Explanation
Here W = T cos θ and P = T sin θ
So P + W = T (cos θ + sin θ) < T
Where as (a), (b) and (c) are correct and (d) is wrong.
There will be no change in momentum parallel to the wall.
Both the spheres strike the ground at the same time, because horizontal velocity does not affect the vertical motion
Here bead Q moves with a constant velocity. The particle P executes S.H.M. Its velocity increases till it reaches at the bottom and then decreases. So the time taken by particle is less than by the bead i.e tP < tQ
A particle performing a uniform circular motion has a transverse velocity and radial acceleration
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