Explanation
Neutrons does not have any charge, so tehse are not deflected by magnetic field.
The magnetic force on a charged particle moving in the field does not work because the kinetic energy of the charged particle does not change.
Deutirium and Helium both are neutral. So neither of them will be accelerated.
Force between two parallel current carrying wire is independent of the radii of the wires.
Magnetic dipole moment = ampere turns × area of coil.
M = NIA
So magnetic dipole moment is independent of magnetic field in which it is lying.
F = idl × B
∵angle between al and B is zero
F = 0
By Fleming’s left hand rule, fore acting on the electron is towards east, so it will deflect towards east.
A st. wire carrying current produces circular magnetic lines of force.
An atomic neon is a neutral atom as its centre of positive charge coincides with the centre of negative charge. Hence it does not behave as an electric dipole.
There will be an electrostatic force of attraction between beam of protons and beam of electrons and there will be magnetic attraction due to currents by virtue of motion of protons and electrons in the same direction and magnetic repulsion due to currents by virtue of motion of protons and electrons in the opposite direction.
F = Bil = 2 × 1.2 × 1.0 = 2.4 N.
Bqv = mv2 / r or q/m = v / rB
As V = IR, so for the given current V ∝ R. i.e. for large value of V, R should be large.
Couple on the current carrying loop in a uniform magnetic field is, τ = i AB ; since for a given perimeter the area of circular loop S will be maximum so, the couple of force on S is maximum.
On applying, Right Hand Rule,we will find that at some points in the region I and IV, the resultant magnetic field induction will be zero.
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