Explanation
Three liquids of equal masses are taken in three identical cubical vessel, A.B.C.
∴ mA = mB = mC.
Force exerted by the liquid on the base of the vessel is F = mg
∴ FA = FB = FC
∴ The same I all the vessel.
Breaking stress = Strain × young's modulus.
F = Y × A × Strain.
Breaking force ∝ r2
If diameter becomes double then breaking force will become four times
i.e. 1000 × 4 = 4000.
Because dimension of invar does not vary with temperature.
Thermal stress = YαΔQ.
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