JEE Questions for Physics Electrostatics I Quiz 13 - MCQExams.com

A capacitor is used to store 24 watt hour of energy at 1200 volt. What should be the capacitance of the capacitance of the capacitor
  • 120 mF
  • 120 µF
  • 24 µF
  • 24 mF
The mean electric energy density between the plates of a charged capacitor is (here q = charge on the capacitor and A = area of the capacitor plate)

  • Physics-Electrostatics I-71324.png
  • 2)
    Physics-Electrostatics I-71325.png

  • Physics-Electrostatics I-71326.png
  • None of these
Work done by an external agent is separating the parallel plate capacitor is
  • CV
  • 2)
    Physics-Electrostatics I-71328.png

  • Physics-Electrostatics I-71329.png
  • None of these
A parallel plate capacitor has an electric field of 105 V/m between the plates. If the charge on the capacitor plate 1 µC, the force on each capacitor plate is
  • 0.5 N
  • 0.05 N
  • 0.005 N
  • None of these
A parallel capacitor has plate area A and separation d. It is charged to a potential difference V0. The charging battery is disconnected and the plates are pulled apart to three times the initial separation. The work required to separate the plates is

  • Physics-Electrostatics I-71331.png
  • 2)
    Physics-Electrostatics I-71332.png

  • Physics-Electrostatics I-71333.png

  • Physics-Electrostatics I-71334.png
A thin metal plate P is inserted half way between the plates of a parallel plate capacitor of capacitance C in such a way that it is parallel to the two plates. The capacitance now becomes
  • C
  • C/2
  • 4C
  • None of these
If there are n capacitors in parallel connected to V volt source, then the energy stored is equal to
  • CV
  • 2)
    Physics-Electrostatics I-71336.png

  • Physics-Electrostatics I-71337.png

  • Physics-Electrostatics I-71338.png
If n drops, each of capacitance C, coalesce to form a single big drop, then the ratio of the energy stored in the big drop to that in each small drop will be
  • n : 1
  • n1/3 : 1
  • n5/3 : 1
  • n2 : 1
64 small drops of mercury, each of radius r and charge q coalesce to form a big drop. The ratio of the surface density of charge of each small drop with that of the big drop is
  • 1 : 64
  • 64 : 1
  • 4 : 1
  • 1 : 4
Capacitance (in F) of a spherical conductor with radius 1 m is
  • 1.1 × 10–10
  • 10–6
  • 9 × 10–9
  • 10–3
A parallel plate air capacitor is charged and then isolated. When a dielectric material is inserted between the plates of the capacitor, then which of the following does not change
  • Electric field between the plates
  • Potential difference across the plates
  • Charge on the plates
  • Energy stored in the capacitor
Capacitance of a parallel plate capacitor becomes 4/3 times its original value if a dielectric slab of thickness t = d/2 is inserted between the plates (d is the separation between the plates). The dielectric constant of the slab is
  • 8
  • 4
  • 6
  • 2
An air filled parallel plate capacitor has capacity C. If distance between plates is doubled and it is immersed in a liquid then capacity becomes twice. Dielectric constant of the liquid is
  • 1
  • 2
  • 3
  • 4
A spherical drop of capacitance 1 µF is broken into eight drops of equal radius. Then, the capacitance of each small drop is ....

  • Physics-Electrostatics I-71345.png
  • 2)
    Physics-Electrostatics I-71346.png

  • Physics-Electrostatics I-71347.png

  • Physics-Electrostatics I-71348.png
The work done in placing a charge of 8 × 10–18 coulomb on a condenser of capacity 100 mF is
  • 32 × 10–32 J
  • 16 × 10–32 J
  • 3.1 × 10–26 J
  • 4 × 10–10 J
64 drops of mercury each charged each charged to a potential of 10V. They are combined to form one bigger drop. The potential of this drop will be (Assume all the drops to be spherical)
  • 160 V
  • 80 V
  • 10 V
  • 640 V
A spherical drop of mercury having a potential of 2.5V is obtained as a result of merging 125 droplets. The potential of constituent droplets would be
  • 1.0 V
  • 0.5 V
  • 0.2 V
  • 0.1 V
A capacitor is charged to 200 volt it has 0.1 coulomb charge. When it is discharged, energy will be
  • 1 J
  • 4 J
  • 10 J
  • 20 J
n identical droplets are charged to V volt each. If they coalesce to form a single drop, then its potential will be
  • n2/3 V
  • n1/3 V
  • nV
  • V/n
A capacitor is charged by a battery and the energy stored is U. The battery is now removed and the separation distance between the plates is doubled. The energy stored now is

