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JEE Questions for Physics Kinetic Theory Of Gases Quiz 14 - MCQExams.com
JEE
Physics
Kinetic Theory Of Gases
Quiz 14
At what temperature the molecules of nitrogen will have the same rms. velocity as the molecules of Oxygen at 127
o
C.
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0%
273o C
0%
350o C
0%
77o C
0%
457o C
The temperature of an ideal gas is increased from 27
o
C to 127
o
C, then percentage increase in
v
rms
is
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0%
33%
0%
11%
0%
15.5%
0%
37%
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0%
2
0%
4
0%
0.5
0%
1
At which temperature the velocity of O
2
molecules will be equal to the rms velocity of N
2
molecules at 0
o
C
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0%
93o C
0%
40o C
0%
39o C
0%
can not be calculated.
At what temperature, pressure remaining unchanged, will the rms velocity of a gas be half its value at O
o
C ?
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0%
204.75 K
0%
204.75o C
0%
–204.75 K
0%
–204.75o C
The rms velocity of gas molecules is 300 ms
–1
. The rms velocity of molecules of gas with twice the molecular weight and half the absolute temperature is
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0%
300 ms–1
0%
150 ms–1
0%
600 ms–1
0%
75 ms–1
Calculate the temperature at which rms velocity of SO
2
molecules is the same as that of O
2
molecules at 27
o
C. Molecular weights of Oxygen and SO
2
are 32 g and 64 g respectively
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0%
327o C
0%
327 K
0%
127o C
0%
227o C
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0%
0.45
0%
2.24
0%
3.16
0%
0.32
When the temperature of a gas is raised from 27
o
C to 90
o
C , the percentage increase in the rms velocity of the molecules will be
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0%
15%
0%
17.5%
0%
10%
0%
20%
The temperature at which the rms speed of hydrogen molecules is equal to escape velocity on earth surface will be
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0%
5030 K
0%
10063 K
0%
1060 K
0%
8270 K
What is the mean free path and collision frequency of a nitrogen molecule in a cylinder containing nitrogen at 2 atm and temperature 17
o
C? Take the radius of nitrogen molecule to be 1 Å. Molecular mass of nitrogen = 28, k
B
= 1.38 × 10
–23
JK
–1
, 1 atm = 1.013 × 10
5
Nm
–2
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0%
0%
2)
0%
0%
The radius of a molecule of Argon gas is 1.78 Å . Find the mean free path of molecules of Argon at 0
o
C temperature and 1 atm pressure. k
B
= 1.38 × 10
–23
JK
–1
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0%
0%
2)
0%
0%
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0%
0%
2)
0%
0%
For a gas if ratio of specific heats at constant pressure and volume is γ, then value of degrees of freedom is
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0%
0%
2)
0%
0%
From the following P – T graph, what inference can be drawn
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0%
V2 < V1
0%
V2 = V1
0%
V2 > V1
0%
none of these
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