Explanation
Centre of mass is closer to massive part of the body therefore the bottom piece of bat has larger mass.
As initially both the particles were at rest therefore velocity, of centre of mass was zero and there is no external force on the system so speed of centre of mass remains constant te., it should be equal to zero.
In the absence of external force, position of centre of mass remain same therefore they will meet at their centre of mass.
v1 = r1 ω1 and v2 = r2 ω2
v. Net v will be horizontal, if v1 and v2 both are horizontal. Further v1 is already horizontal, because centre of mass is rotating about a verticle z–axis. To make v2 also be verticle.
v. Net v will be horizontal, if v1 and v2 both are horizontal. Further v1 is already horizontal, because centre of mass is rotating about a verticle z –axis. To make v2 also be verticle.
As no external torque acts on the system, the angular momentum L is conserved. As the beads slide down, the moment of inertia of the system shall change. As L = I ω = constant and I changes, therefore, ω would change. As no work is being done total energy cannot change. The correct choice is ‘b’.
The centre of mass remains at the centre of the ladder. Therefore, trace of cm shown in Fig. (a) is correct.
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