  • Physics-Electrostatics I-71355.png
  • U
  • 2U
  • 4U
A 2 µF capacitor is charged as shown in figure. The percentage of its stored energy dissipated after the switch S is turned to position 2 is
Physics-Electrostatics I-71356.png
  • 0%
  • 20%
  • 75%
  • 80%
In the given circuit, a charge of + 80 µC is given to the upper plate of the 4µF capacitor. Then in the steady state, the charge on the upper plate of the 3 µF capacitor is
Physics-Electrostatics I-71358.png
  • + 32µC
  • +40µC
  • + 48µC
  • + 80µC
Two identical capacitors are joined in parallel, charged to a potential V and then separated and then connected in series i. e., the positive plate of one is connected to negative of the other
  • The charges on the free plates connected together are destroyed
  • The charges on the free plates are enhanced
  • The energy stored in the system increases
  • The potential difference in the free plates becomes 2V
Seven capacitors each of capacity 2µF are to be so connected to have equivalent capacity 10/11 μF. Which will be the necessary figure as shown?

  • Physics-Electrostatics I-71361.png
  • 2)
    Physics-Electrostatics I-71362.png

  • Physics-Electrostatics I-71363.png

  • Physics-Electrostatics I-71364.png
Four plates of equal area A are separated by equal distances d and are arranged as shown in the figure. The equivalent capacity is
Physics-Electrostatics I-71365.png

  • Physics-Electrostatics I-71366.png
  • 2)
    Physics-Electrostatics I-71367.png

  • Physics-Electrostatics I-71368.png

  • Physics-Electrostatics I-71369.png
n identical condensers are joined in parallel and are charged to potential V. Now they are separated and joined in series. Then the total energy and potential difference of the combination will be
  • Energy and potential difference remain same
  • Energy remains same and potential difference is nV
  • Energy increases n times and potential difference is nV
  • Energy increases n times and potential difference remains same
Four capacitors of equal capacitance have an equivalent capacitance C1 when connected in series and an equivalent capacitance C2 when connected in parallel. The ratio C1/C2 is
  • 1/4
  • 1/16
  • 1/8
  • 1/12
The equivalent capacitance of the combination shown in figure below is
Physics-Electrostatics I-71373.png
  • 2C
  • C
  • 1/2 C
  • None of these
The charge deposited on 4µF capacitor in the circuit is
  • 6 × 10–6 C
  • 12 × 10–6 C
  • 24 × 10–6 c
  • 36 × 10–6 C
In given circuit when switch S has been close then charge on capacitor A & B respectively
Physics-Electrostatics I-71376.png
  • 3 q, 6q
  • 6 q, 3q
  • 4.5 q, 4.5 q
  • 5 q, 4 q
Plates of area A are arranged as shown. The distance between each plate is d, the net capacitance is
Physics-Electrostatics I-71378.png

  • Physics-Electrostatics I-71379.png
  • 2)
    Physics-Electrostatics I-71380.png

  • Physics-Electrostatics I-71381.png

  • Physics-Electrostatics I-71382.png
Two capacitors connected in parallel having the capacities C1 and C2 are given \'q\' charge, which is distributed among them. The ratio of the charge on C1 and C2 will be

  • Physics-Electrostatics I-71383.png
  • 2)
    Physics-Electrostatics I-71384.png

  • Physics-Electrostatics I-71385.png

  • Physics-Electrostatics I-71386.png
Two capacitors of capacities C1 and C2 are charged to voltages V1 and V2 respectively. There will be no exchange of energy in connecting them in parallel, if
  • C1 = C2
  • C1V1 = C2V2
  • V1 = V2

