Explanation
As the spring balances are massless therefore the reading of both balance should be equal.
Due to acceleration in forward direction, vessel is in an accelerated frame therefore a Pseudo force will be exerted in backward direction. Therefore water will be displaced in backward direction.
The pressure on the rear side would be more due to fictitious force (acting in the opposite direction of acceleration) on the rear face. Consequently the pressure in the front side would be lowered.
Mass measured by physical balance remains unaffected due to variation in acceleration due to gravity.
For W, 2W, 3W apparent weight will be zero because the system is falling freely. So, the distances of the weight from the rod will be same.
Heavier gas will acquire largest momentum i. e. , Argon.
The wings of the aeroplane pushes the external air backward and the aeroplane move forward by reaction of pushed air. At low altitudes density of air is high and so the aeroplane gets sufficient force to move forward.
Momentum acquired by the particle is numerically equal to area enclosed between the F – t curve and Lime axis. For the given diagram area in upper half is positive and in lower half is negative (and equal to upper half), so net area is zero. Hence, the momentum acquired by the particle will be zero.
In region AB and CD, slope of the graph is constant i..e., velocity is constant. It means no force acting on the particle in this region.
Impulse = Area between force and time graph and it is maximum for graph (Ill) and (1V).
Slope of surface should change from one constant value (non zero) to another constant value (non zero) in terms of sign because force is constant piecewise.
Gravitational field is a conservative field. Therefore work done in moving a particle from A to B is independent of path chosen.
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