JEE Questions for Physics Electrostatics Ii Quiz 3 - MCQExams.com

Two capacitors C1 and C2 are charged to 120 V and 200 V, respectively. It is found that by connecting them together the potential on each one can be made zero. Then,
  • 5 C1 = 3 C2
  • 3 C1 = 5 C2
  • 3 C1 ± 5 C2 = 0
  • 9 C1 = 4 C2
Two capacitors of capacitance C are connected in series. If one of them is filled with dielectric substance K, what is the effective capacitance?

  • Physics-Electrostatics II-73101.png
  • C (K + 1)

  • Physics-Electrostatics II-73102.png
  • None of these
In the given circuit, a charge of + 80 µC is given to the upper plate of the 4 µF capacitor. Then, in the steady state, the charge on the upper plate of the 3 µF capacitor is
Physics-Electrostatics II-73104.png
  • + 32 µC
  • + 48 µC
  • + 40 µC
  • + 80 µC
An electric circuit requires a total capacitance of 2 µF across a potential of 1000 V. Large number of 1µF capacitances are available, each of which would breakdown, if the potential is more than 350 V. How many capacitances are required to make the circuit?
  • 24
  • 20
  • 18
  • 12
Two identical parallel plate capacitors are placed in series and connected to a constant voltage source of V volt. If one of the capacitor is completely immersed in a liquid of dielectric constant K, then the potential difference between the plates of the other capacitor will change to

  • Physics-Electrostatics II-73107.png
  • 2)
    Physics-Electrostatics II-73108.png

  • Physics-Electrostatics II-73109.png

  • Physics-Electrostatics II-73110.png
Across each of two capacitors of capacitances 1µF and 4 µF, a potential difference of 10 V is applied. Then, positive plate of one is connected to the negative plate of the other and negative plate of one is connected to the positive plate of the other. After contact,
  • charge on each is zero
  • charge on each is same but non-zero
  • charge on each is different but non-zero
  • None of the above
Two capacitors of capacity 6µF and 12µF in series are connected by potential of 150 V. The potential of capacitor of capacity 12µF will be
  • 25 V
  • 50 V
  • 100 V
  • 150 V
The energy of a charged capacitor is U. Another identical capacitor is connected parallel to the first capacitor, after disconnecting the battery. The total energy of the system of these capacitors will be

  • Physics-Electrostatics II-73113.png
  • 2)
    Physics-Electrostatics II-73114.png

  • Physics-Electrostatics II-73115.png

  • Physics-Electrostatics II-73116.png
A 10 µF capacitor and a 20 µF capacitor are connected in series across a 200 V supply line. The charged capacitors are then disconnected from the line and reconnected with their positive plates together and negative plates together and no external voltage is applied. The potential difference across each capacitor is

  • Physics-Electrostatics II-73118.png
  • 2)
    Physics-Electrostatics II-73119.png
  • 400 V
  • 200 V
Three capacitors of capacitance C (µF) are connected in parallel to which a capacitor of capacitance C is connected in series. Effective capacitance is 3.75, then capacity of each capacitor is
  • 4 µF
  • 5 µF
  • 6 µF
  • 8 µF
The charge deposited on 4µF capacitor, the circuit is
Physics-Electrostatics II-73122.png
  • 6 × 10-6 C
  • 12 × 10-6 C
  • 24 × 10-6 C
  • 36 × 10-6 C
The equivalent capacitance between points A and B for the combination of capacitors shown in figure, where all capacitances are in microfarad is
Physics-Electrostatics II-73124.png
  • 6.0 µF
  • 4.0 µF
  • 2.0 µF
  • 3.0 µF
Equivalent capacitance between A and B is
Physics-Electrostatics II-73126.png
  • 14µF
  • 4µF
  • 6µF
  • 2µF
The effective capacitance between points A and B is
Physics-Electrostatics II-73128.png
  • 9µF
  • 3µF
  • 6µF
  • 1µF
Two parallel plate capacitors of capacitances C and 2C are connected in parallel and charged to a potential difference V0 . The battery is then disconnected and the region between the plates of the capacitor C is completely filled with a material of dielectric constant 2. The potential difference across the capacitors now becomes

