Explanation
As all points on the circular path are at same potential, so work done is zero.
In an electric field positive charge particle will move in the direction of electric field while negative charge will move in the direction opposite to the magnetic field.
Electric field done negative work on the proton moves against the direction of electric field. So, proton is moving in electric field from low potential to high potential. Hence its potential energy increases.
Measured value of E = F / q0, which is the resultant of fields of q and q0.
∴ Actual value of E due to source charge must be greater than F / q0.
When negative terminal is grounded, positive terminal of battery is at + 12 V. When positive terminal is grounded, the negative terminal will be at – 12 V.
Potential at the centre of the sphere = potential on the surface = 80 V
According to option (d), electric fields at O due to P and S will cancel. Again electric fields at O due to Q and T will cancel. Electric fields at O due to U and R will add up to give double the electric field.
On connecting O at A, 4 μF capacitor is charged to a constant potential (E). As connection of O is switched over to B, the total charge on 4μF capacitor is shared between 4μF and 2μF capacitor in the ratio 4 : 2. Charge left on 4μ capacitor is (4/(4+2) = 2/3) of original charge
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