Explanation
For particle P. motion between A and C will be an accelerated one while between C and B a retarded one. But in any case horizontal component of it’s velocity will be greater than or equal to u on the other hand in case of particle Q, it is always to v, horizontal displacement of both the particles are equal, so tP < tQ .
There is no loss of energy. Therefore, the final velocity is the same as the initial velocity.
If air resistance is taken into consideration then range and maximum height, both will decrease.
At time t1 the velocity of ball will be maximum and it goes on decreasing with respect to time.
At the highest point of path its velocity becomes zero, then it increases but direction is reversed.
This explanation matches with graph (c).
In the given condition, the particle undergoes uniform circular motion and for uniform circular motion the velocity and acceleration vector changes continuously but kinetic energy is constant for every point.
At the highest point, vertical component of velocity becomes zero so there will be only horizontal velocity and it is perpendicular to the acceleration due to gravity.
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