  • Physics-Electrostatics II-73130.png
  • 2)
    Physics-Electrostatics II-73131.png

  • Physics-Electrostatics II-73132.png
  • V0
Two capacitors of capacitance 2 µF and 4 uF respectively are connected in series. The combination is connected across a potential difference of 10 V. The ratio of energies stored by capacitors will be
  • 1 : √2
  • 2 : 1
  • 1 : 4
  • 4 : 1

Physics-Electrostatics II-73135.png
  • 1.8 pF
  • 45 pF
  • 40.5 pF
  • 20.25 pF
In given circuit when switch S has been closed, then charge on capacitor A and B respectively are
Physics-Electrostatics II-73137.png
  • 3 q, 6 q
  • 6 q, 3 q
  • 4.5 q, 45q
  • 5q, 4q
The total energy stored in the condenser system shown in the figure will be
Physics-Electrostatics II-73139.png
  • 2 µJ
  • 4 µJ
  • 8 µJ
  • 16 µJ
Four plates of equal area A are separated by equal distance d and are arranged as shown in the figure. The equivalent capacity is

  • Physics-Electrostatics II-73141.png
  • 2)
    Physics-Electrostatics II-73142.png

  • Physics-Electrostatics II-73143.png

  • Physics-Electrostatics II-73144.png
Two parallel plates of area A are separated by two different dielectric as shown in figure. The net capacitance is

  • Physics-Electrostatics II-73146.png
  • 2)
    Physics-Electrostatics II-73147.png

  • Physics-Electrostatics II-73148.png

  • Physics-Electrostatics II-73149.png
Four capacitors are connected in a circuit as shown in the following figure. Calculate the effective capacitance between the points A and B.
Physics-Electrostatics II-73151.png

  • Physics-Electrostatics II-73152.png
  • 2)
    Physics-Electrostatics II-73153.png

  • Physics-Electrostatics II-73154.png

  • Physics-Electrostatics II-73155.png

Physics-Electrostatics II-73352.png

  • Physics-Electrostatics II-73353.png
  • 2)
    Physics-Electrostatics II-73354.png

  • Physics-Electrostatics II-73355.png

  • Physics-Electrostatics II-73356.png
A parallel plate capacitor with air as the dielectric has capacitance C. A slab of dielectric constant K and having the same thickness as the separation between the plates is introduced so as to fill one-fourth of the capacitor as shown in the figure. The new capacitance will be
Physics-Electrostatics II-73157.png

  • Physics-Electrostatics II-73158.png
  • 2)
    Physics-Electrostatics II-73159.png

  • Physics-Electrostatics II-73160.png

  • Physics-Electrostatics II-73161.png

Physics-Electrostatics II-73163.png

  • Physics-Electrostatics II-73164.png
  • 2)
    Physics-Electrostatics II-73165.png

  • Physics-Electrostatics II-73166.png

  • Physics-Electrostatics II-73167.png
What is the potential difference between points A and B in the circuit shown?
Physics-Electrostatics II-73169.png
  • 2 V
  • 4 V
  • 3 V
  • 12 V
Three capacitors of capacitances 1µF, 2 µF and 4µF are connected first in a series combination and then in a parallel combination. The ratio of their equivalent capacitances will be
  • 2 : 49
  • 49 : 2
  • 4 : 49
  • 49 : 4
The equivalent capacitance of the combination of the capacitors is
Physics-Electrostatics II-73172.png
  • 3.20 µF
  • 7.80 µF
  • 3.90 µF
  • 2.16 µF
Each capacitor shown in figure is 2 µF. Then, the equivalent capacitance between points A and B is
Physics-Electrostatics II-73174.png
  • 2 µF
  • 4 µF
  • 6 µF
  • 8 µF
Two plates are 20 cm apart and the potential difference between them is 10V. The electric field between the plates is
  • 50 Vm-1
  • 500 Vm-1
  • 0.5 Vm-1
  • 20 Vm-1
0:0:1


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