Explanation
Path difference, x = (SS1 + S1O) – (SS2 + S2O) If x = nλ, the central fringe at O will be bright. If x = (2n –1)λ/2, the central fringe at O will be dark.
When one slit is closed, amplitude becomes half and intensity becomes 1/4th i.e. I0 = 1/4 I or I = 4I0
Interference fringes are bands on screen XY running parallel to the lengths of slits. Therefore, the locus of fringes is represented correctly by w3 w4 .
When source is replaced, by another of shorter wavelength, direct image O remains unaffected but the diffracted images A, B, C will shift closer to O.
We see two images of dot. One image is stationary and other image rotates about it.
Ray optics is valid when characteristic dimensions are much larger than the wavelength of light.
To demonstrate interference, we need two coherent sources, which should emit light of the same frequency and having a definite phase relationship.
The position of central bright fringe will depend on angle θ thickness of palate, distance between the slits and refractive index of glass. It can be any where. For example, if d sin θ = (μ – 1)t the central bright fringe is at O. If d sin θ > (μ – 1)t, the central bright fringe lies above O, and if d sin θ < (μ – 1) t, the central bright fringe lies below O.
Corpuscular theory explains refraction of light.
According to Corpuscular theory different colours of light are due to different sizes of Corpuscules.
According to Plancks hypothesis, black bodies emit radiations in the form of photons.
The coherent source cannot be obtained from two different light sources.
The idea of secondary wavelets is given is Huygen.
Monochromatic wave means of single wavelength not the single colour.
Sound waves and light waves both show interference.
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