Explanation
Magnetic field B will be uniform inside the hallow tube, excepts near the end. Magnetic field at any point outside the tube is zero.
Neither electron nor proton will go through the slit irrespective of their speed and electron will always be deflect upwards irrespective of their speed.
V1 and B will rotate the particle in a circular path in x–y plane. V11 and E will move the particle along positive y–axis. Therefore the reesultant path is helical with increasing pitch, along the y–axis. So option (3) is correct.
The two conductors are attracting each other. Hence current is flowing in parallel direction.
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