by scattering high energy electrons from nuclei. What is the de-Broglie wavelength for 200 MeV electrons ?
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8.28 Fm
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7.98 Fm
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6.45 Fm
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6.20 Fm
The de-Broglie wavelength of an electron in the ground state of the hydrogen atom is
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π r2
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2πr
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πr
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The de-Broglie wavelength of a ball of mass 120 g, moving at a speed of 20 m/s is
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3.5 × 10 -34 m
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2.8 × 10 -34 m
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1.2 × 10 -34 m
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2.1 × 10 -34 m
What is the de-Broglie wavelength of electron having energy 10 ke V ?
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0.12 Å
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1.2 Å
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12.2 Å
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None of these
For the Bohr's second orbit of circumference 2πr, the de-Broglie wavelength of revolving electron will be
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2πr
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πr
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1 / 2πr
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1 / 4πr
In Davisson-Germer experiment, maximum intensity is observed at
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50° and 54 V
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54° and 50 V
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50° and 50 V
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65° and 50 V
A photon and an electron have equal energy
E
.
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0%
2)
0%
1 / E
0%
Does not depend upon E
JJ Thomson's experimentally confirmed the existence of matter waves by the phenomenon
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diffraction
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refraction
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polarisation
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scattering
The kinetic energy of an electron gets tripled, then the de-Broglie wavelength associated with it changes by a factor
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0%
2)
0%
0%
3
If an electron and a proton have the same de-Broglie wavelength, then the kinetic energy of the electron is
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zero
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less than that of a proton
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more than that of a proton
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equal to that of a proton
Which of the following is not the property of the photons?
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Momentum
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Energy
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Charge
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Velocity
The de-Broglie wavelength associated with a particle moving with momentum (
p
) and mass (
m
) is
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0%
0%
2)
0%
0%
Photon of frequency
v
has a momentum associated with it. If
c
is the velocity of light., the momentum is
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v / c
0%
h v c
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h v / c2
0%
h v / c
The momentum of a photon of energy 1 MeV in kg -ms
-1
, will be
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0.33 × 106
0%
7 × 10-24
0%
10-22
0%
5 × 10-22
The ratio of the de-Broglie wavelength of an α-particle and a proton of same kinetic energy is
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1 : 2
0%
1 : 1
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1 : √2
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4 : 1
An electron is accelerated through a potential difference of
V
volt The speed of electrons will be
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0%
0%
2)
0%
0%
If α, β and γ rays carry same momentum, which has the longest wavelength ?
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α–rays
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β–rays
0%
γ–rays
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None, all have same wavelength
If the kinetic energy of a free electron doubles, its de-Broglie wavelength changes by the factor
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0%
0%
2
0%
0%
The de-Broglie wavelength of an electron is the same as that of a 50 keV X-ray photon. The ratio of the energy of the photon to the kinetic energy of the electron is (the energy equivalent of electron mass is 0.5 MeV)
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1 : 50
0%
1 : 2
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20 : 1
0%
50 : 1
If a source of power 4 kW produces 10
20
photon/sec the radiation belong to a part of the spectrum called
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X–rays
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ultraviolet rays
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microwaves
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γ–rays
The energy of an X–ray photon of wavelength 1 Å is (
h
= 6.6 × 10
-34
J-s)
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24.6 keV
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6.1 keV
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12.3 keV
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1.2 keV
Which of the following supports the wave nature of X-rays?
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Photoelectric effect
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Photosynthesis
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Compton scattering
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Diffraction
The potential difference applied to an X-ray tube is 5 kV, and the current through it is 3.2 mA. The number of electrons striking the target per sec is (take, e =1.6 × 10
-19
C)
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1.6 × 106
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2 × 10-6
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4 × 1016
0%
2 × 1016
X-rays are diffracted from a crystal of lattice plane spacing 2Å. The maximum wavelength that can be diffracted is
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1 Å
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2 Å
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2.5 Å
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4 Å
X-rays of wavelength λ = 2 Å is emitted from the metal target. The potential difference applied across the cathode and the metal target is
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5525 V
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320 V
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6200 V
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3250 V
The maximum kinetic energy of the photoelectrons depends only on
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potential
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frequency
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incident angle
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pressure
Find the maximum wavelength of the light that will excite an electron in the valence band of diamond to the conduction band. The energy gap is 5.5 eV.
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225 nm
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315 nm
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352 nm
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412 nm
Which of the following device is the application of photoelectric effect ?
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Light emitting diode
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Diode
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Photocell
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Transistor
What should be the velocity of an electron so that, its momentum becomes equal to that of a photon of wavelength 5200 Å ?
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700 m/s
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1000 m/s
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1400 m/s
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2800 m/s
The work function for aluminium is 4.125 eV. The cut-off wavelength for photoelectric effect for aluminium will be
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420 nm
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350 nm
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300 nm
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200 nm
Calculate the linear momentum of a 3 MeV photon
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0.01 eV–s/m
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0.02 eV–s/m
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0.03 eV–s/m
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0.0 eV–s/m
The photoelectric effect represents that
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light has a particle nature
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electron has a wave nature
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proton has a wave nature
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None of the above
The linear momentum of photon is
p
. The wavelength of photon is λ , then (
h
is Planck's constant)
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λ = hp
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2)
0%
0%
Which of the following event, support the quantum nature of light ?
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Diffraction
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Polarisation
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Interference
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Photoelectric effect
The photons in a radiowave of wavelength 3 × 10
4
cm have energy
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6.62 × 10-10 J
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19.86 × 10-24 J
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6.62 × 10-28 J
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2.2 × 10-35 J
The average energy of the Planck oscillator is
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hv
0%
2)
0%
0%
kT
In photoelectric effect, if the intensity of light is doubled, then maximum kinetic energy of photoelectrons will become
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double
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half
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four times
0%
no change
The maximum kinetic energy of emitted electrons in a photoelectric effect does not depend upon
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wavelength
0%
frequency
0%
intensity
0%
work function
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