  • Physics-Electrostatics I-71388.png
A capacitor of capacity C1 is charged to the potential of V0. On disconnecting with the battery, it is connected with a capacitor of capacity C2 as shown in the adjoining figure. The ratio of energies before and after the connection of switch S will be
Physics-Electrostatics I-71389.png
  • (C1 + C/ C1
  • C1 / (C1 + C2)
  • C1C2
  • C1 / C2
Four capacitors of each of capacity 3 µF are connected as shown in the adjoining figure. The ratio of equivalent capacitance between A and B and between A and C will be
Physics-Electrostatics I-71391.png
  • 4 : 3
  • 3 : 4
  • 2 : 3
  • 3 : 2
The surface charge density (in C /m2) of the earth is about
  • 10–9
  • –109
  • 109
  • –10–9
Three equal capacitors, each with capacitance C are connected as shown in figure. Then the equivalent capacitance between A and B is
Physics-Electrostatics I-71393.png
  • C
  • 3C

  • Physics-Electrostatics I-71394.png

  • Physics-Electrostatics I-71395.png
In the adjoining figure, four capacitors are shown with their respective capacities and the P.D. applied. The charge and the P.D. across the 4 0 capacitor will be
Physics-Electrostatics I-71397.png
  • 600 µC ; 150 volts
  • 300 µC ; 75 volts
  • 800 µC ; 200 volts
  • 580 µC ;145 volts
A 4µF condenser is connected in parallel to another condenser of 8µF. Both the condensers are then connected in series with a 12µF condenser and charged to 20 volts. The charge on the plate of 4µF condenser is
  • 3.3 µC
  • 40 µC
  • 80 µC
  • 240 µC
A capacitor having capacitance C is charged to a voltage V. It is then removed and connected in parallel with another identical capacitor which is uncharged. The new charge on each capacitor is now
  • CV
  • CV/2
  • 2CV
  • CV/4
Four capacitors are connected in a circuit as shown in the following figure. Calculate the effective capacitance between the points A and B
Physics-Electrostatics I-71400.png

  • Physics-Electrostatics I-71401.png
  • 2)
    Physics-Electrostatics I-71402.png

  • Physics-Electrostatics I-71403.png

  • Physics-Electrostatics I-71404.png
Effective capacitance between A and B in the figure shown is (all capacitance are in µF)
Physics-Electrostatics I-71406.png

  • Physics-Electrostatics I-71407.png
  • 2)
    Physics-Electrostatics I-71408.png

  • Physics-Electrostatics I-71409.png

  • Physics-Electrostatics I-71410.png
The resultant capacitance between A and B in the following figure is equal to
Physics-Electrostatics I-71412.png
  • 1 µF
  • 3 µF
  • 2 µF
  • 1.5 µF
In the following circuit, the resultant capacitance between A and B is 1 µF. Then the value of C is
Physics-Electrostatics I-71414.png

  • Physics-Electrostatics I-71415.png
  • 2)
    Physics-Electrostatics I-71416.png

  • Physics-Electrostatics I-71417.png

  • Physics-Electrostatics I-71418.png
Two dielectric slabs of constant K1 and K2 have been filled in between the plates of a capacitor as shown below. What will be the capacitance of the capacitor?
Physics-Electrostatics I-71420.png

  • Physics-Electrostatics I-71421.png
  • 2)
    Physics-Electrostatics I-71422.png

  • Physics-Electrostatics I-71423.png

  • Physics-Electrostatics I-71424.png
What is the equivalent capacitance between A and B in the given figure (all are in Farad)?
Physics-Electrostatics I-71425.png

  • Physics-Electrostatics I-71426.png
  • 2)
    Physics-Electrostatics I-71427.png

  • Physics-Electrostatics I-71428.png

  • Physics-Electrostatics I-71429.png
A condenser having a capacity of 6 µF is charged to 100 V and is then joined to an uncharged condenser of 14 µF and then removed. The ratio of the charges on 6 µF and 14 µF and the potential of 6 µF will be

  • Physics-Electrostatics I-71431.png
  • 2)
    Physics-Electrostatics I-71432.png

  • Physics-Electrostatics I-71433.png

  • Physics-Electrostatics I-71434.png
0.2 F capacitor is charged to 600 V by a battery. On removing the battery, it is connected with another parallel condenser of 1 F. the potential decreases to
  • 100 volts
  • 120 volts
  • 300 volts
  • 600 volts
Minimum number of capacitors of 2 µF capacitance each required to obtain of 5 µF will be
  • Three
  • Four
  • Five
  • Six
The total energy stored in the condenser system shown in the figure will be
Physics-Electrostatics I-71438.png
  • 8 µJ
  • 16 µJ
  • 2 µJ
  • 4 µJ
0:0:1


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