Explanation
There will be electrostatic repulsion between two charged bobs, but it does not affect the motion of pendulum. Time period of pendulum remains same.
Fields cannot be zero if charges are of opposite signs, then the two fields are along the same direction.
So, option (3) is correct.
Now, charge in potential energy is equal to work done by external force.
∴WA→B = q(∆V) = (+)(VB – VA) = (VB – VA)
So, option (4) is also correct.
∴Correct options are (3) and (4).
According to Gauss’s theorem, there will be an electric field between two cylinders. This electric fields will produce a potential difference.
The electric field intensity of a point in an electric field in a given direction is equal to the negative potential gradient in that direction i.e.,
ϵ = -dv/dx
The negative sign signifies that the potential decreases in the direction of electric field. I.e., electric lines of force flow from higher potential region to lower potential region. So, AB is perpendicular to field lines, so, A and B are at same potential.
Hence VA = VB > VC
On addition of -4µC charge to each, q1'= 4 – 4 = 0 and q2 '= + 2 – 4 = -2µC As F’ ∝ q1' q 2' , therefore, force becomes zero.
The force of q1 or q2 is not affected by q3. However, resultant force on q2 will be affected
Effective distance between the two charges
E = σ/∈0
E/ϵ0 , the value of E does not depend upon radius of the sphere
A positive charge, when free, shall move from higher (+) potential to lower (-) potential. Therefore, it must cross the circle S at some time
In series, charge on each condenser is same ∴qb= qd = qf,all these plates carry equal positive charges
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